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\(\frac{1}{6x7}+\frac{1}{7x8}+\frac{1}{8x9}+...+\frac{1}{Xx\left(X+1\right)}=\frac{1}{9}\)
\(\frac{7-6}{6x7}+\frac{8-7}{7x8}+\frac{9-8}{8x9}+...+\frac{\left(X+1\right)-X}{Xx\left(X+1\right)}=\frac{1}{9}\)
\(\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+...+\frac{1}{X}-\frac{1}{X+1}=\frac{1}{9}\)
\(\frac{1}{6}-\frac{1}{X+1}=\frac{1}{9}\)
\(\frac{1}{X+1}=\frac{1}{6}-\frac{1}{9}=\frac{1}{18}\)
X+1=18
X=17

a)\(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}+\frac{1}{72}+\frac{1}{90}+x=\frac{3}{5}\)
\(\Rightarrow\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}+x=\frac{3}{5}\)
\(\Rightarrow\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}+x=\frac{3}{5}\)
\(\Rightarrow\frac{1}{2}-\frac{1}{10}+x=\frac{3}{5}\)
\(\Rightarrow\frac{2}{5}+x=\frac{3}{5}\)
\(\Rightarrow x=\frac{3}{5}-\frac{2}{5}=\frac{1}{5}\)
b)\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{13.15}+x=\frac{1}{3}\)
\(\Rightarrow\frac{2}{3}-\frac{2}{5}+\frac{2}{5}-\frac{2}{7}+...+\frac{2}{13}-\frac{2}{15}+x=\frac{1}{3}\)
\(\Rightarrow\frac{2}{3}-\frac{2}{15}+x=\frac{1}{3}\)
\(\Rightarrow\frac{8}{15}+x=\frac{1}{3}\)
\(\Rightarrow x=\frac{1}{3}-\frac{8}{15}=-\frac{1}{5}\)
c)\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{x\left(x+1\right)}=\frac{9}{10}\)
\(\Rightarrow\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x\left(x+1\right)}=\frac{9}{10}\)
\(\Rightarrow\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{9}{10}\)
\(\Rightarrow\frac{1}{1}-\frac{1}{x+1}=\frac{9}{10}\)
\(\Leftrightarrow\frac{x+1-1}{x+1}=\frac{9}{10}\)
\(\Rightarrow\frac{x}{x+1}=\frac{9}{10}\)
\(\Rightarrow x=9\)
b) \(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{13.15}+x=\frac{1}{3}\)
\(\Leftrightarrow\frac{5-3}{3.5}+\frac{7-5}{5.7}+...+\frac{15-13}{13.15}+x=\frac{1}{3}\)
\(\Leftrightarrow\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{15}+x=\frac{1}{3}\)
\(\Leftrightarrow\frac{1}{3}-\frac{1}{15}+x=\frac{1}{3}\)
\(\Leftrightarrow x=\frac{1}{15}\)

a)12,8 x 195 + 12,8 x 804 + 12,8
= 12,8 x (195+804+1)
=12,8 x 1000
=12800
a) = 12,8 \(\times\) ( 195 + 804 +1)
= 12,8 \(\times\) 1000
= 1280
b) = \(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{9\times10}\)
= \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\)
= 1 - \(\frac{1}{10}\)
= \(\frac{9}{10}\)

a) 42 x 43 + 42 x 56 + 42 = 42 x (43 + 56 + 1) = 42 x 100 = 4200
b) 48 x 8 + 42 x 8 + 8 x 10 = 8 x (48 + 42 + 10) = 8 x 100 = 800
a) 42 x 43 + 42 x 56 + 42
= 42 x 43 + 42 x 56 + 42 x 1
= 42 x ( 43 + 56 + 1 )
= 42 x ( 99 + 1 )
= 42 x 100
= 4200
b) 48 x 8 + 42 x 8 + 8 x10
= 8 x ( 48 + 42 + 10 )
= 8 x ( 90 + 10 )
= 8 x 100
= 800

rút gọn thành
1/2 x 2/3 x 3/4 x 4/5 x 5/6 x 6/7 x 7/8 x 8/9
1x2x3x4x5x6x7x8
__________________
2x3x4x5x6x7x8x9
gạch các số giống nhau ở tử và mẫu và bằng 1/9

\(\left(x+\frac{1}{20}\right)+\left(x+\frac{1}{30}\right)+\left(x+\frac{1}{42}\right)+\left(x+\frac{1}{56}\right)=\frac{1}{8}\)
Ta mở ngoặc rồi tính như sau:
\(x+\frac{1}{20}+x+\frac{1}{30}+x+\frac{1}{42}+x+\frac{1}{56}=\frac{1}{8}\)
\(\Leftrightarrow4x+\left(\frac{1}{20}+\frac{1}{30}+\frac{1}{42}+\frac{1}{56}\right)=\frac{1}{8}\)
\(\Leftrightarrow4x+\frac{1}{8}=\frac{1}{8}\)
\(\Leftrightarrow4x=0\)
Vậy \(x=0\)
x=12.56/42
x=16
K nhé ae
Bài làm
\(\frac{12}{x}=\frac{42}{56}\)
\(\Rightarrow x=\frac{12.56}{42}\)
\(\Rightarrow x=\frac{672}{42}\)
\(\Rightarrow x=16\)
Vậy \(x=16\)
# Học tốt #