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\(x:\dfrac{13}{16}=\dfrac{5}{-8}\\ x=\dfrac{5}{-8}.\dfrac{13}{16}=\dfrac{65}{-128}\)
\(x.\dfrac{-1}{2}=\dfrac{-4}{5}\\ x=\dfrac{-4}{5}:\dfrac{-1}{2}=\dfrac{8}{5}\)
Ix+6I-9=2x
<=> Ix+6I=2x+9
<=> x+6=2x+9 hoặc x+6=-2x-9
<=> -x=3 hoặc 3x=-15
<=> x=-3 hoặc x=-5
Câu còn lại giải tương tự nha bạn
Ix+6I-9=2x
<=> Ix+6I=2x+9
<=> x+6=2x+9 hoặc x+6=-2x-9
<=> -x=3 hoặc 3x=-15
<=> x=-3 hoặc x=-5
Tick cho mik nghen
a)
\(\begin{array}{l}x - \left( { - \frac{7}{9}} \right) = - \frac{5}{6}\\x + \frac{7}{9} = - \frac{5}{6}\\x = - \frac{5}{6} - \frac{7}{9}\\x = - \frac{{15}}{{18}} - \frac{{14}}{{18}}\\x = \frac{{ - 29}}{{18}}\end{array}\)
Vậy \(x = \frac{{ - 29}}{{18}}\).
b)
\(\begin{array}{l}\frac{{15}}{{ - 4}} - x = 0,3\\x = \frac{{15}}{{ - 4}} - 0,3\\x = - 3,75 - 0,3\\x = - 4,05\end{array}\)
Vậy \(x = - 4,05\).
1: x=3/4-1/2=3/4-2/4=1/4
2: x-1/5=2/11
=>x=2/11+1/5=21/55
3: x-5/6=16/42-8/56
=>x-5/6=8/21-4/28=5/21
=>x=5/21+5/6=15/14
4: x/5=5/6-19/30
=>x/5=25/30-19/30=6/30=1/5
=>x=1
5: =>|x|=1/3+1/4=7/12
=>x=7/12 hoặc x=-7/12
6: x=-1/2+3/4
=>x=3/4-1/2=1/4
11: x-(-6/12)=9/48
=>x+1/2=3/16
=>x=3/16-1/2=-5/16
1)x= 1/4
2)x= 2/11+ 1/5
x= 21/55
3)x - 5/6 = 5/21
x = 5/21+5/6
x = 15/14
4)x/5 = 5/6 + -19/30
x:5 = 1/5
x = 1/5.5
x = 1
5) |x| - 1/4 = 6/18
|x| = 6/18 - 1/4
|x| =7/12
⇒x= 7/12 hoặc -7/12
6)x = -1/2 +3/4
x= 1/4
7) x/15 = 3/5 + -2/3
x:15 = -1/15
x = -1/15. 15
x = -1
8)11/8 + 13/6 = 85/x
85/24 = 85/x
⇒ x = 24
9) x - 7/8 = 13/12
x = 13/12 + 7/8
x = 47/24
10)x - -6/15 = 4/27
x = 4/27 + (-6/15)
x = -34/135
11) -(-6/12)+x = 9/48
x= 9/48 - 6/12
x = -5/16
12) x - 4/6 = 5/25 + -7/15
x -4/6 = -4/15
x = -4/15 + 4/6
x = 2/5
\(\frac{x+12}{7}+\frac{x+4}{15}+\frac{x+6}{13}=\frac{x+8}{11}+\frac{x+10}{9}+\frac{x+12}{7}\)
=>\(\left(\frac{x+12}{7}+1\right)+\left(\frac{x+4}{15}+1\right)+\left(\frac{x+6}{13}+1\right)=\left(\frac{x+8}{11}+1\right)+\left(\frac{x+10}{9}+1\right)+\left(\frac{x+12}{7}+1\right)\)
=> \(\frac{x+19}{7}+\frac{x+19}{15}+\frac{x+19}{13}=\frac{x+19}{11}+\frac{x+19}{9}+\frac{x+19}{7}\)
=> \(\frac{x+19}{7}+\frac{x+19}{15}+\frac{x+19}{13}-\frac{x+19}{11}-\frac{x+19}{9}-\frac{x+19}{7}=0\)
\(\Rightarrow\left(x+19\right)\left(\frac{1}{7}+\frac{1}{15}+\frac{1}{13}-\frac{1}{11}-\frac{1}{9}-\frac{1}{7}\right)=0\)
