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Ta thấy trong 3 số thì số B là nhỏ nhất
B kém A 10 lần
B kém C 100 lần
Tổng A+B+ C = 100 x B+ B + 10 x B = 111 x B = 221,778
B= 1,998 nên số A là 19,98
số C là: 199,8
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B kém A 10 lần
B kém C 100 lần
A 10 phần ; C 100 phần ; B 1 phần
tổng số phần bằng nhau : 100 + 10 + 1 = 111 phần
số thập phân A là : 221,778 : 111 x 10 = 19,98
Bước 1: Đặt các biểu thức toán học
- Gọi A là số thập phân cần tìm.
- Khi chuyển dấu phẩy sang trái một hàng, ta được B = A ÷ 10.
- Khi chuyển dấu phẩy sang phải một hàng, ta được C = A × 10.
- Tổng của ba số được cho:
[ A + B + C = 221,778 ]
Bước 2: Biến đổi phương trình
Thay B và C vào phương trình:
[ A + \frac{A}{10} + 10A = 221,778 ]
Bước 3: Quy đồng mẫu số và thu gọn biểu thức
Đưa về mẫu số chung là 10:
[ \frac{10A}{10} + \frac{A}{10} + \frac{100A}{10} = 221,778 ]
[ \frac{111A}{10} = 221,778 ]
Bước 4: Giải A
Nhân hai vế với 10:
[ 111A = 2217,78 ]
Chia hai vế cho 111:
[ A = \frac{2217,78}{111} = 19,98 ]
Kết quả
Vậy số thập phân A = 19,98.
Vì nếu chuyển dấu phẩy của nó sang bên trái 1 hàng thì số đó giảm đi 10 lần
Và nếu chuyển chuyển dấu phẩy của nó sang bên phải 1 hàng thì số đó tăng thêm 10 lần
ta có sơ đồ bn tự vẽ nha,số A là 10 phần,số B là 1 phần và số C là 100 phần
Tổng số phần bằng nhau là : 1+10+100=111(phần)
Số A là :221,778 : 111 x 10 = 19,98
Đ/S:19,98
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Số A, B,C số nào nhỏ nhất
Đúng rồi số B
B kém A 10 lần
B kém C 100 lần
Tổng A+B+ C = 100XB+ B + 10XB = 111XB = 221,778
B= 1,998 sÔ A LÀ 19,98