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a) \(\left(12x-4^3\right).8^3=4.8^4\)
\(12x-4^3=32\)
12x = 96
x = 8
b) \(\left(3x-2^4\right).7^3=2.7^4\)
3x - 24 = 14
3x = 30
x = 10
![](https://rs.olm.vn/images/avt/0.png?1311)
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a) \(\frac{3}{7}-\frac{1}{7}x=\frac{2}{3}\)
=> \(\frac{1}{7}x=\frac{3}{7}-\frac{2}{3}=-\frac{5}{21}\)
=> \(x=-\frac{5}{21}:\frac{1}{7}=-\frac{5}{21}\cdot7=-\frac{5}{3}\)
b) \(3x^2-2=72\)=> 3x2 = 74 => x2 = 74/3 => x không thỏa mãn
c) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)
=> \(\left(19x+2\cdot25\right):14=5^2-4^2=9\)
=> \(\left(19x+50\right):14=9\)
=> \(19x+50=126\)
=> \(19x=76\)
=> x = 4
d) \(x:\frac{1}{2}+x:\frac{1}{4}+x:\frac{1}{8}+x:\frac{1}{16}+x:\frac{1}{32}=343\)
=> \(x\cdot2+x\cdot4+x\cdot8+x\cdot16+x\cdot32=343\)
=> \(x\left(2+4+8+16+32\right)=343\)
=> x . 62 = 343
=> x = 343/62
( 3x - 2 mũ 4 ) . 7 mũ 3 = 2 . 7 mũ 4
5x-2 - 3 mũ 2 = 2 mũ 4 - ( 2 mũ 1 . 2 mũ 4 - 2 mũ 10. 2 mũ 2 )
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(3x-2^4\right)\cdot7^3=2\cdot7^4\)
\(3x-2^4=7^4\cdot2:7^3=7\cdot2=14\)
\(3x-16=14\)
\(3x=14+16=30\)
\(x=\frac{30}{3}=10\)
vậy x=10
\(\left(3x-2^4\right)\cdot7=2\cdot7^2\)
\(\Leftrightarrow3x-2^4=2\cdot7^2:7\)
\(\Leftrightarrow3x-16=2\cdot7\)
\(\Leftrightarrow3x-16=14\)
\(\Leftrightarrow3x=14+16\)
\(\Leftrightarrow3x=30\)
\(\Leftrightarrow=30:3\)
\(\Leftrightarrow x=10\)
Vậy x=10