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a)\(4\sqrt{x}-5\sqrt{4x}-\sqrt{25x}-3\sqrt{x}-5\)
=\(4\sqrt{x}-10\sqrt{x}-5\sqrt{x}-3\sqrt{x}-5\)
=\(-14\sqrt{x}-5\)
b)\(\sqrt{16x}-5\left(\sqrt{x}-2\right)\sqrt{79x}-5\)
=\(4\sqrt{x}-\left(5\sqrt{x}-10\right)\sqrt{79x}-5\)
=\(4\sqrt{x}-\left(5\sqrt{79}x-10\sqrt{79}x\right)-5\)
=\(4\sqrt{x}+5\sqrt{79}x-5\)
\(1,\\ a,ĐK:11-2x\ge0\Leftrightarrow x\le\dfrac{11}{2}\\ b,ĐK:9x-18\ge0\Leftrightarrow x\ge2\\ c,ĐK:x\ne0;\dfrac{3}{x^2}\ge0\left(luôn.đúng.do.3>0;x^2>0\right)\Leftrightarrow x\in R\backslash\left\{0\right\}\\ d,ĐK:\dfrac{5}{x-7}\ge0\Leftrightarrow x-7>0\left(5>0;x-7\ne0\right)\Leftrightarrow x>7\\ 2,\\ a,=\left|4x\right|-2x^2=4x-2x^2\\ b,bạn.thiếu.điều.kiện.nhé\\ c,=\left|x-5\right|-4x=5-x-4x=5-5x\)
a: \(=6+2\sqrt{11}-4+\sqrt{11}=2+3\sqrt{11}\)
b: \(=\dfrac{3x+9\sqrt{x}-2x+4\sqrt{x}}{\left(\sqrt{x}+3\right)\left(x-2\sqrt{x}\right)}\cdot\dfrac{\left(\sqrt{x}+3\right)^2}{\sqrt{x}+13}=\dfrac{\sqrt{x}+3}{x-2\sqrt{x}}\)
a: \(A=\dfrac{1}{x-1}\cdot5\sqrt{3}\cdot\left|x-1\right|\cdot\sqrt{x-1}\)
\(=\dfrac{5\sqrt{3}}{x-1}\cdot\left(x-1\right)\cdot\sqrt{x-1}=5\sqrt{3}\cdot\sqrt{x-1}\)
b: \(B=10\sqrt{x}-3\cdot\dfrac{10\sqrt{x}}{3}-\dfrac{4}{x}\cdot\dfrac{x\sqrt{x}}{2}\)
\(=10\sqrt{x}-10\sqrt{x}-\dfrac{4\sqrt{x}}{2}=-2\sqrt{x}\)
c: \(C=x-4+\left|x-4\right|\)
=x-4+x-4
=2x-8
b: B=căn 49a^2+3a
=|7a|+3a
=7a+3a(a>=0)
=10a
c: C=căn16a^4+6a^2
=4a^2+6a^2
=10a^2
d: \(D=3\cdot3\cdot\sqrt{a^6}-6a^3=6\cdot\left|a^3\right|-6a^3\)
TH1: a>=0
D=6a^3-6a^3=0
TH2: a<0
D=-6a^3-6a^3=-12a^3
e: \(E=3\sqrt{9a^6}-6a^3\)
\(=3\cdot\sqrt{\left(3a^3\right)^2}-6a^3\)
=3*3a^3-6a^3(a>=0)
=3a^3
f: \(F=\sqrt{16a^{10}}+6a^5\)
\(=\sqrt{\left(4a^5\right)^2}+6a^5\)
=-4a^5+6a^5(a<=0)
=2a^5