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ừa, nhưng mik còn những câu sau khó hơn nhưng mỏi tay quá nên tí gửi tiếp!
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a) Ta có :
990 = 2.32.5.11
2610=2.32.5.29
ƯCLN(990;2610) = 2.32.5=90
\(\Rightarrow\frac{990}{2610}=\frac{990:90}{2610:90}=\frac{11}{29}\)
Tương tự với câu b)
\(a,\frac{990}{2610}=\frac{990:90}{2610:90}=\frac{11}{29}\)
\(b,\frac{374}{506}=\frac{374:2}{506:2}=\frac{187}{253}=\frac{187:11}{253:11}=\frac{17}{23}\)
\(c,\frac{3600-75}{8400-175}=\frac{3525}{8225}=\frac{3525:25}{8225:25}=\frac{141}{329}\)
\(d,\frac{9^{14}.25^5.8^7}{18^{12}.625^3.24^3}=\frac{9^{12}.9^2.25^3.25^2.8^3.8^4}{\left(9.2\right)^{12}.\left(25.25\right)^3.\left(8.3\right)^3}=\frac{9^{12}.9^2.25^3.25^2.8^3.8^3.8}{9^{12}.2^{12}.25^3.25^2.25.8^3.3^3}=\frac{9^2.8}{2^{12}.25.3^3}\) đến đây bn tự làm nốt đi!
~ mỏi ~
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\(\frac{44116-14}{10290-35}=\frac{44102}{10255}\)
\(\frac{3600-75}{8400-175}=\frac{75\left(48-1\right)}{35\left(240-5\right)}=\frac{15\cdot47}{7\cdot235}=\frac{3\cdot5\cdot47}{7\cdot5\cdot47}=\frac{3}{7}\)
g, \(\frac{44116-14}{10290-35}=\frac{44102}{10255}\)
h, \(\frac{3600-75}{8400-175}=\frac{3525}{8225}=\frac{3}{7}\)
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\(d.\frac{2.5.13}{14.15}=\frac{2.5.13}{2.7.5}=\frac{13}{7}\)
\(e.\frac{9.6-9.3}{18}=\frac{9\left(6-3\right)}{9.2}=\frac{9.3}{9.2}=\frac{3}{2}\)
\(f.\frac{17.5-17.2}{3-20}=\frac{17\left(5-2\right)}{-17}=\frac{17.3}{-17}=-3\)
Thích chơi kiểu gạch này :v
d, \(\frac{2.5.13}{14.15}=\frac{2.5.13}{2.7.3.5}=\frac{13}{21}\)
e, \(\frac{9.6-9.3}{18}=\frac{54-27}{18}=\frac{27}{18}=\frac{3}{2}\)
f, \(\frac{17.5-17.2}{3-20}=\frac{17\left(5-2\right)}{-17}=\frac{17.3}{-17}=\frac{17.3}{-1.17}=\frac{3}{-1}=-3\)
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\(\frac{18.2+9}{27}=\frac{9.2.2+9}{3.9}=\frac{9\left(2.2+1\right)}{3.9}\)
\(\Rightarrow\frac{2.2+1}{3}=\frac{5}{3}\)
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Ta có:
\(\frac{a}{b}\)=\(\frac{-8}{11}\)
Hay 1-\(\frac{a}{b}\)=1-\(\frac{-8}{11}\)=1+\(\frac{8}{11}\)
<=>\(\frac{b-a}{b}\)=\(\frac{11+8}{11}\)(*)
Thay b-a vào (*) ta được:
\(\frac{190}{b}\)=\(\frac{19}{11}\)
=>b=(190x11):19=110
Vậy phân số cần tìm là\(\frac{-80}{110}\)
cho tớ đúng nhé
\(a.\frac{4.7}{9.32}=\frac{4.7}{4.8.9}=\frac{7}{8.9}=\frac{7}{72}\)
\(b.\frac{990}{2610}=\frac{990\div90}{2610\div90}=\frac{11}{29}\)
\(c.\frac{374}{-506}=\frac{374\div\left(-22\right)}{-506\div\left(-22\right)}=\frac{-17}{23}\)
\(\frac{4\cdot7}{9\cdot32}=\frac{4\cdot7}{9\cdot4\cdot8}=\frac{7}{9\cdot8}=\frac{7}{72}\)
\(\frac{990}{2610}=\frac{2\cdot3^2\cdot5\cdot11}{2\cdot3^2\cdot5\cdot29}=\frac{11}{29}\)
\(\frac{374}{-506}=-\frac{374}{506}=\frac{2\cdot11\cdot17}{2\cdot11\cdot23}=-\frac{17}{23}\)