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3 tháng 12 2016
\(\frac{2^{35}.9^{25}.5^{25}.13^{22}.7^{16}.5^{16}}{9^{26}.13^{22}5.^{22}.7^{17}.4^{17}.5^{2.9}}=2^{\left(35-2.17\right)}.9^{\left(25-26\right)}.5^{\left(25+16\right)-\left(22+2.9\right)}.13^{22-22}.7^{16-17}.\)
\(2^1.9^{-1}.5^1.13^0.7^{-1}=\frac{2.5}{9.7}=\frac{10}{63}\)
BT
9 tháng 11 2016
A=\(\frac{2^{35}.9^{25}.5^{25}.13^{22}.7^{16}.5^{16}}{4^{17}.7^{17}.9^{26}.13^{22}.5^{22}.5^9.5^9}=\frac{2^{35}.5^1}{4^{17}.7^1.9}=\frac{2^{35}.5}{2^{34}.7^1.9}\)= \(\frac{2.5}{7.9}=\frac{10}{63}\)
29 tháng 12 2021
\(=\dfrac{\left(x-3\right)\left(x+3\right)}{x+3}=x-3\)
7 tháng 1 2022
\(\dfrac{x^2-3x}{x^2-6x+9}=\dfrac{x\left(x-3\right)}{\left(x-3\right)^2}=\dfrac{x}{x-3}.\)
ĐKXĐ: \(x\ne3.\)
7 tháng 1 2022
\(=\dfrac{\left(x-3\right)\cdot x}{\left(x-3\right)^2}=\dfrac{x}{x-3}\)
S
3
TH
27 tháng 7 2016
Ta có:
\(\frac{2^{35}.45^{25}.13^{22}.35^{16}}{9^{26}.65^{22}.28^{17}.25^9}=\frac{2^{35}.\left(9.5\right)^{25}.13^{22}.\left(5.7\right)^{16}}{9^{26}.\left(5.13\right)^{22}.\left(7.4\right)^{17}.\left(5.5\right)^9}\)
\(=\frac{2^{35}.9^{25}.5^{25}.13^{22}.5^{16}.7^{16}}{9^{26}.13^{22}.5^{22}.7^{17}.4^{17}.5^9.5^9}\)
\(=\frac{2^{35}.5^3}{9.4^{17}.5^2.7}\)
\(=\frac{2^{35}.5}{9.4^{17}.7}\)
\(=\frac{2^{35}.5}{9.2^{34}.7}\)
\(=\frac{2.5}{9.7}\)
\(=\frac{10}{63}\)
p/s: - Ko chắc ~
22 tháng 12 2021
\(a,\dfrac{\left(x-1\right)^2}{x^2-1}=\dfrac{\left(x-1\right)^2}{\left(x-1\right)\left(x+1\right)}=\dfrac{x-1}{x+1}\\ b,\dfrac{x^2-16}{4x-x^2}=\dfrac{\left(x-4\right)\left(x+4\right)}{x\left(4-x\right)}=\dfrac{-\left(4-x\right)\left(x+4\right)}{x\left(4-x\right)}=\dfrac{-\left(x+4\right)}{x}\\ c,\dfrac{x^2+6x+9}{2x+6}=\dfrac{\left(x+3\right)^2}{2\left(x+3\right)}=\dfrac{x+3}{2}\)
\(d,\dfrac{x^2+x}{x^2+4x+3}=\dfrac{x\left(x+1\right)}{\left(x^2+x\right)+\left(3x+3\right)}=\dfrac{x\left(x+1\right)}{x\left(x+1\right)+3\left(x+1\right)}=\dfrac{x\left(x+1\right)}{\left(x+1\right)\left(x+3\right)}=\dfrac{x}{x+3}\)
\(e,\dfrac{x^2-x+1}{x^3+1}=\dfrac{x^2-x+1}{\left(x+1\right)\left(x^2-x+1\right)}=\dfrac{1}{x+1}\\ f,\dfrac{\left(x+y\right)^2-z^2}{x+y+z}=\dfrac{\left(x+y-z\right)\left(x+y+z\right)}{x+y+z}=x+y-z\)
DN
1
KV
14 tháng 12 2023
9(x + 1)² - 16(y + 3)²
= 9(x² + 2x + 1) - 16(y² + 6y + 9)
= 9x² + 18x + 9 - 16y² - 96y - 144
= 9x² - 16y² + 18x - 96y - 135