
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.



\(\Rightarrow N=20^2-19^2+18^2-17^2+...+2^2-1^2\)
\(=\left(20+19\right)\left(20-19\right)+\left(18+17\right)\left(18-17\right)+...+\left(2+1\right)\left(2-1\right)\)
\(=20+19+18+17+...+2+1\)\(=\left(20+1\right)+\left(19+2\right)+...+\left(11+10\right)\)(có 10 cặp)
=21x10=210

\(S=20^2-19^2+18^2-17^2+...+2^2-1^2\)
\(S=\left(20-19\right)\left(20+19\right)+\left(18-17\right)\left(18+17\right)+...+\left(2-1\right)\left(2+1\right)\)
\(S=39+35+31+...+3\)
\(S=\frac{\left(3+39\right)}{2}.\left(\frac{39-3}{4}+1\right)=210\)
2/ \(1^2+2^2+3^2+...+10^2=385\)
\(\Rightarrow2^2\left(1^2+2^2+3^2+...+10^2\right)=2^2.385\)
\(\Rightarrow2^2+4^2+8^2+...+20^2=4.385=1540\)
1)\(S=\left(20^2+18^2+16^2+...+2^2\right)-\left(19^2+17^2+...+1^2\right)\\ S=20^2-19^2+18^2-17^2+...+2^2-1^2\\ S=\left(20-19\right).\left(20+19\right)+\left(18-17\right)\left(18+17\right)+...+\left(2-1\right).\left(2+1\right)\\ S=39+35+31+...+3\\ S=\frac{\left(3+39\right)}{2}+\left(\frac{39-3}{4}+1\right)\\ S=210\)
2)\(2^2+4^2+6^2+...+20^2\\ =1^2.2^2+2^2.2^2+3^2.2^2+...+10^2.2^2\\ =2^2.\left(1^2+2^2+3^2+...+10^2\right)\\=4.385\\ =1540 \)
#tick&theo dõi

\(M=100^2-99^2+98^2-97^2+...+2^2-1^2\)
\(M=\left(100-99\right)\left(100+99\right)+\left(98-97\right)\left(98+97\right)+...+\left(2-1\right)\left(2+1\right)\)
\(M=100+99+98+97+...+2+1\)
\(M=5050\)
\(N=\left(20^2+18^2+...+2^2\right)-\left(19^2+17^2+...+1^2\right)\)
\(N=20^2-19^2+18^2-17^2+...+2^2-1^2\)
\(N=\left(20-19\right)\left(20+19\right)+\left(18-17\right)\left(18+17\right)+...+\left(2-1\right)\left(2+1\right)\)
\(N=20+19+18+17+...+2+1\)
\(N=210\)

\(=20^2-19^2+18^2-17^2+...+2^2-1^2\)
\(=\left(20+19\right)\left(20-19\right)+\left(18+17\right)\left(18-17\right)+...+\left(2+1\right)\left(2-1\right)\)
\(=39+35+..+3\)
\(=210\)

ta có: H(x) = P(x) +Q(x)
\(\Rightarrow H_{\left(x\right)}=\left(20x^{20}+19x^{19}+18x^{18}+...+2x^2+x\right)+\left(x^{20}-x^{19}+x^{18}-...+3x^2+1\right)\)
\(H_{\left(x\right)}=\left(20x^{20}+x^{20}\right)+\left(19x^{19}-x^{19}\right)+\left(18x^{18}+x^{18}\right)+...+\left(2x^2+3x^2\right)+x+1\)
\(H_{\left(x\right)}=21x^{20}+18x^{19}+19x^{18}+...+5x^2+x+1\)
thay x= -1 vào đa thức H(x)
\(H_{\left(-1\right)}=20.\left(-1\right)^{20}+18.\left(-1\right)^{19}+19\left(-1\right)^{18}+...+5\left(-1\right)^2-1+1\)
\(H_{\left(-1\right)}=20-18+19-16+...+5-1+1\)
\(H_{\left(-1\right)}=\left(20+19+17+...+5+1\right)-\left(18+16+...+1\right)\)
\(H_{\left(-1\right)}=117-91\)
\(H_{\left(-1\right)}=26\)
Chúc bạn học tốt !!

sao cái Q(x) nó chẳng có quy luật j sất vậy
Ta có:A= 2^20+2^19+2^18+...+2^2+2+1
=>2A=2^21+2^20+2^19+...+2^3+2^2+2+1
=>2A-A=2^21-1
A=2^21-1