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a)
-2x+3=-7
-2x=-7-3
-2x=-10
x=-10:-2
x=5
b)(-3)x+1=-8
-3x=-8-1
-3x=-9
x=-9 :-3
x=3
c)[2x+1]=5 ( cái này à trị tuyệt đối đúng k ?) nếu dấu [ là dấu giá trị tuyệt đối
=>\(\orbr{\begin{cases}2x+1=5\\2x+1=-5\end{cases}}\)
=>\(\orbr{\begin{cases}2x=4\\2x=-6\end{cases}}\)
=>\(\orbr{\begin{cases}x=2\\x=-3\end{cases}}\)
vậy x \(\in\left\{2;-3\right\}\)
d)|2x-1|-3=18
|2x-1|=21
=> \(\orbr{\begin{cases}2x-1=21\\2x-1=-21\end{cases}}\)
=>\(\orbr{\begin{cases}2x=22\\2x=-20\end{cases}}\)
=>\(\orbr{\begin{cases}x=11\\x=-10\end{cases}}\)
vậy \(x\in\left\{11;-10\right\}\)
b)
\(3\left(2x^2-7\right)=33\)
\(\Leftrightarrow2x^2-7=11\)
\(\Leftrightarrow2x^2=18\)
\(\Leftrightarrow x^2=9\)
\(\Leftrightarrow x=\pm3\)
a) -2(2x - 8) + 3(4 - 2x) = -72 - 5(3x - 7)
=> -4x + 16 + 12 - 6x = -72 - 15x + 35
=> -10x + 28 = -37 - 15x
=> -10x + 15x = -37 - 28
=> 5x = -65
=> x = -65 : 5
=> x = -13
b) 3(2x2 - 7) = 33
=> 2x2 - 7 = 33 : 3
=> 2x2 - 7 = 11
=> 2x2 = 11 + 7
=> 2x2 = 18
=> x2 = 18 : 2
=> x2 = 9
=> \(\orbr{\begin{cases}x=3\\x=-3\end{cases}}\)
Vậy ...
\(12\left(x-3\right)=5\left(x-1\right)+4\)
\(\Rightarrow12x-36=5x-5+4\)
\(\Rightarrow12x-5x=-5+4+36\)
\(\Rightarrow7x=35\)
\(\Rightarrow x=5\)
\(-6\left(x-7\right)+2\left(x+10\right)=x-18\)
\(-6x+42+2x+20=x-18\)
\(-6x+2x-x=-18-20-42\)
\(-5x=-80\)
\(x=16\)
\(7\left(2x-1\right)-12\left(x-5\right)=3\)
\(\Rightarrow14x-7-12x+60=3\)
\(\Rightarrow14x-12x=3-60+7\)
\(\Rightarrow2x=-50\)
\(\Rightarrow x=-25\)
\(\left|2x-1\right|=17\)
\(\Leftrightarrow\orbr{\begin{cases}2x-1=17\\2x-1=-17\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=9\\x=-8\end{cases}}\)
\(\left|8-3x\right|=14\)
\(\Leftrightarrow\orbr{\begin{cases}8-3x=14\\8-3x=-14\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-2\\x=\frac{22}{3}\end{cases}}\)
Lời giải:
$(2x-3).6-7(3x-1)+6=6.2x$
$(12x-18)-(21x-7)+6=12x$
$-9x-5=12x$
$5=-9x-12x=-21x$
$x=\frac{5}{-21}$
a)2+4+6+8+...+2x=210
\(\frac{2x-2}{2}+1=210\)
\(\frac{2x-2}{2}=210-1\)
\(\frac{2x-2}{2}=209\)
\(2x-2=209.2\)
\(2x-2=418\)
\(2x=418+2\)
\(2x=420\)
\(x=\frac{420}{2}\)
\(x=210\)
Vậy...
câu b tương tự bn nha
tk mk nha bn
5(3x+8)-7(2x+3)=16
<=> 15x+40-14x-21=16
<=> x+19=16
<=> x=-3
Vậy x=-3
5.(3x+8)-7(2x+3)=16
15x+40-14x-21=16
15-14x=16-40+21
x=-3
Vậy x=-3
\(a,3\left(x-12\right)-2\left(2x-4\right)=3-2\left(x-11\right)\)
\(3x-36-4x+8=3-2x+22\)
\(3x-4x+2x=3+22+36-8\)
\(x=53\)
\(a,3\left(x-12\right)-2\left(2x-4\right)=3-2\left(x-11\right)\)
\(3x-36-4x+8=3-2x+22\)
\(3x-4x+2x=3+22+36-8\)
\(x=53\)
\(b,5\left(x-7\right)-4\left(x-8\right)=5-2\left(x-4\right)+2x\)
\(5x-35-4x+32=5-2x+8+2x\)
\(5x-4x+2x-2x=5+8+35-32\)
\(x=16\)
\(\Leftrightarrow\left(2x-3\right)^7\left(2x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{3}{2}\end{matrix}\right.\)