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a) Ta có : (3x - 0.5) ( 2x + 2.5) = 0
\(\Leftrightarrow\orbr{\begin{cases}3x-0,5=0\\2x+2,5=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}3x=0,5\\2x=-2,5\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{0,5}{3}=\frac{1}{6}\\x=-\frac{2,5}{2}=\frac{5}{4}\end{cases}}\)

1
2(\(\frac{3}{4}\)-5x)=\(\frac{4}{5}\)-3x
=> \(\frac{6}{4}-10x=\frac{4}{5}-3x\)
=>\(-10x+3x=\frac{4}{5}-\frac{6}{4}\)
=> \(x=\frac{1}{10}\)
2 .
\(\frac{3}{2}-4\left(\frac{1}{4}-x\right)=\frac{2}{3}-7x\)
=>\(\frac{3}{2}-1+4x=\frac{2}{3}-7x\)
=>\(11x=\frac{1}{6}\)
=>x=\(\frac{1}{66}\)
3.
\(3\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)
=>\(\frac{3}{2}-3x+\frac{1}{3}=\frac{7}{6}-x\)
=>\(-2x=\frac{-2}{3}\)
=>\(\frac{1}{3}\)
4. câu 4 ko hiểu bạn ơi

1)\(-\frac{3}{2}\left(\frac{4}{5}-\frac{2}{3}\right)+x=4\left(x-\frac{2}{3}\right)\)
\(\Leftrightarrow-\frac{3}{2}\cdot\frac{2}{15}+x=4x-\frac{8}{3}\)
\(\Leftrightarrow-\frac{1}{5}+x=4x-\frac{8}{3}\)
\(\Leftrightarrow x-4x=-\frac{8}{3}+\frac{1}{5}\)
\(\Leftrightarrow-3x=-\frac{37}{15}\)
\(\Leftrightarrow x=\frac{37}{45}\)
2)\(2\left(\frac{3}{2}-x\right)-\frac{1}{3}=7x-\frac{1}{4}\)
\(\Leftrightarrow3-2x-\frac{1}{3}=7x-\frac{1}{4}\)
\(\Leftrightarrow-2x-7x=-\frac{1}{4}-3+\frac{1}{3}\)
\(\Leftrightarrow-9x=-\frac{35}{12}\)
\(\Leftrightarrow x=\frac{35}{108}\)
3)\(\frac{1}{5}\left(-\frac{3}{5}10\right)+5x=x-\frac{2}{3}\)
\(\Leftrightarrow-\frac{6}{5}+5x=x-\frac{2}{3}\)
\(\Leftrightarrow5x-x=-\frac{2}{3}+\frac{6}{5}\)
\(\Leftrightarrow4x=\frac{8}{15}\)
\(\Leftrightarrow x=\frac{2}{15}\)
4)\(-\frac{3}{2}\left(5-\frac{1}{6}\right)+4\left(x-\frac{1}{2}\right)=1\)
\(\Leftrightarrow-\frac{15}{2}+\frac{1}{4}+4x-2=1\)
\(\Leftrightarrow4x=1+\frac{15}{2}-\frac{1}{4}+2\)
\(\Leftrightarrow4x=\frac{41}{4}\)
\(\Leftrightarrow x=\frac{41}{16}\)

=> 4X + 10 = 110
=> 4X = 110 - 10
=> 4X = 100
=> X = 100 : 4
=> X = 25
(X+1) + (X + 2) + (X + 3) + (X + 4) = 110
<=>(x+x+x+x)+(1+2+3+4)=110
<=>4x+10=110
<=>4x=100
<=>x=25

1,\(2\left(\frac{3}{4}-5x\right)=\frac{4}{5}-3x\)
\(\frac{6}{4}-10x=\frac{4}{5}-3x\)
\(\frac{6}{4}+\frac{4}{5}=7x\)
\(\frac{23}{10}=7x\)
\(\frac{23}{70}=x\)
2,\(\frac{3}{2}-4\left(\frac{1}{4}-x\right)=\frac{2}{3}-7x\)
\(\frac{3}{2}-1-4x=\frac{2}{3}-7x\)
\(\frac{3}{2}-1-\frac{2}{3}=-3x\)
\(\frac{-1}{6}=-3x\)
\(\frac{1}{18}=x\)
3,\(3\left(\frac{1}{2}-x\right)+\frac{1}{3}=\frac{7}{6}-x\)
\(\frac{3}{2}-3x+\frac{1}{3}=\frac{7}{6}-x\)
\(\frac{3}{2}-\frac{7}{6}+\frac{1}{3}=2x\)
\(\frac{2}{3}=2x\)
\(\frac{1}{3}=x\)
4,mình không hiểu a ở đây là gì

a)\(\frac{3x}{7}=\frac{5x-1}{2}=>\frac{6x}{14}=\frac{35x-7}{14}\)
=>6x=35x-7
=>35x-6x=7
=>29x=7
=>\(x=\frac{7}{29}\)
b)\(\frac{2-5x}{3}=\frac{4+x}{5}=>\frac{10-25x}{15}=\frac{12+3x}{15}\)
=>10-25x=12+3x
=>25x+3x=10-12
=>28x=-2
=>\(x=\frac{-2}{28}=-\frac{1}{14}\)
\(\dfrac{3}{5}x-\dfrac{25}{4}=\dfrac{1}{2}:x+\dfrac{5}{4}\)
=>\(\dfrac{3}{5}x-\dfrac{25}{4}-\dfrac{1}{2x}+\dfrac{5}{4}\)
=>\(\dfrac{3}{5}x-\dfrac{1}{2x}=\dfrac{30}{4}\)
=>\(\dfrac{3x}{5}-\dfrac{1}{2x}=\dfrac{30}{4}\)
=>\(\dfrac{6x^2-5}{10x}=\dfrac{30}{4}\)
=>\(6x^2-5=10x\cdot\dfrac{30}{4}=5x\cdot15=75x\)
=>\(6x^2-75x-5=0\)
=>\(x=\dfrac{75\pm\sqrt{5745}}{12}\)