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20 – [30 – (5 – 1)2] = 20 – (30 – 42) = 20 – (30 – 16) = 20 – 14 = 6
\(a.20-\left[30-\left(5-1\right)^2\right]\) \(b.75-\left(3.5^2-4.2^3\right)\)
\(=20-\left[30-4^2\right]\) \(=75-\left(75-4.2^3\right)\)
\(=20-14=6\) \(=75-\left(75-32\right)\)
\(=75-43=32\)
1: \(78+22+18\)
\(=\left(78+22\right)+18\)
=100+18
=118
2: \(94+563+\left(106-563\right)-\left(-70\right)\)
\(=94+563+106-563+70\)
\(=\left(94+106\right)-\left(563-563\right)+70\)
=100-0+70
=170
3: \(25\cdot154-25+47\cdot25\)
\(=25\left(154-1+47\right)\)
\(=25\cdot200=5000\)
4: \(\left[5^{29}+5^{30}\left(16-11\right)\right]:5^{29}\)
\(=\left(5^{29}+5^{30}\cdot5\right):5^{29}\)
\(=\dfrac{5^{29}\cdot1+5^{29}\cdot5^2}{5^{29}}\)
\(=1+5^2=26\)
8: \(25\cdot2^3-\left(9-14\right)+\left(29-34+20\right)\)
\(=25\cdot8-\left(-5\right)+\left(-5\right)+20\)
\(=200+5-5+20\)
=220
c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)
\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)
\(=1-2=-1\)
Giải:
a)-1/12+4/3=-1/12+16/12=15/12=5/4
b)(-4/14-3/15)-(1/5-20/35-(-1)).7
=-17/35-22/35.7
=-17/35-22/5
=-171/35
c)3/5+-5/20+30/75+-7/4
=3/5+-1/4+2/5+-7/4
=(3/5+2/5)+(-1/4+-7/4)
=1+-2
=-1
d)5/6.-12/14+7/13
=-5/7+7/13
=-16/91
e)2/-9-5/-36-1/4
=-1/12-1/4
=-1/3
f)2/23+-5/12+7/18+21/23+-7/12
=(2/23+21/23)+(-5/12+-7/12)+7/18
=1+-1+7/18
=7/18
a ) 5 ^30 : ( 5^25 . 6 + 5^25 . 9 )
= 5^30 : [ 5^25 ( 6 + 9 ) ]
= 5^30 : [ 5^25 . 15 ]
= 5^30 : [ 5^25 . 5 . 3 ]
= 5^30 : [ 5^26 . 3 ]
= 5^30 : 5^26 : 3
= 5^4 : 3
b ) ( 20 . 2^4 + 12 . 2^4 - 48 . 2^2 ) : 8^2
= ( 20 . 2^4 + 12.2^4 - 12 . 2^2 . 2^2 ) : 8^2
= ( 20 . 2^4 + 12.2^4 - 12.2^4 ) : 8^2
= 20 . 2^4 : 8^2
= 5 . 2^2 . 2^4 : ( 2^3 )^2
= 5 . 2^6 : 2^6
= 5
= 625 : 3
= 625/3
a, 3 . 5 2 - 16 : 2 2 = 3.25 - 16:4 = 75 - 4 = 71
b, 15.141 + 59.15 = 15.(141+59) = 15.200 = 3000
c, 2 3 . 17 - 2 3 . 14 = 8.17 - 8.14 = 8.(17 - 14) = 8.3 = 24
d, 20 - 30 - 5 - 1 2 = 20 - 30 - 4 2 = 20 - (30 - 16) = 20 - 14 = 6
BÀI CỦA MÌNH LÀM LÀ :
20 - [30 - ( 5 -1 ) 2 ]
= 20 - [ 30 - 42 ]
= 20 - 14
= 6