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\(=81.53+19.\left(28+25\right)\)
\(=81.53+19.53\)
\(=\left(81+19\right).53\)
\(=100.53\)
\(=5300\)
81*53+19*28+19*25
=81*53+19*(28+25)
=81*53+19*53
=53*(81+19)
=53*100
=5300

=>3C=1.2.3+2.3.3+...+99.100.3
= 1.2.(3 - 0) + 2.3.(4 - 1) +...+ 99.100.(101 - 98)
= 1.2.3 - 0.1.2 + 2.3.4 - 1.2.3 +...+ 99.100.101 - 98.99.100
= 99.100.101
=>\(C=\frac{99.100.101}{3}=333300\)
\(C = 1.2+2.3+3.4+...+99.100\)
\(\Rightarrow3C=1.2.3+2.3.3+3.4.3+...+99.100.3\)
\(3C=1.2.\left(3-0\right)+2.3.\left(4-1\right)+3.4.\left(5-2\right)+...+99.100.\)\(\left(101-98\right)\)
\(3C=\left(1.2.3+2.3.4+3.4.5+...+99.100.101\right)\)\(-\left(0.1.2+1.2.3+2.3.4+...+98.99.100\right)\)
\(3C=99.100.101-0.1.2\)
\(3C=999900-0=999900\)
\(C=999900:3\)
\(\Rightarrow C=333300\)

\(\frac{15\cdot12-15}{12-27}\)
\(=\frac{15\left[12-1\right]}{12-27}\)
\(=\frac{15\cdot11}{12-27}=\frac{3\cdot5\cdot1\cdot11}{3\cdot4-3\cdot9}=\frac{3\cdot5\cdot1\cdot11}{3\left[4-9\right]}=\frac{3\cdot5\cdot1\cdot11}{3\cdot(-5)}=\frac{5\cdot1\cdot11}{-5}=\frac{1\cdot1\cdot11}{-1}=-11\)

\(126+\left(-20\right)+|124|-\left(-320\right)-|-150|\)
\(=126-20+124+320-150\)
\(=\left(126+124\right)+\left(320-20\right)-150\)
\(=250-150+300=100+300=400\)
\(126+\left(-20\right)+|124|-\left(-320\right)-|-150|\)
=126-20+124+320-150
=(126+124)+(320-150-20)
=250+150
=400


\(=\left[2^{10}\left(18+14\right)\right]:2^{13}\)
\(=\left[2^{10}.32\right]:2^{13}\)
\(=\left[2^{10}.2^5\right]:2^{13}\)
\(=2^{15}:2^{13}\)
\(=2^2\)
\(=4\)
VI + XXVII = 6 + 27 = 33 = XXXIII
VI = 6
XXVI = 26
26x6=156
các bạn cho mk vài li-ke cho tròn 730 với