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\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{2352}+\frac{1}{2450}\\ \)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{49.50}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{49}-\frac{1}{50}\)
\(=1-\frac{1}{50}\)
\(=\frac{49}{50}\)
\(=>S=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{48.49}+\frac{1}{49.50}\)
\(=>S=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+..+\frac{1}{48}-\frac{1}{49}+\frac{1}{49}-\frac{1}{50}=\frac{1}{1}-\frac{1}{50}=\frac{49}{50}\)
vậy S=49/50
A=1/1x2+1/2x3+1/3x4+1/4x5+1/5x6+1/6x7=1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7
A=1-1/7=6/7
=1/1.2 + 1/2.3 + 1/3.4 +1/4.5 +1/5.6 +1/6.7
=1-1/2 + 1/2 -1/3 +1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 +1/6 - 1/7
= (1-1/7)+(1/2-1/2)+(1/3-1/3) + ... +(1/6-1/6)
= (1-1/7) + 0+...+0 = 1-1/7 = 7/7 - 1/7 = 6/7
Vậy A =6/7
câu 2:
\(\frac{1}{2}+\frac{1}{6}+...+\frac{1}{2450}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{49.50}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{49}-\frac{1}{50}\)
\(=1-\frac{1}{50}\)
\(=\frac{49}{50}\)
1/2+1/6+1/12+1/20+.....+1/2352+1/2450
=1/1.2+1/2.3+1/3.4+1/4.5+.....+1/48.49+1/49.50
=1-/2+1/2-1/31/3-1/4+1/4-1/5+.....+1/48-1/49+1/49-1/50
=1-1/50
=49/50
\(G=\frac{1}{3^0}+\frac{1}{3^1}+...+\frac{1}{3^{2005}}\)\(\Rightarrow3G=3+\frac{1}{3^0}+\frac{1}{3^1}+\frac{1}{3^2}+...+\frac{1}{3^{2004}}\)
\(\Rightarrow3G-G=2G=3-\frac{1}{3^{2005}}\)\(\Rightarrow G=\frac{3-\frac{1}{3^{2005}}}{2}\)
\(Y=1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2012}}\)\(\Rightarrow2Y=2+1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{2011}}\)
\(\Rightarrow2Y-Y=2-\frac{1}{2^{2012}}\) \(\Rightarrow Y=2-\frac{1}{2^{2012}}\)
S=1/2+1/6+...............+1/2450
S=1/1.2+1/2.3+............+1/49.50
S=1-1/2+1/2-1/3+..........+1/49-1/50
S=1-1/50
S=49/50
S=1/2+1/6+...............+1/2450
S=1/1.2+1/2.3+............+1/49.50
S=1-1/2+1/2-1/3+..........+1/49-1/50
S=1-1/50
S=49/50