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c) Ta có \(125^{80}=\left(5^3\right)^{80}=5^{240}\)
\(25^{118}=\left(5^2\right)^{118}=5^{236}\)
vì \(240>236\) nên \(5^{240}>5^{236}\)
\(\Rightarrow125^{80}>25^{118}\)
a/ \(2A=2+2^2+2^3+2^4+...+2^{2011}\)
\(A=2A-A=2^{2011}-2^0=2^{2011}-1=B\)
b/ \(A=2009.2011=\left(2010-1\right)\left(2010+1\right)=2010^2-1< B=2010^2\)
c/
\(5^{36}=\left(5^3\right)^{12}=125^{12}\)
\(11^{24}=\left(11^2\right)^{12}=121^{12}\)
\(\Rightarrow11^{24}=121^{12}< 125^{12}=5^{36}\)
d/
\(625^5=\left(5^4\right)^5=5^{20}\)
\(125^7=\left(5^3\right)^7=5^{21}>5^{20}=625^5\)
e/
\(3^{2n}=\left(3^2\right)^n=9^n\)
\(2^{3n}=\left(2^3\right)^n=8^n< 9^n=3^{2n}\)
f/
\(6.5^{22}>5.5^{22}=5^{23}\)
g/
\(333^{444}=\left(3.111\right)^{444}=3^{444}.111^{444}=\left(3^4\right)^{111}.111^{444}=81^{111}.111^{444}\)
\(444^{333}=\left(4.111\right)^{333}=4^{333}.111^{333}=\left(4^3\right)^{111}.111^{333}=64^{111}.111^{333}\)
\(\Rightarrow333^{444}>444^{333}\)
5\(^{300}\)=25\(^{150}\)
3\(^{453}\)=27\(^{151}\)=27.27\(^{150}\)
vì 25\(^{150}\)<27.27\(^{150}\)
\(\Rightarrow\)5\(^{300}\)<3\(^{453}\)
31\(^{11}\)<32\(^{11}\)=(2\(^5\))\(^{11}\)=2\(^{55}\)
31\(^{11}\)<2\(^{55}\)
17\(^{14}\)>16\(^{14}\)=2\(^{56}\)
31\(^{11}\)<2\(^{55}\)<2\(^{56}\)<17\(^{14}\)
\(\Rightarrow\)31\(^{11}\)<17\(^{14}\)
333\(^{444}\)=3\(^{444}\).111\(^{444}\)
444\(^{333}\)=4\(^{333}\).111\(^{333}\)
ta có 3\(^{444}\)=81\(^{111}\)
4\(^{333}\)=64\(^{111}\)
\(\Rightarrow\)3\(^{444}\)>4\(^{333}\)(81\(^{111}\)>64\(^{111}\))
111\(^{444}\)>111\(^{333}\)
3\(^{444}\).111\(^{444}\)>4\(^{333}\).111\(^{333}\)
Vậy 333\(^{444}\)>444\(^{333}\)
nảy mình làm thiếu 1 câu bây giờ bù nhá
a. 3450 = (33)150 = 27150;
5300 = (52)150 = 25150
Vì 27150 > 25150
=> 3450 > 5300.
b. 333444 = (3.111)444 = 3444.111444 =(34)111.111444=81111.111444
444333=(4.111)333=4333.111333=(43)111.111333=64111.111333
Vì 81111 > 64111 và 111444 > 111333
=> 81111.111444 > 64111.111333
=> 333444 > 444333.
c. 2014.2016
= 2014.(2015+1)
= 2014.2015+2014 (1)
20152
=2015.2015
=2015.(2014+1)
=2015.2014+2015 (2)
Từ (1) và (2) => 2014.2016 < 20152.
b) 333\(^{444}\)và 444\(^{333}\)
Ta có :333\(^{444}\)(3.111)\(^{4.111}\)=(3\(^4\).111\(^4\))\(^{111}\)=(81.111\(^4\)).111
444\(^{333}\)(4.111)\(^{3.111}\)=4\(^3\).111\(^2\))\(^{111}\)=(64.111\(^3\))\(^{111}\)
vì 81>64 ; 111\(^4\)>111\(^3\) nêb (81.111\(^4\))\(^{111}\)>(64.113\(^3\))\(^{111}\)
hay 333\(^{444}\)>444\(^{333}\)
a, 2711 = (33)11 = 333
818 = (34)8 = 332
Vì 332 < 333 => 818 < 2711
b, 12580 = (53)80 = 5240 < 251118
c, 536 = (53)12 = 12512 > 12112 = (112)12 = 1124
Đúng 100000000000000000000000000000000000000000000