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\(3^2\left(x+4\right)-5^2=5\cdot2^2\\ 9\left(x+4\right)-25=20\\ 9\left(x+4\right)=20+25\\ 9\left(x+4\right)=45\\ x+4=45:9\\ x+4=5\\ x=5-4\\ x=1\)
a) 5.22 + (x + 3) = 52
5.4 + (x + 3) = 25
20 + (x + 3) = 25
x + 3 = 25 – 20
x + 3 = 5
x = 5 – 3 = 2
b) 23 + (x – 32) = 53 - 43
8 + (x – 9) = 125 – 64
8 + (x – 9) = 61
x – 9 = 61 – 8
x – 9 = 53
x = 53 + 9 = 62
a) \(5.2^2+\left(x+3\right)=5^2\)
\(x+3=5^2-5.2^2\)
\(x+3=25-20\)
\(x+3=5\)
\(x=2\)
b) \(2^3+\left(x-3^2\right)=5^3-4^3\)
\(8+\left(x-9\right)=125-64\)
\(x-9=53\)
\(x=62\)
= 5.4 + ( x+3) = 25
20 + (x+3) = 25
x + 3 = 25 - 20 =5
x = 5 - 3 =2
a, 2 3 x + 5 2 x = 2 5 2 + 2 3 - 33
8x+25x = 33
33x = 33
x = 1
b, 260 : x + 4 = 5 2 3 + 5 - 3 3 2 + 2 2
260:(x+4) = 5.13–3.13
x+4 = 260:26
x+4 = 10
x = 6
c, 720 : [ 41 - 2 x - 5 ] = 2 3 . 5
41–(2x–5) = 720:40
2x–5 = 41–18
2x = 28
x = 14
d, 3 2 - 2 x - 12 + 35 = 5 2 + 279 : 3 2
7(x–12)+35 = 56
7(x–12) = 21
x–12 = 3
x = 15
a)100:25+7.9=4+16=20
b)84:4+9+1=31
c)29-(16+3.1)=10
d)5.4+98:49=20+2=22
\(3^2\cdot\left(x+4\right)-5^2=5\cdot22\)
\(\Rightarrow9\cdot\left(x+4\right)-25=110\)
\(\Rightarrow9\cdot\left(x+4\right)=110+25\)
\(\Rightarrow9\cdot\left(x+4\right)=135\)
\(\Rightarrow x+4=\dfrac{135}{9}\)
\(\Rightarrow x+4=15\)
\(\Rightarrow x=15-4\)
\(\Rightarrow x=11\)
`#3107`
\(3^2\cdot\left(x+4\right)-5^2=5\cdot22\\ \Rightarrow3^2\left(x+4\right)=5\cdot22+5^2\\ \Rightarrow9\left(x+4\right)=110+25\\ \Rightarrow9\left(x+4\right)=135\\ \Rightarrow x+4=135\div9\\ \Rightarrow x+4=15\\ \Rightarrow x=15-4\\ \Rightarrow x=11\)
Vậy, `x = 11.`
a) 135 - ( x + 32 ) = 80
x + 32 = 135 - 80
x + 32 = 55
x = 55 - 32
x = 23
b)( x - 17 ) + 52 = 158
x - 17 = 158 - 52
x - 17 = 106
x = 106 + 17
x = 123
c x : 17 + 83 = 297
x : 17 = 297 - 83
x : 17 = 214
x = 214 x 17
x = 3638
d) 9052: x - 56 = 17
9052 : x = 17 + 56
9052 : x = 73
x = 9052 : 73
x = \(\frac{1004}{17}\)
32(x+4)-52=5.4
9(x+4)-25=20
9(x+4)=20+25
9(x+4)=45
x+4=45:9
x+4=5
x=5-4
x=1
vậy x=1