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329 = (25)9 = 245 < 252 = (24)13=1613<1813
=> (-32)9 > (-18)13
a: \(=\left\{\left[\left(20-\dfrac{1}{4}\right)\cdot0.2\right]+\dfrac{3}{20}\right\}\cdot5:\left[\left(2+\dfrac{25}{11}\cdot\dfrac{22}{100}\cdot10\right)\cdot\dfrac{1}{33}\right]\)
\(=\left\{\left[\dfrac{79}{20}+\dfrac{3}{20}\right]\right\}\cdot5:\left[\dfrac{356}{55}\cdot\dfrac{1}{33}\right]\)
\(=\dfrac{82}{20}\cdot5:\dfrac{3856}{1815}\simeq104,516\)
b: \(=\dfrac{13}{30}+\dfrac{28}{45}\cdot\dfrac{5}{2}\cdot\left[\dfrac{5}{6}:\dfrac{53}{90}\right]\cdot\dfrac{53}{50}\)
\(=\dfrac{13}{30}+\dfrac{14}{9}\cdot\dfrac{3}{2}=\dfrac{83}{30}\)
c) \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{0,625-0,5+\frac{5}{11}+\frac{5}{12}}=\frac{3\left(0,125-0,1+\frac{1}{11}+\frac{1}{12}\right)}{5\left(0,123-0,1+\frac{1}{11}+\frac{1}{12}\right)}=\frac{3}{5}\)
1. Ta có: \(\sqrt{23}+\sqrt{15}< \sqrt{25}+\sqrt{16}=5+4=9\)
mà \(\sqrt{83}>\sqrt{81}=9\)
\(\Rightarrow\sqrt{23}+\sqrt{15}< \sqrt{83}\)
a) 63
36 = 32.3 = ( 32)3 = 93
Do 6 < 9 nên 63 < 93 hay 63 < 36
^^
(\(\frac{1}{2}\))50=(\(\frac{1}{2^5}\))10=(\(\frac{1}{32}\))10
Do 1/6> 1/30 nên (\(\frac{1}{6}\))10>(\(\frac{1}{2}\))50
\(\left(\frac{1}{2}\right)^{50}=\left[\left(\frac{1}{2}\right)^5\right]^{10}=\left[\frac{1^5}{2^5}\right]^{10}=\left[\frac{1}{32}\right]^{10}\)
Vì 2 phân số này có cùng tử mà 6 < 30
=> \(\frac{1}{6}>\frac{1}{30}\)
=> \(\left(\frac{1}{6}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)
a) ( 0,5 )6 = \(\frac{5^6}{10^6}=\left(\frac{5}{10}\right)^6=\left(\frac{1}{2}\right)^6\)
( 0,5 )9 = \(\frac{5^9}{10^9}=\left(\frac{5}{10}\right)^9=\left(\frac{1}{2}\right)^9\)
vì \(\left(\frac{1}{2}\right)^6>\left(\frac{1}{2}\right)^9\)nên \(\left(0,5\right)^6>\left(0,5\right)^9\)
b) vì ( -0,125)8 = ( 0,125 )8 = ( 0,5 )24
=> ( -0,125 )8 = ( 0,5 )24