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\(a)x=\dfrac{1}{4}+\dfrac{5}{13}=\dfrac{33}{52}.\\ b)\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}.\\ \Leftrightarrow\dfrac{x}{3}=\dfrac{11}{21}.\\ \Leftrightarrow\dfrac{7x}{21}=\dfrac{11}{21}.\\ \Rightarrow7x=11.\\ \Leftrightarrow x=\dfrac{11}{7}.\\ c)\dfrac{x}{3}=\dfrac{16}{24}+\dfrac{24}{36}=\dfrac{2}{3}+\dfrac{2}{3}=\dfrac{4}{3}.\\ \Rightarrow x=4.\\ d)\dfrac{x}{15}=\dfrac{1}{5}+\dfrac{2}{3}=\dfrac{13}{15}.\\ \Rightarrow x=13.\)
Để mình làm cho...
...........
a. -x + 17 = (-24 - 15 +35)
-x + 17 = -4
............đến dây thui............
b. 39-2.x=-51
-2.x=39-(-51)
-2.x=90
x=90:-2
x=-45
c. | x - 3 | - 2 = 15
| x - 3 | = 15 + 2
| x - 3 | = 17
=> x - 3 = 17 hoặc x - 3 = - 17
=> x = 17 + 3 hoặc x = - 17 + 3
=> x = 20 hoặc x = - 14
Nhớ tick mình nha.........
Giải
a) 24 + (15-x) = 16
<=> 15-x=16-24
<=> 15-x=(-8)
<=> x = 15-(-8) => x = 23
b) 11 - (24-x) =
<=> 24-x= 11 - (-27)
<=> 24 - x = 38
<=> x = 24 - 38 => x = -14
c) |x-16| = 42
<=> x-16=42 và x-16=-42
<=> x = 42 + 16 ; x =-42+16
<=> x = 58 ; x = -26
d) 10-2|x| = (-2) . (-3)
<=> 10 - (-2) . (-3) = 2|x|
<=> 10 - 6 = 2|x|
<=> 2|x| = 4
<=> |x| = 4 : 2 = 2
=> x = 2 hoặc x = (-2)
A/ 24+(15-x)=16
(15-x)= 16- 24
(15-x)= - 18
x = 5 - (-18)
x = 23
B/ 11-(24-x)=(-3)3
(24-x)=11- 27
(24-x)= -16
x = 24 -(- 16)
x= 40
C/
\(\left|x-16\right|=42\hept{\begin{cases}x-16=42\\x-16=-42\end{cases}}\hept{\begin{cases}x=42+16\\x=-42+16\end{cases}}\hept{\begin{cases}x=58\\x=-26\end{cases}}\)
D/ 10-2|x|=(-2)x(-3)
10-2|x|=6
2|x|=10-6
2|x|=4
x=4:2
x=2
a)2x.3+12=24
2x.3=24-12
2x.3=12
2x=12:3
2x=4
2x=22
=>x=2
2x . 3 + 12 = 24
2x . 3 = 24 - 12
2x . 3 = 12
2x = 12 : 3
2x = 4
2x = 22
=> x = 2
b) 2x . 51 + 2 = 47
2x . 5 = 47 - 2
2x . 5 = 45
2x = 45 : 5
2x = 9
=> ko có giá trị x
Bài 2:
a: \(\Leftrightarrow x-1\in\left\{1;-1;2;-2;3;-3;6;-6\right\}\)
=>\(x\in\left\{2;0;3;-1;4;-2;7;-5\right\}\)
b: \(\Leftrightarrow x+3\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)
=>\(x\in\left\{-2;-4;0;-6;2;-8;12;-18\right\}\)
c: \(\Leftrightarrow x+3\in\left\{1;-1;2;-2;3;-3;4;-4;6;-6;12;-12\right\}\)
=>\(x\in\left\{-2;-4;-1;-5;0;-6;1;-7;3;-9;9;-15\right\}\)
d: =>x+1+15 chia hết cho x+1
=>\(x+1\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)
=>\(x\in\left\{0;-2;2;-4;4;-6;14;-16\right\}\)
Dễ mak
nhưng mik nhìn đề thấy dài quá nên ko muốn làm
hihi^_$
c) \(\left(34-2x\right)\left(2x-6\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}34-2x=0\\2x-6-0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)
d) \(\left(2019-x\right)\left(3x-12\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\3x=12\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)
e) \(57\left(9x-27\right)=0\)
\(\Rightarrow9x-27=0\)
\(\Rightarrow9\left(x-3\right)=0\)
\(\Rightarrow x-3=0\)
\(\Rightarrow x=3\)
f) \(25+\left(15-x\right)=30\)
\(\Rightarrow25+15-x=30\)
\(\Rightarrow40-x=30\)
\(\Rightarrow x=40-30\)
\(\Rightarrow x=10\)
g) \(43-\left(24-x\right)=20\)
\(\Rightarrow43-24+x=20\)
\(\Rightarrow19+x=20\)
\(\Rightarrow x=20-19\)
\(\Rightarrow x=1\)
h) \(2\left(x-5\right)-17=25\)
\(\Rightarrow2\left(x-5\right)=17+25\)
\(\Rightarrow x-5=21\)
\(\Rightarrow x=21+5\)
\(\Rightarrow x=26\)
i) \(3\left(x+7\right)-15=27\)
\(\Rightarrow3\left(x+7\right)=27+15\)
\(\Rightarrow x+7=14\)
\(\Rightarrow x=14-7\)
\(\Rightarrow x=7\)
j) \(15+4\left(x-2\right)=95\)
\(\Rightarrow4\left(x-2\right)=95-15\)
\(\Rightarrow4\left(x-2\right)=80\)
\(\Rightarrow x-2=20\)
\(\Rightarrow x=20+2\)
\(\Rightarrow x=22\)
k) \(20-\left(x+14\right)=5\)
\(\Rightarrow x+14=20-5\)
\(\Rightarrow x+14=15\)
\(\Rightarrow x=15-14\)
\(\Rightarrow x=1\)
l) \(14+3\left(5-x\right)=27\)
\(\Rightarrow3\left(5-x\right)=27-14\)
\(\Rightarrow3\left(5-x\right)=13\)
\(\Rightarrow5-x=\dfrac{13}{3}\)
\(\Rightarrow x=5-\dfrac{13}{3}\)
\(\Rightarrow x=\dfrac{2}{3}\)
Bài 2:
d, 43-(24-x)=20
<=>43-24+x=20
<=>19+x=20
<=>x=20-19=1
Vậy x=1
e, 20-(x+14)=5
<=> 20-x-14=5
<=>6-x=5
<=>x=6-5=1
Vậy x=1
f,15:(x-3)=3
<=> x-3=15:3=5
<=>x=5+3
<=>x=8
Vậy x=8
\(d,43-\left(24-x\right)=20\)
\(24-x=23\)
\(x=1\)
\(e,20-\left(x+14\right)=5\)
\(x+14=15\)
\(x=1\)
\(f,15:\left(x-3\right)=3\)
\(x-3=5\)
\(x=8\)
15 + 2.(x+3)+x=24
(=) 15 + 2x + 6 + x =24
(=) 3x = 24_ 15_6
(=) 3x = 3
(=) x = 1
15 + 2 . (x + 3) + x = 24
2 . (x + 3) + x = 24 - 15
2 . (x + 3) + x = 9
3x + 6 = 9
3x = 9 - 6
3x = 3
x = 3 : 3
x = 1