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a)
x= 43
b) 2X-12=8
2X =8+12
2X=20
X=20:2
x =10
c)45:(3X-17)=32
45 : (3X-17)=9
3X-17=45:9
3X-17=5
3X=5+17
3X=22
x=22:3
x= 7,33
d)(2X-8)x2=24
( 2X-8)x2 =16
2X-8 =16:2
2X-8 =8
2X =8+8
2X =16
x =16:2
X =8
Đúng thì tk nếu sai thì thôi
Làm ẩu ^^
\(\left(x-1\right)^2+\left|2y-x\right|=0\)
có \(\hept{\begin{cases}\left(x-1\right)^2\ge0\\\left|2y-x\right|\ge0\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}x-1=0\\2y-x=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=1\\2y-1=0\end{cases}}\Leftrightarrow\hept{\begin{cases}x=1\\y=\frac{1}{2}\end{cases}}}\)
vậy_
\(\frac{2}{5}.\frac{1}{x}+\frac{1}{x}.2+\frac{2}{5}=0,5\)
\(\Rightarrow\frac{2}{5x}+\frac{2}{x}+\frac{2}{5}=\frac{1}{2}\)
\(\Rightarrow2.\left(\frac{1}{5x}+\frac{1}{x}+\frac{1}{5}\right)=\frac{1}{2}\)
\(\Rightarrow\frac{1}{5x}+\frac{5}{5x}+\frac{x}{5x}=\frac{1}{2}:2=\frac{1}{4}\)
\(\Rightarrow\frac{1+5+x}{5x}=\frac{1}{4}\)
\(\Rightarrow4.\left(1+5+x\right)=5x\)
\(\Rightarrow4+20+4x=5x\)
\(\Rightarrow24+4x=5x\)
\(\Rightarrow5x-4x=24\)
\(\Rightarrow x=24\)
a) 128 - 3(x + 4) = 23
3(x + 4) = 128 -23
3(x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31
\(a.128-3\left(x+4\right)=23.\)
\(3\left(x+4\right)=128-23\)
\(3\left(x+4\right)=105\)
\(x+4=105:3=35\)
\(x=35-4=31\)
\(b.\left[\left(4x+28\right)\cdot3+55\right]:5=35\)
\(\left(4x+28\right)\cdot3+55=35\cdot5=175\)
\(\left(4x+28\right)\cdot3=175-55=120\)
\(4x+28=120:3=40\)
\(4x=40-28=12\)
\(x=12:4=3\)
\(5x=6y\Leftrightarrow\frac{x}{6}=\frac{y}{5};x^2-y^3=11\)
Tính chất dãy tỉ số bằng nhau:
\(\frac{x}{6}=\frac{y}{5}=\frac{x^2-y^3}{6^2-5^3}=\frac{11}{-89}=-\frac{11}{89}\)
\(\Rightarrow\hept{\begin{cases}\frac{x}{6}=-\frac{11}{89}\Leftrightarrow x=\frac{-11.6}{89}=-\frac{66}{89}\\\frac{y}{5}=-\frac{11}{89}\Leftrightarrow y=\frac{-11.5}{89}=-\frac{55}{89}\end{cases}}\)
131 . x - 942 = 2^7 . 2^3
131 . x - 942 = 2^10
131 . x - 942 = 1024
131 . x = 1024 + 942
131 . x = 1966
x = 1966 : 131
x \(\approx15\)
b ) [ ( x + 32 ) - 17 ] . 2 = 42
[ ( x + 32 ) - 17 ] = 42 : 2
( x + 32 ) - 17 = 21
x + 32 = 21 + 17
x + 32 = 38
x = 38 - 32
x = 6
a) \(\left(5x+3^4\right).6^8=6^9.3^4\)
\(=>6x+3^4=3^4.6^9:6^8\)
\(=>6x+3^4=3^4.6\)
\(=>6x=6.3^4-3^4\)
\(=>6x=0\)
\(=>x=0:6\)
\(=>x=0\)
a/(5x + 34).68=69.34
(5x + 34) = 69:68.34
5x + 81 = 6.81
5x = 6.81 - 81
5x = 486 - 81
5x = 425
x = 425:5
x = 85
b/92 - 2x = 2.42- 3.4 + 120:15
92 - 2x = 2.16 - 12 + 8
92 - 2x = 32 - 12 + 8
92 - 2x = 28
2x = 92 - 28
2x = 64
x = 64:2
x = 32
c/53.(3x + 2) : 13 = 103: (135:134)
125.(3x + 2) : 13 = 1000:13
125.(3x+2) = 1000:13.13
125.(3x+2) = 1000
3x + 2 = 1000:125
3x + 2 = 8
3x = 8 - 2
3x = 6
x = 6:3
x = 2
Bạn nhớ tick cho mình nhé!
2x^2 - xy + 2x - y = 5
=> (2 x^2 - xy) + (2x - y) = 5
=> x (2 x - y) + (2x - y) = 5
=> (x + 1 ) (2 x - y)= 5
th1:
=> \(\hept{\begin{cases}x+1=5\\2x-y=1\end{cases}}\)
=> \(\hept{\begin{cases}x=4\\y=7\end{cases}}\)
th2
=>\(\hept{\begin{cases}x+1=1\\2x-y=5\end{cases}}\)
=> \(\hept{\begin{cases}x=0\\y=-5\end{cases}}\)
th3
=> \(\hept{\begin{cases}x+1=-1\\2x-y=-5\end{cases}}\)
=> \(\hept{\begin{cases}x=-2\\y=-1\end{cases}}\)
th4
=> \(\hept{\begin{cases}x+1=-5\\2x-y=-1\end{cases}}\)
=> \(\hept{\begin{cases}x=-6\\y=-11\end{cases}}\)
:2x^2-xy+2x-y=5
cái đề này có y mà