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Ko biết ##########################################################
a) n = 32 x (132 - 247) - 132 x (32 - 247)
n = 32 x 132 - 32 x 247 - 132 x 32 - 132 x 247
n = 32 x (132 - 247 - 132) - 132 x 247
n = 32 x (-247) - 132 x 247
n = 32 x (-247) - (-132) x (-247)
n = 32 x (-247) + 132 x (-247)
n = (-247) x (32 + 132)
n = (-247) x 164
n = -40508
b) 3n + 6 \(⋮\)n + 1
=> (3n + 1) + 5 \(⋮\)n + 1
=> 5 \(⋮\)n + 1
=> n + 1 \(\in\)Ư(5) = {1;5}
=> n \(\in\){0;4}
Ta có: n = 32.132-32.247-132.32+132.247
= 32.132-132.32-32.247+132.247
= 0+247(132-32)
= 247.100
= 24700
a, \(3\frac{12}{13}< x\frac{12}{13}< 5\frac{12}{13}\Rightarrow x=4\)
b, \(x\frac{3}{4}=\frac{21989}{7996}=\frac{11}{4}=2\frac{3}{4}\Rightarrow x=2\)
~ Hok tốt ~
a: =>41-(2x-5)=720:40=18
=>2x-5=23
=>2x=28
=>x=14
b: =>100x+5050=5750
=>100x=700
=>x=7
a: =>41-(2x-5)=720:40=18
=>2x-5=23
=>2x=28
=>x=14
b: =>100x+5050=5750
=>100x=700
=>x=7
Bài 2:
\(\Leftrightarrow5a+14\in\left\{2;3;5;7;11;13;17;19;23;29;31;37\right\}\)
\(\Leftrightarrow5a\in\left\{5;15\right\}\)
hay a=3(vì a là số nguyên tố)
\(\Rightarrow41-\left(2x+5\right)=18\)
\(\Rightarrow2x+5=23\)
\(\Rightarrow2x=18\)
\(\Rightarrow x=9\)
a)
720 : (x - 17) = 12
x – 17 = 60
x = 60 + 17
x = 77
b)
(x - 28) : 12 = 8
x – 28 = 8 . 12
x – 28 = 96
x = 124
c)
26 + 8x = 6x + 46
8x – 6x = 46 – 26
2x == 20
x = 10
d)
3600 : [(5x + 335) : x] = 50
(5x + 335) : x = 72
5x + 335 = 72x
67x = 335
x = 5
a) 58.57+58.150-58.125
=58.(57+150-125)
=58. 82
= 4756
b)32.5-22.7+83.20190
=9.5-4.7+83
=45-28+83
=100
c)2019+(-247)+(-53)-2019
=(2019-2019)+[ (-247)+(-53)]
0+(-300)
= -300
d)13.70-50 [(19-32):2+23]
=13.70-50[10:2+8]
=13.70-50.13
=13.(70-50)
=13.20
=260
2.
a)x-36:18=12-5
x-36:18=6
x-36=6.18
x-36=108
x=108+36
x= 144
b)92-(17+x)=72
17+x=92-72
17+x=20
x=20-17
x=3
c)720:[41-(2x+5)]=40
41-(2x+5)=720:40
41-(2x+5)= 18
2x+5=41-18
2x+5=23
2x=23-5
2x=18
x=18:2
x=9
d) (x+2)3 -23=41
(x+2)3 =41+23
(x+2)3 =64
=> (x+2)3 =43
=>x+2=4
=>x=4-2
=>x=2
12987 -x- [(-720) + 1247 - 247] = 12987
\(\Leftrightarrow\text{12987 -x- [280] = 12987}\)
\(\Leftrightarrow-x-280=0\Leftrightarrow x=-280\)