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29 tháng 7 2021

a, \(A=\left(x-1\right)\left(x^2+x+1\right)-\left(x+1\right)\left(x^2-x+1\right)=x^3-1-x^3-1=-2\)

b, \(B=2x\left(4x+1\right)-8x^2\left(x+1\right)+\left(2x\right)^3-2x+3\)

\(=8x^2+2x-8x^3-8x^2+8x^3-2x+3=3\)

c, \(C=\left(x-1\right)^3+\left(x+1\right)^3+2x\left(x+2\right)\left(x-2\right)\)

\(=\left(x-1+x+1\right)^3-3\left(x-1\right)\left(x+1\right)\left(x-1+x+1\right)+2x\left(x^2-4\right)\)

\(=8x^3-6x\left(x^2-1\right)+2x^3-8x=8x^3-6x^3+6x+2x^3-8x=4x^3-2\)

d, \(D=\left(x+y-5\right)^2-2\left(x+y-5\right)\left(x+3\right)+x^2+6x+9\)

\(=\left(x+y-5-x-3\right)^2=\left(y-8\right)^2=y^2-16x+64\)

a: Ta có: \(\left(x+y\right)^2+\left(x-y\right)^2-2x^2\)

\(=x^2+2xy+y^2+x^2-2xy+y^2-2x^2\)

\(=2y^2\)

b: Ta có: \(\left(x+1\right)^3-\left(x-1\right)\left(x^2+x+1\right)-3x\left(x+1\right)\)

\(=x^3+3x^2+3x+1-x^3+1-3x^2-3x\)

=2

5 tháng 10 2021

c) \(\left(x+2y\right)\left(x^2-2xy+4y^2\right)-\left(x-2y\right)\left(x^2+2xy+4y^2\right)+2y^3\)

\(=\left(x^3+\left(2y\right)^3\right)-\left(x^3-\left(2y^3\right)\right)+2y^3\)

\(=x^3+8y^3-x^3+8y^3+2y^3\)

\(=8y^3+8y^3+2y^3\)

\(=18y^3\)

8 tháng 11 2021

a) \(=x^2+2x-2x=x^2\)

b) \(=4-x^2+x^2=4\)

c) \(=x^2-x^3+x^3+27=x^2+27\)

d) \(=4x^2+4xy+y^2+4x^2-8x^2-4xy=y^2\)

9 tháng 5 2021

\(x\ge0\)

\(A=x-3+\left|6x\right|=x-3+6x=7x-3\)

\(x< 0\)

\(A=x-3+\left|6x\right|=x-3+6\cdot\left(-x\right)=-5x-3\)

 

9 tháng 5 2021

`x>= 0 => A = 5x-1-3x=2x-1`

`x<0 => A=5x-1+3x=8x-1`

19 tháng 3 2020

=[x(x-2)/2(x2+4)-2x2/(4+x2)(2-x)][x(x-2)(x+1)/x3]

={[x(x-2)(2-x)-4x2 ]/2(2-x)(4+x2)} .[x(x-2)(x+1)/x3 ]

=[-x(x2+4)/2(2-x)(4+x2)].[x(x-2)(x+1)/x3 ]

=-x.x(x-2)(x+1)/2(2-x)x3

=(x+1)/2x

2 tháng 6 2023

D = (3x - 2)^2 - 3(x - 4)(4 + x) + (x - 3)^3 - (x^2 - x + 1)(x + 1)

D = 9x^2 - 12x + 4 - 3x^2 + 48 + x^3 - 9x^2 + 27x - 27 - x^3 - 1

D = -3x^2 + 15x + 24

9 tháng 5 2021

\(x\ge-\dfrac{4}{5}\)

\(A=5x+2+\left|5x+4\right|=5x+2+5x+4=10x+6\)

\(x< -\dfrac{4}{5}\)

\(A=5x+2+\left|5x+4\right|=5x+2-5x+4=6\)

11 tháng 12 2023

d: \(D=x^3-6x^2+12x-100\)

\(=x^3-6x^2+12x-8-92\)

\(=\left(x-2\right)^3-92\)

Khi x=-98 thì \(D=\left(-98-2\right)^3-92=-1000000-92=-1000092\)

e: \(E=\left(x+1\right)^3+6\left(x+1\right)^2+12x+20\)

\(=\left(x+1\right)^3+6\left(x+1\right)^2+12\left(x+1\right)+8\)

\(=\left(x+1+2\right)^3\)

\(=\left(x+3\right)^3\)

Khi x=5 thì \(E=\left(5+3\right)^3=8^3=512\)

f: \(F=\left(2x-1\right)\left(4x^2+2x+1\right)-7\left(x^3+1\right)\)

\(=\left(2x\right)^3-1^3-7x^3-7\)

\(=x^3-8\)

Khi x=-1/2 thì \(F=\left(-\dfrac{1}{2}\right)^3-8=-\dfrac{1}{8}-8=-\dfrac{65}{8}\)

g: \(G=\left(-x-2\right)^3+\left(2x-4\right)\left(x^2+2x+4\right)-x^2\left(x-6\right)\)

\(=-\left(x+2\right)^3+2\left(x-2\right)\left(x^2+2x+4\right)-x^3+6x^2\)

\(=-x^3-6x^2-12x-8+2\left(x^3-8\right)-x^3+6x^2\)

\(=-2x^3-12x-8+2x^3-16=-12x-24\)

Khi x=-2 thì \(G=-12\cdot\left(-2\right)-24=24-24=0\)

h: \(H=\left(x-1\right)^3-\left(x+2\right)\left(x^2-2x+4\right)+3\left(x+4\right)\left(x-4\right)\)

\(=x^3-3x^2+3x-1-\left(x^3+8\right)+3\left(x^2-16\right)\)

\(=x^3-3x^2+3x-1-x^3-8+3x^2-48\)

\(=3x-57\)

Khi x=-1/2 thì \(H=3\cdot\dfrac{-1}{2}-57=-1,5-57=-58,5\)