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( 8x + 89 ) - 5x = 112 + 132
8x + 89 - 5x = 121 + 169
( 8x - 5x ) + 89 = 290
3x + 89 = 290
3x = 290 - 89
3x = 201
x = 201 : 3
x = 67
Vậy x = 67
\(\left(12x-4^3\right).8^3=4.8^4\)
\(12x-4^3=4.8^4:8^3\)
\(12x-64=4.8\)
\(12x-64=32\)
\(12x=32+64=96\)
\(x=96:12=8\)
Vậy x=8
\(b.\left(\left(4x+28\right).3+55\right):5=35\)
\(\left(4x+28\right).3+55=35\times5\)
\(\left(4x+28\right).3+55=175\)
\(\left(4x+28\right).3=175-55\)
\(\left(4x+28\right).3=120\)
\(4x+28=120:3=40\)
\(4x=40-28=12\)
\(x=12:4=3\)
Vậy x=3
\(c.720:\left(41-\left(2x-5\right)\right)=2^3.5\)
\(720:\left(41-\left(2x-5\right)\right)=40\)
\(41-\left(2x-5\right)=720:40=18\)
\(2x-5=41-18=23\)
\(2x=23+5=28\)
\(x=28:2=14\)
Vậy x=14
\(d.\left(3x-2^4\right).7^3=2.7^4\)
\(\left(3x-16\right).7^3=2.7^4\)
\(3x-16=2.7^4:7^3\)
\(3x-16=2.7=14\)
\(3x=14+16=30\)
\(x=30:3=10\)
Vậy x=10
Nhớ k cho mình nhé! Thank you!!!
\(\left(x-5\right).4=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-5=0\\4=0\left(ktm\right)\end{cases}\Leftrightarrow\orbr{\begin{cases}x=5\\4=0\left(ktm\right)\end{cases}}}\)
vậy x=5
\(8x-4x=1208\)
\(x\left(8-4\right)=1208\)
\(x4=1208\)
\(\Rightarrow x=1208:4=302\)
\(\left(x-4\right)\left(x-3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-4=0\\x-3=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=4\\x=3\end{cases}}}\)
vậy x=4 hoặc x=3
a) (4x - 1)2 = 25.9
=> (4x - 1)2 = 52 . 32 = 152
=> 4x - 1 = 15
=> 4x = 16
=> x = 4
b) 2x + 2x+3 = 144
=> 2x + 2x . 23 = 144
=> 2x (1 + 23) = 144
=> 2x . 9 = 144
=> 2x = 16
=> x = 4
c) đề chắc chắn đúng chứ :v
d) (2x + 1)3 - 12 = 15
=> (2x + 1)3 = 27
=> (2x + 1)3 = 33
=> 2x + 1 = 3 => 2x = 2 => x = 1
2. 2x = 16 => 2x = 24 => x = 4
3x = 81 => 3x = 34 => x = 4
x3 = 64 => x3 = 43 => x = 4
x2 =81 => x2 = 92 => x = 9
\(2^{10}.2^{x+4}=64^5\)
\(\Leftrightarrow2^{x+14}=2^{30}\)
\(\Leftrightarrow x+14=30\)
\(\Leftrightarrow x=16\)
\(5^x+5^{x+3}=630\)
\(\Rightarrow5^x.1+5^x.125=630\)
\(\Rightarrow5^x.126=630\)
\(\Rightarrow5^x=5\)
\(\Rightarrow x=1\)
\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+..............+\left(x+100\right)=7450\)
\(\Rightarrow\left(x+x+x+x+.........+x\right)+\left(1+2+3+..........+100\right)=7450\)
\(101x+5050=7450\)
Đến đây tự tính
a/ 2x . 7 = 224
2x = 224 : 7
2x = 32
2x = 25
x = 5.
b/ 32x + 1 . 11 = 2673
32x + 1 = 2673 : 11
32x + 1 = 243
32x + 1 = 35
32x = 35 - 1
32x = 34
2x = 4
x = 4 : 2
x = 2.
c/ (3x + 5)2 = 289
(3x + 5)2 = 172
3x + 5 = 17
3x = 17 - 5
3x = 12
x = 12 : 3
x = 4.
d/ x . (x2)3 = x5
x1 . x5 = x5
x6 = x5
=> x = 0 hoặc x = 1
a) 2x x 7=224
2x=224:7
2x=32
2x=25
=> x=5
Vậy x=5
b) 32x+1 x 11=2673
32x+1=2673:11
32x+1=243
32x+1=35
=> 2x+1=5
x=(5-1):2
x=2
Vậy x=2
c) (3*x+5)2=289
(3*x+5)2=172
=> 3*x+5=17
x=(17-5):3
x=4
Vậy x=4
d) x.(x2)3=x5
x.x6=x5
x=x5:x6
x=x-1
(556)2 x (559)5 = 556x2 x 559x5 = 5512 x 5545 = 5547
100010 x 100056 = 100076
55095 x 5505 =550100
1. 179 - ( 55 + 2x ) = 64
( 55 +2x) = 179 - 64
55 + 2x = 115
2x = 115 - 55
2x = 60
x = 30