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a, Ta có : \(2^{333}=\left(2^3\right)^{111}=8^{111}\)
\(3^{222}=\left(3^2\right)^{111}=9^{111}\)
Vì \(8^{111}< 9^{111}\Rightarrow2^{333}< 3^{222}\)
b, Ta có : \(9^{1005}=\left(3^2\right)^{1005}=3^{2010}\)
\(\Rightarrow3^{2009}< 9^{1005}\)
c, Ta có : \(99^{20}=\left(99^2\right)^{10}=9801^{10}\)
Vì \(9801^{10}< 9999^{10}\Rightarrow99^{20}< 9999^{10}\)
a) Ta có: \(2^{333}=\left(2^3\right)^{111}=8^{111}\)
\(3^{222}=\left(3^2\right)^{111}=9^{111}\)
Vì 9>8 nên 9111>8111
Vậy 3222>2333
b) Ta có: \(9^{1005}=\left(3^2\right)^{1005}=3^{2010}\)
Vì 2010>2009 nên 32010>32009
Vậy 91005>32009
c)Ta có:\(99^{20}=\left(99^2\right)^{10}=\left(99.99\right)^{10}\)
\(9999^{10}=\left(99.101\right)^{10}\)
Vì 99<101 nên (99.99)10<(99.101)10
Vậy 9920<999910
\(2^{333}=\left(2^3\right)^{111}=8^{111}\)
\(3^{222}=\left(3^2\right)^{111}=9^{111}\)
Có: \(8^{111}< 9^{111}\)
\(\Leftrightarrow2^{333}< 3^{222}\)
\(9^{1005}=\left(3^2\right)^{1005}=3^{2010}\)
Có: \(3^{2010}>3^{2009}\)
\(\Rightarrow9^{1005}>3^{2009}\)
\(90^{20}=\left(90^2\right)^{10}=8100^{10}\)
Có: \(8100^{10}< 9999^{10}\)
\(\Rightarrow90^{20}< 9999^{10}\)
Ta có : \(2^{333}=\left(2^3\right)^{111}=8^{111}\)
\(3^{222}=\left(3^2\right)^{111}=9^{111}\)
Do : \(8^{111}< 9^{111}\left(8< 9\right)\)
\(\Rightarrow2^{333}< 3^{222}\)
\(A,2^{333}\) và \(3^{222}\)
Ta có:
\(2^{333}=\left(2^3\right)^{111}=8^{111}\)
\(3^{222}=\left(3^2\right)^{111}=9^{111}\)
Vì 8<9 \(\Rightarrow8^{111}< 9^{111}\)
\(\Rightarrow2^{333}< 3^{222}\)
B,\(3^{2009}\) và \(9^{2005}\)
Ta có:
\(9^{2005}=\left(3^2\right)^{2005}=3^{4010}\)
Vì 2009 < 4010 \(\Rightarrow3^{2009}< 3^{4010}\)
2333=(23)111=8111
3222=(32)111=9111
Vì: 8<9 nên: 8111<9111
vậy: 2333<3222
b, 9920=(992)10=980110
Mà: 9801<9999 nên:
9920<999910
aTa có:
2333=(23)111=8111
3222=(32)111=9111
Do 8111<9111
=>2333<3222
b,Ta có:
9920=(992)10=980110
Do 980110 <999910
=>9920<999910
a) \(2^{333}=2^{3.111}=\left(2^3\right)^{111}=8^{111}\)
\(3^{222}=3^{2.111}=\left(3^2\right)^{111}=9^{111}\)
Vì \(8< 9\)\(\Rightarrow8^{111}< 9^{111}\)\(\Rightarrow2^{333}< 3^{222}\)
b) \(9^{1005}=\left(3^2\right)^{1005}=3^{2.1005}=3^{2010}>3^{2009}\)