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a) ta có: \(-6x=18\)
\(\Rightarrow x=\frac{18}{-6}\)
\(\Rightarrow x=-3\)
b) ta có: \(2x-\left(-3\right)=7\)
\(\Rightarrow2x+3=7\)
\(\Rightarrow2x=7-3\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=2\)
c) ta có: \(\left(x-5\right)\left(x+6\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-5=0\\x+6=0\end{cases}\Rightarrow\orbr{\begin{cases}x=5\\x=-6\end{cases}}}\)
Vậy....
hok tốt!!
\(a,-6x=18\)
<=>\(x=18:\left(-6\right)\)
<=>\(x=-3\)
\(b,2x-\left(-3\right)=7\)
<=>\(2x+3=7\)
<=>\(2x=4\)
<=>\(x=2\)
\(c,\left(x-5\right)\left(x+6\right)=0\)
<=>\(\orbr{\begin{cases}x-5=0\\x+6=0\end{cases}}\)
<=>\(\orbr{\begin{cases}x=5\\x=-6\end{cases}}\)
a. -6x=18
\(\Rightarrow x=18:\left(-6\right)\)
\(\Rightarrow x=-3\)
Vậy x=-3
b,2x-(-3)=7
\(\Rightarrow2x=7+\left(-3\right)\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=4:2\)
\(\Rightarrow x=2\)
Vậy x=2
c,(x-5)(x+6)=0
\(\Rightarrow\orbr{\begin{cases}x-5=0\\x+6=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0+5\\x=0-6\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x=-6\end{cases}}\)
Vậy \(\orbr{\begin{cases}x=5\\x=-6\end{cases}}\)
a, 7\(x\).(\(x\) - 10) = 0
\(\left[{}\begin{matrix}7x=0\\x-10=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=0\\x=10\end{matrix}\right.\)
Vậy \(x\in\) {0; 10}
b, 17.(3\(x\) - 6).(2\(x\) - 18) = 0
\(\left[{}\begin{matrix}3x-6=0\\2x-18=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}3x=6\\2x-18=0\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=6:3\\x=18:2\end{matrix}\right.\)
\(\left[{}\begin{matrix}x=2\\x=9\end{matrix}\right.\)
d) |2x – 5| –7 = 22
| 2x -5 | = 22+7
| 2x -5 | = 29
TH1: 2x-5 = -29
2x = -29+5
2x= -24
x= -24:2
x= -12
TH2: 2x -5 =29
2x = 29+5
2x= 34
x= 34:2
x= 17
Vậy...
a, (2\(x\) -5) + 17 = 6
2\(x\) - 5 = 6 - 17
2\(x\) - 5 = - 11
2\(x\) = - 11 + 5
2\(x\) = -6
\(x\) = -3
b, (-18).\(x\) = - 36
\(x\) = -36 : (-18)
\(x\) = 2
c, 15 - (-11\(x\) - 7) = -22
- 11\(x\) - 7 = 15 + 22
-11\(x\) - 7 = 37
11\(x\) = -37 - 7
11\(x\) = - 44
\(x\) = - 4
a) \(\left(2x-5\right)+17=6\Rightarrow2x-5=-11\Rightarrow2x=-6\Rightarrow x=-3\)
b) \(\left(-18\right)x=-36\Rightarrow x=\left(-36\right):\left(-18\right)=2\)
c) \(15-\left(-11x-7\right)=-22\)
\(\Rightarrow15+11x+7=-22\)
\(\Rightarrow11x=-22-7-15\)
\(\Rightarrow11x=-44\)
\(\Rightarrow x=-44:11=-4\)
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\(a,-6x=18\)
\(=>x=\frac{18}{-6}=-3\)
\(b,2x-\left(-3\right)=7\)
\(=>2x+3=7\)
\(=>2x=7-3=4\)
\(=>x=\frac{4}{2}=2\)
\(c,\left(x-5\right)\left(x-6\right)=0\)
\(=>\orbr{\begin{cases}x=5\\x=6\end{cases}}\)