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a, 3x - 2 ⋮ x + 3
=> 3x + 9 - 11 ⋮ x + 3
=> 3(x + 3) - 11 ⋮ x + 3
=> 11 ⋮ x + 3
b, x ⋮ 2x + 1
=> 2x ⋮ 2x + 1
=> 2x + 1 - 1 ⋮ 2x + 1
=> 1 ⋮ 2x + 1
c, 3x + 6 ⋮ x + 1
=> 3x + 3 + 3 ⋮ x + 1
=> 3(x + 1) + 3 ⋮ x + 1
=> 3 ⋮ x + 1
d, em không biết làm
câu a,b,c bn Cả Út lm r
mik làm câu d
\(x^2⋮x-2\)
\(\Rightarrow x\left(x-2\right)+2x⋮x-2\)
\(\Rightarrow2x⋮x-2\)
\(\Rightarrow2\left(x-2\right)+4⋮x-2\)
\(\Rightarrow4⋮x-2\)
\(\Rightarrow x-2\inƯ\left(4\right)=\left\{\pm1;\pm2;\pm4\right\}\)
\(\Rightarrow n\in\left\{3;1;4;0;6;-2\right\}\)
Vậy..............................
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bài 1
\(\frac{3x-y}{x+y}=\frac{3}{4}\)
\(\Rightarrow\left(3x-y\right).4=\left(x+y\right)3\)
\(\Rightarrow12x-4y=3x+3y\)
\(\Rightarrow9x=7y\)
\(\Rightarrow\frac{x}{y}=\frac{7}{9}\)
Vậy \(\frac{x}{y}=\frac{7}{9}\)
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\(8^{x+1}+2^{3x+1}=320\)
\(\left(2^3\right)^{\left(x+1\right)}+2^{3x}.2=320\)
\(2^{3x}.2^3+2^{3x}.2=320\)
\(2^{3x}\left(8+2\right)=320\)
\(2^{3x}=32\)
\(2^{3x}=2^5\)
\(3x=5\)
\(x=\frac{5}{3}\)
toàn bộ số dương phải không bạn
nếu x dương thì I 3x-1 I-I 3x-2 I=3x-1-( 3x-2)= 3x-1-3x+2=1( luôn luôn đúng) nếu x âm thì I 3x-1I-I3x-2I= -( 3x-1)-[-(3x-2)]=-(3x-1)+3x-2=3x-2-3x+1=-1( sai) nếu x=0 thì I3x-1I- I3x-2I=1-2= -1