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a: \(-\dfrac{11}{33}< 0< \dfrac{25}{16}\)
b: \(-\dfrac{17}{23}=\dfrac{-171717}{232323}\)
a) \(\frac{-8}{-70}=\frac{8}{70}\left(=\frac{4}{35}\right)\)
\(\frac{-1}{-28}=\frac{1}{28}\)
\(\frac{27}{-180}=\frac{-27}{180}\left(=\frac{-3}{20}\right)\)
b) \(\frac{18}{-45}=\frac{-18}{45}\left(=\frac{-2}{5}\right)\)
\(\frac{-151515}{252525}=\frac{-151515}{252525}\left(=\frac{-3}{5}\right)\)
\(\frac{7777}{-1111}=\frac{-7777}{1111}\left(=\frac{-7}{1}=-7\right)\)
Ta có: \(\frac{2000}{-2001}=-\frac{2000}{2001}=-\left(\frac{2001-1}{2001}\right)=-\left(\frac{2001}{2001}-\frac{1}{2001}\right)=-\left(1-\frac{1}{2001}\right)=-1+\frac{1}{2001}\)
\(-\frac{2003}{2002}=-\left(\frac{2002+1}{2002}\right)=-\left(\frac{2002}{2002}+\frac{1}{2002}\right)=-\left(1+\frac{1}{2002}\right)=-1-\frac{1}{2002}\)
Vì \(\frac{1}{2001}>-\frac{1}{2002}\) nên \(-1+\frac{1}{2001}>-1-\frac{1}{2002}\)
hay \(\frac{2000}{-2001}>-\frac{2003}{2002}\)
a) Vì \(-45< -16\) nên \(\left(-\dfrac{45}{17}\right)^{15}< \left(\dfrac{-16}{17}\right)^{15}\)
b) Vì \(21< 23\) nên \(\left(-\dfrac{8}{9}\right)^{21}< \left(-\dfrac{8}{9}\right)^{23}\)
c) \(27^{40}=3^{3^{40}}=3^{120}\)
\(64^{60}=8^{2^{60}}=8^{120}\)
Vì \(3< 8\) nên \(3^{120}< 8^{120}\) hay \(27^{40}< 64^{60}\)
con ai kooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooooo
\(-\frac{13}{15}+-\frac{2}{15}=-1;-\frac{14}{16}+-\frac{2}{16}\)
Vì \(-\frac{2}{15}< -\frac{2}{16}\Rightarrow\frac{-13}{15}< -\frac{14}{16}\)
2.Gọi 3 p/số đó là x;y;z
\(-\frac{5}{8}< x< y< z< -\frac{3}{5}\)
\(-\frac{100}{160}< x< y< z< -\frac{96}{160}\)
\(\Rightarrow x=-\frac{99}{160};y=-\frac{98}{160}=-\frac{49}{80};z=-\frac{97}{160}\)
\(-3< \frac{1}{5}\)
\(\frac{-19}{15}< \frac{999}{1000}\)
-\(\frac{-24}{50}>\frac{-49}{97}\)
\(-0,35>\frac{-15}{28}\)
KẾT BN VỚI MK NHA
\(-0,35>\frac{-15}{28}\)
a: -1/200<0<1/2000
b; -1789/1788<-1
-1<2009/-2010
=>-1789/1788<-2009/2010
d: -27/45=-3/5
-272727/454545=-3/5
=>-27/45=-272727/454545