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C
10 tháng 12 2023
1) 5 + (-4) = 1
2) (-8) + 2 = -6
3) 8 + (-2) = 6
4) 11 + (-3) = 8
5) (-11) + 2 = -9
6) (-7) + 3 = -4
7) (-5) + 5 = 0
8) 11 + (-12) = -1
9) (-18) + 20 = 2
10) (15) + (-12) = 3
11) (-17) + 17 = 0
12) 16 + (-2) = 14
13) (30) + (-14) = 16
14) (-19) + 20 = 1
15) (-18) + 15 = -3
16) (10) + (-6) = 4
17) (-28) + 14 = -14
18) 15 + (-30) = -15
19) (15) + (-4) = 11
20) (-21) + 11 = -10
21) 8 + (-22) = -14
22) (-15) + 4 = -11
23) (-3) + 2 = -1
24) 17 + (-14) = 3
25) 17 + (-14) = 3
LK
0
DN
3
A
19 tháng 1 2022
1, 3/5 + -4/15 = \(\dfrac{9}{15}\)+ \(\dfrac{-4}{15}\)= \(\dfrac{5}{15}\)= \(\dfrac{1}{3}\)
2, -1/3 + 2/5 + 2/15= \(\dfrac{-5}{15}+\dfrac{6}{15}+\dfrac{2}{15}\)=\(\dfrac{3}{15}=\dfrac{1}{5}\)
3, -3/5 + 7/21 + -4/5 + 7/5= \(\dfrac{1}{3}\)
19 tháng 1 2022
\(1.\dfrac{3}{5}+\dfrac{-4}{15}=\dfrac{9}{15}+\dfrac{-4}{15}=\dfrac{5}{15}=\dfrac{1}{3}\)
\(2.\dfrac{-1}{3}+\dfrac{2}{5}+\dfrac{2}{15}=\dfrac{-5}{15}+\dfrac{6}{15}+\dfrac{2}{15}=\dfrac{3}{15}=\dfrac{1}{5}\)
\(3.\dfrac{-3}{5}+\dfrac{7}{21}+\dfrac{-4}{5}+\dfrac{7}{5}=\left(\dfrac{-3}{5}+\dfrac{-4}{5}+\dfrac{7}{5}\right)+\dfrac{7}{21}=0+\dfrac{7}{21}=\dfrac{1}{3}\)
DN
2
NV
0
16 tháng 12 2023
a: \(2\cdot25\cdot4\cdot50\)
\(=\left(2\cdot50\right)\cdot\left(25\cdot4\right)\)
\(=100\cdot100=10000\)
b: \(\left(-125\right)\cdot5\cdot\left(-16\right)\cdot\left(-8\right)\)
\(=-125\cdot5\cdot16\cdot8\)
\(=-\left(125\cdot8\right)\cdot\left(5\cdot16\right)\)
\(=-80\cdot1000=-80000\)
c: \(5^2\cdot3^3\cdot2\)
\(=25\cdot27\cdot2\)
\(=\left(25\cdot2\right)\cdot27=27\cdot50=1350\)
d: \(\left(-4\right)\cdot3^2\left(-5\right)^3\)
\(=\left(-4\right)\cdot\left(-125\right)\cdot9\)
\(=500\cdot9=4500\)
DC
2
KN
11 tháng 4 2019
\(\frac{1}{4}.\frac{15}{49}-\left(\frac{4}{5}+\frac{2}{3}\right)\div3\frac{2}{3}\)
\(=\frac{15}{196}-\left(\frac{12}{15}+\frac{10}{15}\right)\div\frac{11}{3}\)
\(=\frac{15}{196}-\left(\frac{12}{15}+\frac{10}{15}\right).\frac{3}{11}\)
\(=\frac{15}{196}-\frac{22}{15}.\frac{3}{11}\)
\(=\frac{15}{196}-\frac{2}{5}.\frac{1}{1}\)
\(=\frac{15}{196}-\frac{2}{5}\)
\(=\frac{75}{980}-\frac{392}{980}=\frac{-317}{980}\)
BA
11 tháng 4 2019
\(\frac{1}{4}\cdot\frac{15}{49}-\left(\frac{4}{5}+\frac{2}{3}\right):3\frac{2}{3}\)
\(=\frac{15}{196}-\frac{22}{15}\cdot\frac{3}{11}\)
\(=\frac{15}{196}-\frac{2}{5}\)
\(=-\frac{317}{980}\)
HT
3
VN
20 tháng 1 2023
a)
\(11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)
\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)
\(=\dfrac{146}{13}-\dfrac{18}{7}-\dfrac{68}{13}\)
\(=\left(\dfrac{146}{13}-\dfrac{68}{13}\right)-\dfrac{18}{7}\)
\(=6-\dfrac{18}{7}\)
\(=\dfrac{24}{7}\)
b)
\(\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)
\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)
\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)
\(=\dfrac{2}{7}\times2\)
\(=\dfrac{4}{7}\)
Y
20 tháng 1 2023
\(a,11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)
\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)
\(=\dfrac{146}{13}-\dfrac{68}{13}-\dfrac{18}{7}\)
\(=6-\dfrac{18}{7}\)
\(=\dfrac{24}{7}\)
\(b,\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)
\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)
\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)
\(=\dfrac{2}{7}\times2\)
\(=\dfrac{4}{7}\)
− 3 2 + 2 3 − − 5 2 + 4 3 = 9 + 8 – 25 + 64 = 56