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Lời giải:
$G=(314+240+470+198)+(251-337)$
= chẵn + chẵn = chẵn
Vậy $G$ là 1 số chẵn.
Mà $G>2$ nên $G$ là hợp số.
Theo đề ta có: 9x + 11x = 4120
=> 20x = 4120
=> x = 206
Vậy phân số cần tìm là: \(\frac{9.x}{11.x}=\frac{9.206}{11.206}=\frac{1854}{2266}\)
A = 51 − 314 + 213 ; A = 51 − 314 − 213 B = 51 + 213 − 314 ; C = 51 + 314 − 213 ; D = 51 + 213 − 314 ; D = 51 + 213 − 314 E = 51 − 314 − 213 ; E = 51 − 314 + 213 F = 51 − 213 − 314. V ậ y A = F ; B = E = D
a.125-(27-75+73)
= 125 - (27 + 73 - 75)
= 125 - (100 - 75)
=125 - 25
=100
b.314-(21-86+79)
= 314 - (21 + 79 - 86)
= 314 - (100 - 86)
= 314 - 14
= 300
c.728-(211-72+89)
= 728 - (211 + 89 -72)
= 728 - (300 - 72)
= 728 - 28
= 700
d.(547-623)-(547-23)
= 547 - 623 - 547 + 23
= 547 - 547 + 23 - 623
= 0 + -600
= - 600
a)125-(27-75+73)=125-27+75-73=(125+75)-(27+73)=200-100=100. b)314-(21-86+79)=314-21+86-79=(314+86)-(21+79)=400-100=300. c) 728-(221-72+89)=(728+72)-(221+89)=800-300=500. d) (547-623)-(547-23)=547-623-547+23=(547-547)+(23-623)=0+(-600)=-600
- 314 - { - 314 - [ - 314 - ( - 314 + 1000 )]}
= - 314 - { - 314 + 314 + 314 - 1000 }
= - 314 + 314 - 314 - 314 + 1000
= [ ( - 314 ) + 314 ] + [ ( - 314 ) + 314 ] + 1000
= 0 + 0 + 1000
= 1000
\(478.615-314.678+385.478-314.322\)
\(=478.\left(615+385\right)-314.\left(678+322\right)\)
\(=478.1000-314.1000\)
\(=478000-314000\)
\(=164000\)
\(478.615-314.678+385.478-314.322\)
\(=478.615+\left(-314\right).678+385.478+\left(-314\right).322\)
\(=478.\left(615+385\right)+\left(-314\right).\left(678+322\right)\)
\(=478.1000+\left(-314\right).1000\)
\(=478000+\left(-314000\right)\)
\(=164000\)
\(284:\left[314-\left(x+3\right)\right]=12.\)
\(\Leftrightarrow\left[314-\left(x+3\right)\right]=\frac{71}{3}\)
\(\Leftrightarrow\left(x+3\right)=\frac{871}{3}\)
\(\Leftrightarrow x=\frac{862}{3}\)
\(14.\left[251-\left(x-5\right)\right]=1470\)
\(\Leftrightarrow\left[251-\left(x-5\right)\right]=105\)
\(\Leftrightarrow x-5=146\)
\(\Leftrightarrow x=151\)
\(\left(120+x\right):x-15=16\)
\(\Leftrightarrow\left(120+x\right):x=31\)
\(\Leftrightarrow\left(120+x\right).\frac{1}{x}=31\)
\(\Leftrightarrow\frac{1}{x}.x+120x=31\)
\(\Leftrightarrow1+120x=31\)
\(\Leftrightarrow120x=30\)
\(\Leftrightarrow x=4\)
\(\left(135-x\right):x+24=28\)
\(\Leftrightarrow\left(135-x\right):x=4\)
\(\Leftrightarrow\left(135-x\right).\frac{1}{x}=4\)
\(\Leftrightarrow\frac{1}{x}.135-\frac{1}{x}x=4\)
\(\Leftrightarrow\frac{1}{x}135-1=4\)
\(\Leftrightarrow\frac{1}{x}135=5\)
\(\Leftrightarrow\frac{1}{x}=\frac{1}{27}\)
\(\Leftrightarrow x=27\)
\(\frac{2^{50}.3^{14}.7^{28}}{2^{51}.3^{14}.7^{29}}=\frac{1}{2.7}=\frac{1}{14}\)