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\(\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{11}\) \(\frac{3}{5}.\frac{2}{8}+\frac{-6}{16}.\frac{2}{5}+\frac{-6}{15}:\left(-16\right)\)
\(=\frac{-5}{7}\left(\frac{2}{11}+\frac{9}{11}\right)\) \(=\frac{3}{20}+\frac{-3}{20}+\frac{1}{40}\)
\(=\frac{-5}{7}.1=\frac{-5}{7}\) \(=0+\frac{1}{40}=\frac{1}{40}\)
\(x-\frac{2}{5}=0,24\) \(\left(\frac{7}{3}x-0,6\right):3\frac{2}{5}=1\)
\(\Rightarrow x=0,24+\frac{2}{5}=\frac{16}{25}\) \(\Rightarrow\left(\frac{7}{3}x-0,6\right):\frac{17}{5}=1\)
vậy x = 16/25 \(\Rightarrow\frac{7}{3}x-0,6=\frac{17}{5}\)
\(\Rightarrow\frac{7}{3}x=\frac{17}{5}+0,6=4\)
\(\Rightarrow x=4:\frac{7}{3}=\frac{12}{7}\)
vậy x = 12/7
a/ x= 3 hoặc x= -7
mới nghĩ ra có phần a thui ak thông cảm nhé
Bài giải:
Câu 1: a, \(\left(-2\right).4.5.38.\left(-25\right)\)
\(=\left[\left(-2\right).5\right].\left[4.\left(-25\right)\right].38\)
\(=\left(-10\right).\left(-100\right).38\)
\(=1000.38=38000\)
b,\(\frac{1}{3}+\frac{3}{8}-\frac{7}{12}\)
\(=\left(\frac{1}{3}+\frac{3}{8}\right)-\frac{7}{12}\)
\(=\frac{17}{24}-\frac{7}{12}=\frac{1}{8}\)
c, \(\frac{-5}{8}.\frac{5}{12}+\frac{-5}{8}.\frac{7}{12}+2\frac{1}{8}\)
\(=\frac{-5}{8}.\left(\frac{5}{12}+\frac{7}{12}\right)+\frac{17}{8}\)
\(=\frac{-5}{8}.1+\frac{17}{8}\)
\(=\frac{3}{2}\)
Câu 2: a, \(x-\frac{2}{5}=0,24\)
\(x-0,4=0,24\)
\(x=0,24+0,4\)
\(\Rightarrow x=0,64\left(\frac{16}{25}\right)\)
b,\(\frac{2}{3}.x+\frac{1}{12}=\frac{1}{10}\)
\(\frac{2}{3}.x=\frac{1}{10}-\frac{1}{12}\)
\(\frac{2}{3}.x=\frac{1}{60}\)
\(x=\frac{1}{60}:\frac{2}{3}\)
\(\Rightarrow x=\frac{1}{40}\)
c, \(\left(3\frac{1}{2}-2x\right).1\frac{1}{3}=7\frac{1}{3}\)
\(\frac{7}{2}-2x=\frac{22}{3}:\frac{4}{3}\)
\(\frac{7}{2}-2x=\frac{11}{2}\)
\(2x=\frac{7}{2}-\frac{11}{2}\)
\(2x=-2\)
\(\Rightarrow x=-2:2\)
\(x=-1\)
Ta có : x(x + 3) = 0
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x+3=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-3\end{cases}}\)
1.
a) x . ( x + 3 ) = 0
\(\Rightarrow\orbr{\begin{cases}x=0\\x+3=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=-3\end{cases}}\)
b) ( x - 2 ) . ( 5 - x ) = 0
\(\Rightarrow\orbr{\begin{cases}x-2=0\\5-x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=5\end{cases}}}\)
c) \(\left(x-1\right).\left(x^2+1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-1=0\\x^2+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\\text{x không tồn tại}\end{cases}}}\)
1) x-2/5=0,24 2) (7/3 . x -0,6) : 3 . 2/5=1
x =6/25+2/5 (7/3 . x -3/5) :3 = 1: 2/5
x =6/25+10/25 (7/3 . x -3/5) :3 = 5/2
x =16/25 7/3 . x -3/5 =5/2 . 3
7/3 . x -3/5 =15/2
7/3 .x =15/2+3/5
7/3. x = 81/10
x = 81/10 : 7/3
x =243/70
2) \(\left(\frac{7}{3}.x-0,6\right):3\frac{2}{5}=1\Rightarrow\left(\frac{7}{3}x-\frac{3}{5}\right):\frac{17}{5}=1\Rightarrow\left(\frac{7}{3}x-\frac{3}{5}\right)=\frac{17}{5}\Rightarrow\frac{7}{3}x=\frac{17}{5}+\frac{3}{5}=4\Rightarrow4:\frac{7}{3}=4.\frac{3}{7}=\frac{12}{7}=1\frac{5}{7}\)