Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ở câu a) số mũ lúc nào cug dương mà bạn ( 45-10 = 4510). Nếu số mũ là dương thì:
a)\(\frac{45^{10}.5^{20}}{75^{15}}\)
= \(\frac{\left(3^2.5\right)^{10}.5^{20}}{\left(3.5^2\right)^{15}}\)
= \(\frac{3^{20}.5^{10}.5^{20}}{3^{15}.5^{30}}\)
= \(\frac{3^{20}.5^{30}}{3^{15}.5^{30}}\)
= \(\frac{3^5.1}{1.1}\)
= \(\frac{243}{1}\)
= 243
b)\(\frac{2^{15}.9^4}{6^6.8^2}\)
= \(\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^6.\left(2^3\right)^2}\)
= \(\frac{2^{15}.3^8}{2^6.3^6.2^6}\)
= \(\frac{2^{15}.3^8}{2^{12}.3^6}\)
= \(\frac{2^3.3^2}{1.1}\)
= \(\frac{8.9}{1}\)
= \(\frac{72}{1}\)
= 72
1) \(\frac{3^{10}+6^2}{5\cdot3^8+20}=\frac{3^{10}+3^2\cdot2^2}{5\cdot3^8+5\cdot2^2}=\frac{3^2\left(3^8+2^2\right)}{5\left(3^8+2^2\right)}=\frac{9}{5}\)
2) \(\frac{28^{15}\cdot3^{17}}{84^{16}}=\frac{28^{15}\cdot3^{17}}{28^{16}\cdot3^{16}}=\frac{3}{28}\)
a) \(\frac{25}{1188}\)
b)\(\frac{4}{3}\)
c)\(\frac{17\times4}{-17}=\frac{4}{-1}=\frac{-4}{1}=-4\)
Phân tích ra : VD : 415=(22)15=22.15=230
Nếu làm thế này thì sẽ dể hơn vì sẽ có nhiều lũy thừa giống nhau và dễ chiệt tiêu hơn nhé bạn >
Ta có:\(\frac{3^{10}\cdot\left(-5\right)\cdot21}{\left(-5\right)^{20}\cdot3^{12}}\)
\(=\frac{3^{10}\cdot\left(-5\right)\cdot21}{\left(-5\right)^{19}\cdot\left(-5\right)\cdot3^{12}}\)
\(=\frac{3\cdot7}{\left(-5\right)^{19}\cdot3^2}\)
\(=\frac{7}{\left(-5\right)^{19}\cdot3}\)
\(\frac{20.4^{15}.9^{10}-4.3^{21}.8^{10}}{10.2^{10}.6^{20}-2^{31}.27^7}\)
\(=\frac{4.5.\left(2^2\right)^{15}.\left(3^2\right)^{10}-4.3^{21}.\left(2^3\right)^{10}}{2.5.2^{10}.\left(2.3\right)^{20}-2^{31}.\left(3^3\right)^7}\)
\(=\frac{2^2.5.2^{30}.3^{20}-2^2.3^{21}.2^{30}}{2^{11}.5.2^{20}.3^{20}-2^{31}.3^{21}}\)
\(=\frac{2^{32}.5.3^{20}-2^{32}.3^{21}}{2^{31}.3^{20}.5-2^{31}.3^{21}}\)
\(=\frac{2^{32}.3^{20}.\left(5-3\right)}{2^{31}.3^{20}\left(5-3\right)}\)
\(=2\)
\(\frac{9^8.15^{20}}{6^{10}.3^{15}}\)
\(=\frac{\left(3^2\right)^8.\left(3.5\right)^{20}}{\left(2.3\right)^{10}.3^{15}}\)
\(=\frac{3^{16}.3^{20}.5^{20}}{2^{10}.3^{10}.3^{15}}\)
\(=\frac{3^{16+20}.5^{20}}{2^{10}.3^{10+15}}\)
\(=\frac{3^{36}.5^{20}}{2^{10}.3^{25}}\)
\(=\frac{3^{11}.5^{20}}{2^{10}}\)
~Study well~
#Zu
#K bt còn rút gọn đc nx hay k...
N = \(\frac{9^8.15^{20}}{6^{10}.3^{15}}\)
= \(\frac{\left(3^2\right)^8.\left(3.5\right)^{20}}{\left(3.2\right)^{10}.3^{15}}\)
= \(\frac{3^{2.8}.3^{20}.5^{20}}{3^{10}.2^{10}.3^{15}}\)
= \(\frac{3^{16}.3^{20}.5^{20}}{3^{10}.3^{15}.2^{10}}\)
= \(\frac{3^{36}.5^{20}}{3^{25}.2^{10}}\)
= \(\frac{3^{25}.3^{11}.5^{20}}{3^{25}.2^{10}}\)
= \(\frac{3^{11}.5^{20}}{2^{10}}\)