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a, 4x - 3x + 1 = 5
x =5-1
x =4
Vậy x=4
b, (2x - 4 ) . 3x =0
=> 2x - 4 =0 hoặc 3x = 0
=> 2x =4 hoặc x=0
=> x =2 hoặc x=0
vậy x= 2 hoặc x=0
c, x . ( x -1 ) - ( x-1 )=0
(x-1) . (x-1 ) =0
(x-1)2 =02
x-1 =0
x =1
vậy x=1
2/ a, 7 . (x - 1 ) = 6x + 3
7x -7 = 6x +3
7x - 6x =7+3
x =10
vậy x=10
b, 8 . ( 2x - 3 ) -15x =4
16x - 24 -15x =4
16x - 15x =4+24
x =28
vậy x=28
c, 7 . 10 + ( x-1 ) .2 =100
70 + 2x -2 =100
2x -2 =100-70
2x -2 =30
2x =30+2
2x =32
x =16
vậy x=16
chúc bn học tốt
b, \(\frac{1}{6}x+\frac{1}{10}x-\frac{4}{15}x+1=0\)
\(x\left(\frac{1}{6}+\frac{1}{10}-\frac{4}{15}\right)+1=0\)
\(x.0=-1\)
\(\Rightarrow x\in rỗng\)
a, \(\Rightarrow x-2\inƯ\left(-3\right)=\left\{\pm1;\pm3\right\}\)
x-2 | 1 | -1 | 3 | -3 |
x | 3 | 1 | 5 | -1 |
b, \(3\left(x-2\right)+13⋮x-2\Rightarrow x-2\inƯ\left(13\right)=\left\{\pm1;\pm13\right\}\)
x-2 | 1 | -1 | 13 | -13 |
x | 3 | 1 | 15 | -11 |
c, \(x\left(x+7\right)+2⋮x+7\Rightarrow x+7\inƯ\left(2\right)=\left\{\pm1;\pm2\right\}\)
x+7 | 1 | -1 | 2 | -2 |
x | -6 | -8 | -5 | -9 |
a) \(x-2=-6\)
\(x=-6+2\)
\(x=-4\)
b) \(15-\left(x-7\right)=-21\)
\(x-7=36\)
\(x=43\)
c) \(4.\left(3x-4\right)-2=18\)
\(4\left(3x-4\right)=20\)
\(3x-4=5\)
\(3x=9\)
\(x=3\)
d) \(\left(3x-6\right)+3=32\)
\(3x-6=29\)
\(3x=29+6\)
\(3x=35\)
\(x=\frac{35}{3}\)
e) \(\left(3x-6\right).3=32\)
\(3x-6=\frac{32}{3}\)
\(3x=\frac{32}{3}+6\)
\(3x=\frac{50}{3}\)
\(x=\frac{50}{9}\)
f) \(\left(3x-6\right):3=32\)
\(3x-6=96\)
\(3x=102\)
\(x=34\)
g) \(\left(3x-6\right)-3=32\)
\(3x-6=35\)
\(3x=41\)
\(x=\frac{41}{3}\)
h) \(\left(3x-2^4\right).7^3=2.7^4\)
\(\left(3x-2^4\right)=2.7=14\)
\(\left(3x-16\right)=14\)
\(3x=14+16=30\)
\(x=10\)
i) \(\left|x\right|=\left|-7\right|\)
\(\left|x\right|=7\)
\(\Rightarrow\orbr{\begin{cases}x=7\\x=-7\end{cases}}\)
k) \(\left|x+1\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x+1=2\\x+1=-2\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x=-3\end{cases}}}\)
l) \(\left|x-2\right|=3\)
\(\Rightarrow\orbr{\begin{cases}x-2=3\\x-2=-3\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-1\end{cases}}}\)
m) \(x+\left|-2\right|=0\)
\(x+2=0\)
\(x=-2\)
o) \(72-3\left|x+1\right|=9\)
\(3\left|x-1\right|=63\)
\(\left|x-1\right|=21\)
\(\Rightarrow\orbr{\begin{cases}x-1=21\\x-1=-21\end{cases}\Rightarrow\orbr{\begin{cases}x=22\\x=-20\end{cases}}}\)
p) Ta có: \(\left|x-1\right|=3\)
\(\Rightarrow\orbr{\begin{cases}x-1=3\\x-1=-3\end{cases}}\)
mà \(x+1< 0\)
\(\Rightarrow x-1=-3\)
\(\Rightarrow x=-2\)
q) \(\left(x-2\right)\left(x+4\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-2=0\\x+4=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=-4\end{cases}}}\)
hok tốt!!
( 2. l x l - 1) .(7 - 3x ) =0 ( x2 + 1 ). ( 1/2 - 3x ) <0 ( l x l + 1 ) . ( 15x - 1 ) = 0
=> 2 . l x l - 1 = 0 hoặc 7 - 3x = 0 => x2+1 hoặc 1/2 -3x < 0 => l x l + 1 hoặc 15x - 1 =0
+ 2 . l x l - 1 = 0 => 2 . l x l =1 => x = 1/2 + x2 +1< 0 => x không tồn tại + l x l - 1 = 0 => l x l = 1 => thuộc 1 : -1
+ 7 - 3x = 0 => 3x = 7 => x = 7/3 + 1/2 - 3x < 0 => 3x > 1/2 => x > 1 + 15x - 1 = 0 => 15x =1 => x = 1/15