=> x + 19 = 0 Vì \(\frac{1}{7}+\frac{1}{15}+\frac{1}{13}-\frac{1}{11}-\frac{1}{9}-\frac{1}{7}\ne0\)
=> x = - 19
Bài làm:
Ta có: \(\frac{x+12}{7}+\frac{x+4}{15}+\frac{x+6}{13}=\frac{x+8}{11}+\frac{x+10}{9}+\frac{x+12}{7}\)
\(\Leftrightarrow\left(\frac{x+12}{7}+1\right)+\left(\frac{x+4}{15}+1\right)+\left(\frac{x+6}{13}+1\right)-\left(\frac{x+8}{11}+1\right)-\left(\frac{x+10}{9}+1\right)-\left(\frac{x+12}{7}+1\right)=0\)
\(\Leftrightarrow\frac{x+19}{7}+\frac{x+19}{15}+\frac{x+19}{13}-\frac{x+19}{11}-\frac{x+19}{9}-\frac{x+19}{7}=0\)
\(\Leftrightarrow\left(x+19\right)\left(\frac{1}{7}+\frac{1}{15}+\frac{1}{13}-\frac{1}{11}-\frac{1}{9}-\frac{1}{7}\right)=0\)
\(\Leftrightarrow\left(x+19\right)\left(\frac{1}{15}+\frac{1}{13}-\frac{1}{11}-\frac{1}{9}\right)=0\)
Mà \(\hept{\begin{cases}\frac{1}{15}< \frac{1}{11}\\\frac{1}{13}< \frac{1}{9}\end{cases}\Rightarrow}\frac{1}{15}+\frac{1}{13}-\frac{1}{11}-\frac{1}{9}< 0\)
\(\Rightarrow x+19=0\)
\(\Rightarrow x=-19\)
a) Có: y tỉ lệ thuận với x và khi x=6 thì y=4
\(\Rightarrow\dfrac{x}{y}=\dfrac{6}{4}=\dfrac{3}{2}\Rightarrow y=\dfrac{2}{3}x\)
b) Khi x = 9 \(\Rightarrow y=\dfrac{2}{3}\cdot9=6\)
Khi y =15 \(\Rightarrow15=\dfrac{2}{3}x\Rightarrow x=22,5\)
Do y tỉ lệ thuận với x nên y = kx (k là hệ số tỉ lệ)
\(\Rightarrow k=\dfrac{y}{x}=\dfrac{4}{6}=\dfrac{2}{3}\)
a) Biểu diễn y theo x:
\(y=\dfrac{2}{3}.x\)
b) Khi x = 9 \(\Rightarrow y=\dfrac{2}{3}.9=6\)
Khi y = 15 \(\Rightarrow\dfrac{2}{3}.x=15\Rightarrow x=15:\dfrac{2}{3}=\dfrac{45}{2}\)
a)5/x=2/10
<=>2x=5.10
<=>2x=50
<=>x=25
=>5/25=y/-15
=>y/-15=1/5
=>y=-15/5=-3
b)x/-6=3/9
<=>x/-6=1/3
<=>x/-6=2/6=-2/-6
<=>x=-2
4/y=3/9
<=>4/y=1/3
<=>4/y=4/12
<=>y=12
a,\(\frac{5}{x}=\frac{y}{-15}=\frac{2}{10}\)
\(\frac{2}{10}=\frac{1}{5}\)
Nên Ta có:
\(\frac{5}{x}=\frac{y}{-15}=\frac{1}{5}\)
<=> x = 5.5
<=> x = 25
Vậy, x = 25
<=> 5y = -15
<=> y = -15:5
<=> y = -3
Vậy, y = -3
b, \(\frac{x}{6}=\frac{4}{y}=\frac{3}{9}\)
Mà \(\frac{3}{9}=\frac{1}{3}\)
Nên Ta có:
\(\frac{x}{6}=\frac{4}{y}=\frac{1}{3}\)
<=> 3x=6
<=> x = 6:3
<=> x = 2
Vậy, x = 2
<=> y = 4.3
<=> y =12
Vậy, y = 12
\(-\dfrac{6}{x}=\dfrac{9}{-15}\)
\(\Rightarrow9x=\left(-6\right).\left(-15\right)\)
\(\Rightarrow9x=90\)
\(\Rightarrow x=90:9\)
\(\Rightarrow x=10\)