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\(M=\frac{131.145+100}{45-132.145}\)
\(=\frac{131-\frac{100}{145}}{\frac{45}{145}-132}\)
\(=\frac{131-\frac{20}{29}}{\frac{9}{29}-132}\)
\(=\frac{131\frac{-20}{29}}{-132\frac{9}{29}}\)
\(\frac{131.145+100}{45-132.140}=\frac{132.145-45}{45-132.140}=-1\)
\(\frac{49^6.5-7^{11}}{\left(-7\right)^{10}.5+2.49^5}=\frac{7^{11}.7-7^{11}.1}{7^{10}.5+2.7^{10}}=\frac{7^{11}.\left(7-1\right)}{7^{10}.\left(5+2\right)}=\frac{7^{11}.6}{7^{11}}=6\)
a) \(\frac{1}{7}+\frac{6}{7}:\frac{3}{7}\)
\(=\frac{1}{7}+\frac{6}{7}.\frac{7}{3}\) (nhân nghịch đảo)
\(=\frac{1}{7}+2\)
\(=\frac{15}{7}\)
b) \(\frac{4}{5}-\frac{1}{5}.\left(-3\right)\)
\(=\frac{4}{5}-\left(-\frac{3}{5}\right)\)
\(=\frac{7}{5}\)
c) \(\frac{3}{7}+\left(\frac{-5}{2}\right)-\left(-\frac{3}{5}\right)\)
\(=\frac{3}{7}-\left(-\frac{5}{2}\right)+\frac{3}{5}\)
\(=\frac{30}{70}+\frac{175}{70}+\frac{42}{70}\)
\(=\frac{30+175+42}{70}\)
\(=\frac{247}{70}\)
d) viết lại đề hộ mình nhé
\(\frac{-2}{13}+\frac{-3}{26}=\frac{-4}{26}+\frac{-3}{26}=\frac{-7}{26}\)
\(\left(7-\frac{2}{3}-\frac{1}{4}\right)-\left(\frac{4}{3}-\frac{10}{4}\right)-\left(\frac{5}{4}-\frac{1}{3}\right)\)
\(=7-\frac{2}{3}-\frac{1}{4}-\frac{4}{3}+\frac{10}{4}-\frac{5}{4}+\frac{1}{3}\)
\(=7-\frac{5}{3}+1\)
\(=8-\frac{5}{3}\)
\(=\frac{19}{3}\)
\(\left(7-\frac{2}{3}-\frac{1}{4}\right)-\left(\frac{4}{3}-\frac{10}{4}\right)-\left(\frac{5}{4}-\frac{1}{3}\right)\)
\(=\frac{84}{12}-\frac{8}{12}-\frac{3}{12}-\frac{16}{12}+\frac{30}{12}-\frac{15}{12}+\frac{4}{12}\)
\(=\frac{84-8-3-16+30-15+4}{12}\)
\(=\frac{76}{12}=\frac{19}{3}\)
Vậy \(\left(7-\frac{2}{3}-\frac{1}{4}\right)-\left(\frac{4}{3}-\frac{10}{4}\right)-\left(\frac{5}{4}-\frac{1}{3}\right)\)\(=\frac{19}{3}\)