\(\left(5-3x\right)^2+\left(x+2\right)^2+x\left(3-4x\right)\)

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\(\left(3x-5\right)^2+\left(x+2\right)^2+x\left(3-4x\right)\)

\(=9x^2-30x+25+x^2+4x+4+3x-4x^2\)

\(=6x^2-23x+29\)

5 tháng 10 2021

\(=25-30x+9x^2+x^2+4x+4+3x-12x^2=-2x^2-23x+29\)

24 tháng 8 2018

\(5x^2-3x\left(x-2\right)\)

\(=5x^2-3x^2+6x\)

\(=2x^2+6x\)

\(-4x^2+2x-4x\left(x-5\right)\)

\(=-4x^2+2x-4x^2+20x\)

\(=-8x^2+22x\)

\(3x\left(x-5\right)-5x\left(x+7\right)\)

\(=3x^2-15x-5x^2+35x\)

\(=-2x^2+20x\)

29 tháng 9 2018

\(\left(x^2-1\right)\left(x+2\right)-\left(x-4\right)\left(x^2+4x+16\right)\)

\(=x^3+2x^2-x-2-\left(x^3-4^3\right)\)

\(=x^3+2x^2-x-2-x^3+64\)

\(=2x^2-x+62\)

\(2x\left(3x-2\right)^2\)

\(=2x\left(9x^2-12x+4\right)\)

\(=18x^3-24x^2+8x\)

\(\left(x-3\right)\left(x^2-3x+9\right)\)

\(=x^3-3x^2+9x-3x^2+9x-27\)

\(=x^3-3x^2+18x-27\)

29 tháng 9 2018

\(\left(x^2-1\right)\left(x+2\right)-\left(x-4\right)\left(x^2+4x+16\right)\)

\(=\left(x^2-1^2\right)\left(x+2\right)-x^3-4^3\)

\(=\left(x+1\right)\left(x-1\right)\left(x+2\right)-x^3-64\)

20 tháng 4 2017

a) (x + 3)(x2 – 3x + 9) – (54 + x3) = (x + 3)(x2 – 3x + 32 ) - (54 + x3)

= x3 + 33 - (54 + x3)

= x3 + 27 - 54 - x3

= -27

b) (2x + y)(4x2 – 2xy + y2) – (2x – y)(4x2 + 2xy + y2)

= (2x + y)[(2x)2 – 2 . x . y + y2] – (2x – y)(2x)2 + 2 . x . y + y2]

= [(2x)3 + y3]- [(2x)3 - y3]


= (2x)3 + y3- (2x)3 + y3= 2y3

20 tháng 4 2017

Bài giải:

a) (x + 3)(x2 – 3x + 9) – (54 + x3) = (x + 3)(x2 – 3x + 32 ) - (54 + x3)

= x3 + 33 - (54 + x3)

= x3 + 27 - 54 - x3

= -27

b) (2x + y)(4x2 – 2xy + y2) – (2x – y)(4x2 + 2xy + y2)

= (2x + y)[(2x)2 – 2 . x . y + y2] – (2x – y)(2x)2 + 2 . x . y + y2]

= [(2x)3 + y3]- [(2x)3 - y3]

= (2x)3 + y3- (2x)3 + y3= 2y3

17 tháng 8 2020

a) \(4x^2\left(5x^3-2x+3\right)\)

\(=20x^5-8x^3+12x^2\)

b) \(3y^2\left(4y^3+\frac{2}{3}y^2-\frac{1}{3}\right)\)

\(=12y^5+2y^4-y^2\)

c) \(\left(5x^2-4x\right)\left(x-2\right)\)

\(=5x^3-14x^2+8x\)

d) \(\left(3x-5\right)\left(2x+11\right)-\left(2x+3\right)\left(3x+7\right)\)

\(=6x^2+22x-55-6x^2-23x-21\)

\(=-x-76\)

17 tháng 8 2020

1, \(4x^2\left(5x^3-2x+3\right)=20x^5-8x^3+12x^2\)

2, \(3y^2\left(4y^3+\frac{2}{3}y^2-\frac{1}{3}\right)=12y^5+2y^4-y^2\)

3, \(\left(5x^2-4x\right)\left(x-2\right)=5x^3-10x^2-4x^2+8x=5x^3-14x^2+8x\)

4, \(\left(3x-5\right)\left(2x+11\right)-\left(2x+3\right)\left(3x+7\right)=6x^2+33x-10x-55-\left(6x^2+14x+9x+21\right)\)

\(=6x^2+23x-55-6x^2-23x-21=-76\)

8 tháng 7 2015

2x(3x3-x)-4x2(x-x2+1)+(x-3x2)x

=6x4-2x2-4x3+4x4-4x2+x2-3x3

=10x4-7x3-5x2

27 tháng 7 2020

a) \(\left(1+x\right)^2+\left(1-x\right)^2\) 

\(=1+2x+x^2+1-2x+x^2\)

\(=2x^2+2\)

b) \(\left(x+2\right)^2+\left(1+x\right)\left(1-x\right)\)

\(=x^2+4x+4+1-x^2\)

\(=4x+5\)

c) \(\left(x-3\right)^2+3\left(x+1\right)^2\)

\(=x^2-6x+9+3x^2+6x+3\)

\(=4x^2+12\)

d)\(\left(2+3x\right)\left(3x-2\right)-\left(3x+1\right)^2\)

\(=9x^2-4-9x^2-6x-1\)

\(=-6x-5\)

e) \(\left(x+5\right)\left(x-2\right)-\left(x+2\right)^2\)

\(=x^2-2x+5x-10-x^2-4x-4\)

\(=-x-14\)

f) \(\left(x+3\right)\left(2x-5\right)-2\left(1+x\right)^2\)

\(=2x^2-5x+6x-15-2-4x-2x^2\)

\(=-3x-17\)

g) \(\left(4x-1\right)\left(4x+1\right)-4\left(1-2x\right)^2\)

\(=16x^2-1-4+16x-16x^2\)

\(=16x-5\)

#Học tốt!

12 tháng 6 2018

a)\(9x^2+30x+25+9x^2-30x+25-\left(9x^2-2^2\right)\)

=\(9x^2+54\)=\(9\left(x^2+6\right)\)

b)\(2x\left(4x^2-4x+1\right)-3x\left(x^2-9\right)-4x\left(x^2+2x+1\right)\)

=\(8x^3-8x^2+2x-3x^3+27x-4x^3-8x^2-4x\)

=\(x^3-16x^2+25x\)

c)\(\left(x+y-z\right)^2-2\left(x+y-z\right)\left(x+y\right)+\left(x+y\right)^2\)

=\(\left(x+y-z-\left(x+y\right)\right)^2\)=\(\left(-z\right)^2\)

7 tháng 9 2020

\(2x\left(2x-1\right)^2-3x\left(x+3\right)\left(x-3\right)-4x\left(x+1\right)^2\)

\(=x\left[2\left(2x-1\right)^2-3\left(x^2-9\right)-4\left(x+1\right)^2\right]\)

\(=x\left(8x^2-8x+1-3x^2+27-4x^2-8x-4\right)\)

\(=x\left(x^2-16x+28\right)=x\left(x-2\right)\left(x-14\right)\)

7 tháng 9 2020

\(2x\left(2x-1\right)^2-3x\left(x+3\right)\left(x-3\right)-4x\left(x+1\right)^2\)

\(=2x\left(4x^2-4x+1\right)-3x\left(x^2-9\right)-4x\left(x^2+2x+1\right)\)

\(=8x^3-8x^2+2x-3x^3+27x-4x^3-8x^2-4x\)

\(=x^3-16x^2+25x\)