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a) \(\frac{120}{115}-1=\frac{5}{115}\) ; \(1-\frac{175}{170}=\frac{5}{170}\)
Vì \(\frac{5}{115}>\frac{5}{170}\) nên \(\frac{120}{115}<\frac{175}{170}\)
\(42+\frac{93}{6}+\frac{87}{12}+\frac{79}{20}+\frac{69}{30}+\frac{57}{42}\)
\(=37+\left(1+\frac{93}{6}\right)+\left(1+\frac{87}{12}\right)+\left(\frac{79}{20}+1\right)+\left(1+\frac{69}{30}\right)+\left(1+\frac{57}{42}\right)\)
\(=37+\frac{99}{6}+\frac{99}{12}+\frac{99}{20}+\frac{99}{30}+\frac{99}{42}\)
\(=37+99\left(\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\right)\)
\(=37+99\left(\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\right)\)
\(=37+99\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)
\(=37+99\left(\frac{1}{2}-\frac{1}{7}\right)\)
\(=37+99.\frac{5}{14}\)
\(=37+35\frac{5}{14}\)
\(=72\frac{5}{14}\)
Tính nhanh:
29 x 87 - 29 x 23 + 64 x 71
= 29 x ( 87 - 23 ) + 64 x 71
= 29 x 64 + 64 x 71
= 64 x ( 29 + 71 )
= 64 x 100
= 6400
So sánh:
333^444 và 444^333
Ta có: 333^444 = 111^444 x 3^444
444^333 = 111^333 x 4^333
Tách: 3^444 = (3^4)^111 =81^111 <=>4^333 = (4^3)^111 = 64^111
Mà: {111^444 > 111^333 (1)
{81^111 > 64^111 hay: (3^4)^111 > (4^3)^111 (2)
Từ (1) và (2) ta có:333^444 > 444^333
29 x 87 - 29 x 23 + 64 x 71
= 29 x ( 87 - 23 ) + 64 x 71
= 29 x 64 + 64 x 71
= 64 x ( 29 + 71 )
= 64 x 100
= 6400
\(333^{444}=\left(111.3^4\right)^{111}=\left(111.81\right)^{111}\)
\(444^{333}=\left(111.4^3\right)^{111}=\left(111.64\right)^{111}\)
Do \(111.81>111.64\)
\(\Rightarrow\left(111.81\right)^{111}>\left(111.64\right)^{111}\)
\(\Leftrightarrow333^{444}>444^{333}\)
a) 15 . 23 + 4. 23 - 5.7
= 15 . 8 + 4.8 - 35
= 120 + 32 - 35
= 152 - 35
= 117
b) 49 . 213+ 87. 72
=49.213+ 87. 49
=10437 + 4263
= 14700
c) 20+21+22+23+24+25+26+27+28+29+30
d) 56 : 53 + 3 . 32
= 56 : 53 + 3. 9
=53 + 27
= 125+ 27
= 152
e) 2 . 325 . 12 + 4 . 69 . 24 + 3 . 399 . 8
= 7800+ (6624+ 9576)
=7800+ 16200
= 24000
e, Ta có:
\(9^{20}=3^{40}\)
\(27^{13}=3^{39}\)
Vì \(\hept{\begin{cases}3=3\\40>39\end{cases}\Rightarrow}3^{40}>3^{39}\)
Vậy 920>2713
Ta có:
\(A=\frac{20^{10}+1}{20^{10}-1}=1\)
\(B=\frac{20^{10}-1}{20^{10}-3}=1\)
Vậy A và B bằng nhau
Tính A và B rồi ta so sánh:
A = \(\frac{20^{10}+1}{20^{10}-1}\) = \(1\)
B = \(\frac{20^{10}-1}{20^{10}-3}\) = \(1\)
Mà \(1\) = \(1\)
Nên: A = B
a ) 87 . ( − 2 0 ) < | 87 . ( − 2 0 ) |
b ) 87 . ( − 2 0 ) = 87 . ( − 2 0 )
c ) 87 . ( − 2 0 ) = − | − 87 . 2 0 |