
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


a) Ta có:
252/x = 84/97
==> x.84=252.97
==> x.84= 24444
==> x=24444:84
==> x=291
b) x/17 + 19/34=1/2
X/17=1/2–19/34
X/17=17/34–19/34
X/17=—2/34
==> x.34=17.(—2)
==> x.34=-34
==> x=(—34):34
==> x=—1
dàiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

a. Vì 252/x=84/97 nên => 252.97=84.x hay 84.x =24444 => x= 24444: 84= 291
b 7/5 :x = 4/5-1/6
7/5 :x =19/30
x=7/5:19/30
x=42/19
c Tự làm đi dễ mà
tính ra rồi tìm

a) \(\frac{53}{101}\cdot-\frac{13}{97}+\frac{53}{101}\cdot-\frac{84}{97}\)
\(=\frac{53}{101}\cdot\left(-\frac{13}{97}-\frac{84}{97}\right)\)
\(=\frac{53}{101}\cdot\left(-1\right)\)
\(=-\frac{53}{101}\)

\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
\(\Rightarrow\left(\frac{x+1}{99}+1\right)+\left(\frac{x+2}{98}+1\right)+\left(\frac{x+3}{97}+1\right)+\left(\frac{x+4}{96}+1\right)=0\)
\(\Rightarrow\frac{x+100}{99}+\frac{x+100}{98}+\frac{x+100}{97}+\frac{x+100}{99}=0\)
\(\Rightarrow\left(x+100\right)\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{98}\right)=0\)
\(\Rightarrow x+100=0\)
\(\Rightarrow x=-100\)

Ta có : \(\frac{3}{x}=\frac{-36}{84}=\frac{3}{7}\) => \(x=7\)
\(\frac{y}{35}=\frac{-36}{84}=\frac{3}{7}\)=> \(7y=3\cdot35\)=> \(y=\frac{3\cdot35}{7}=15\)

Ta có: \(\frac{-36}{84}=\frac{-3}{7}\)
\(\frac{3}{x}=\frac{-3}{7}\Rightarrow x=\frac{3.7}{-3}=-7\)
\(\frac{y}{35}=\frac{-3}{7}\Rightarrow y=\frac{\left(-3\right).35}{7}=-15\)
Vậy x = -7; y = -15

a) \(1\frac{1}{3}.1\frac{1}{8}.1\frac{1}{15}.1\frac{1}{24}.........1\frac{1}{99}\)
\(=\frac{4}{3}.\frac{9}{8}.\frac{16}{15}.\frac{25}{24}......\frac{100}{99}\)
\(=\frac{\left(2.2\right).\left(3.3\right).\left(4.4\right).\left(5.5\right)....\left(10.10\right)}{\left(1.3\right).\left(2.4\right).\left(3.5\right).\left(4.6\right).....\left(9.11\right)}\)
\(=\frac{\left(2.3.4.5...10\right).\left(23.4.5....10\right)}{\left(1.2.3.4...9\right).\left(3.4.5.6....11\right)}=\frac{10}{1}.\frac{2}{11}=\frac{20}{11}\)
b) \(\frac{99}{98}-\frac{98}{97}+\frac{1}{97.98}=\frac{99}{98}-\frac{98}{97}+\frac{1}{97}-\frac{1}{98}=\left(\frac{99}{98}-\frac{1}{98}\right)-\left(\frac{98}{97}-\frac{1}{97}\right)\)
\(=\frac{98}{98}-\frac{97}{97}=1-1=0\)

\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
\(\frac{x+1}{99}+1+\frac{x+2}{98}+1+\frac{x+3}{97}+1+\frac{x+4}{96}+1=-4+4=0\)
\(\frac{x+100}{99}+\frac{x+100}{98}+\frac{x+100}{97}+\frac{x+100}{96}=0\)
\(\left(x+100\right)\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\right)=0\)
Mà \(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\ne0\)
\(\Rightarrow x+100=0\)
\(x=-100\)
Vậy..........................
\(\frac{x+1}{99}+\frac{x+2}{98}+\frac{x+3}{97}+\frac{x+4}{96}=-4\)
\(\Leftrightarrow\)\(\frac{x+1}{99}+1+\frac{x+2}{98}+1+\frac{x+3}{97}+1+\frac{x+4}{96}+1=0\)
\(\Leftrightarrow\)\(\frac{x+100}{99}+\frac{x+100}{98}+\frac{x+100}{97}+\frac{x+100}{96}=0\)
\(\Leftrightarrow\)\(\left(x+100\right)\left(\frac{1}{99}+\frac{1}{98}+\frac{1}{97}+\frac{1}{96}\right)=0\)
\(\Leftrightarrow\)\(x+100=0\) ( do 1/99 + /198 + /197 + 1/96 # 0 )
\(\Leftrightarrow\)\(=-100\)
Vậy...

Hướng dẫn giải :
Xét đẳng thức ta thấy : \(\frac{3}{x}\)= \(\frac{-36}{84}\)ta có :
Cách 1 :
Đưa về hai phân số có phần tử bằng cách rút gọn phân số : \(\frac{-36}{84}\)= \(\frac{-36}{84}\)= \(\frac{-36:\left(-12\right)}{84:\left(-12\right)}\)= \(\frac{3}{-7}\)
khi đó : \(\frac{3}{x}\)= \(\frac{3}{-7}\), suy ra x = -7
Cách 2 :
từ đẳng thức \(\frac{3}{x}\)= \(\frac{-36}{84}\)ta có : x.( -36 )= 3.84
suy ra x = \(\frac{3.84}{-36}\)= - 7
* xét đẳng thức \(\frac{y}{35}\)= \(\frac{-36}{84}\)
Từ đẳng thức \(\frac{y}{35}\)= \(\frac{-36}{84}\), ta có y . 84= 35.( -36 )
suy ra y = \(\frac{35.\left(-36\right)}{84}\)= -15
\(\frac{252}{x}x\frac{84}{97}\)
x.84 = 252.97
x.84 = 24444
x = 24444 : 84
x = 291