Question

[Nguyễn Hoàng Gia Huy]

tìm x, biết :
√1,96 + 3 x/4 = √0,04 + 1/4 . √256/25

Answer 1

[Nguyễn Lê Phước Thịnh]

ĐKXĐ: \(x>=-\dfrac{1.96}{3}=-\dfrac{196}{300}=\dfrac{-49}{75}\)

\(\sqrt{\dfrac{1.96+3x}{4}}=\sqrt{0,04}+\dfrac{1}{4}\cdot\sqrt{\dfrac{256}{25}}\)

=>\(\sqrt{\dfrac{3x+1.96}{4}}=0.2+\dfrac{1}{4}\cdot\dfrac{16}{5}=1\)

=>\(\dfrac{3x+1,96}{4}=1\)

=>3x+1,96=4

=>3x=2,04

=>\(x=\dfrac{2.04}{3}=0.68\left(nhận\right)\)