Q = (–3) + (–4) + (–5) +

K

Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

Mua vip

8T

8.Vũ Tùng Dương tổ2

8 tháng 12 2021 - olm

Q = (–3) + (–4) + (–5) + ...+ (–40)Q = (–3) + (–4) + (–5) + ...+ (–40)Q =(-3) + (-4) + ( -5 ) +...+(-40)

#Hỏi cộng đồng OLM #Toán lớp 6

1

DB

Đỗ Bùi Minh Thư

8 tháng 12 2021

[(-40)-(-3)]÷1+1=(-36) [(-40)+(-3)]×(-36)÷2=774

Các câu hỏi dưới đây có thể giống với câu hỏi trên

NT

Nguyễn Thị Hồng Anh

27 tháng 6 2017

Bài 1: Tính a) ( \(\dfrac{-3}{4}\)+ \(\dfrac{2}{5}\)) : \(\dfrac{3}{7}\)+ ( \(\dfrac{3}{5}\) + \(\dfrac{-9}{4}\)) :\(\dfrac{3}{7}\) b) \(\dfrac{7}{8}\): ( \(\dfrac{2}{9}\)- \(\dfrac{1}{18}\)) + \(\dfrac{7}{8}\) : ( \(\dfrac{1}{36}\) - \(\dfrac{5}{12}\)) Cần gấp...

#Hỏi cộng đồng OLM #Toán lớp 6

2

MS

Mashiro Shiina

27 tháng 6 2017

a) \(\left(\dfrac{-3}{4}+\dfrac{2}{5}\right):\dfrac{3}{7}+\left(\dfrac{3}{5}+\dfrac{-9}{4}\right):\dfrac{3}{7}\)

\(=\left(\dfrac{-3}{4}+\dfrac{2}{5}+\dfrac{3}{5}+\dfrac{-9}{4}\right):\dfrac{3}{7}\)

\(=-2:\dfrac{3}{7}=\dfrac{-14}{3}\)

\(\dfrac{7}{8}:\left(\dfrac{2}{9}-\dfrac{1}{18}\right)+\dfrac{7}{8}:\left(\dfrac{1}{36}-\dfrac{5}{12}\right)\)

\(=\dfrac{7}{8}:\dfrac{1}{6}+\dfrac{7}{8}:\dfrac{-7}{18}\)

\(=\dfrac{7}{8}:\left(\dfrac{1}{6}+\dfrac{-7}{18}\right)=\dfrac{7}{8}:\dfrac{-2}{9}=\dfrac{63}{-16}\)

NT

Nguyễn Thị Hồng Anh

27 tháng 6 2017

còn phần b

HH

hello hello

26 tháng 3 2018

4. tính a. A=\(\dfrac{1}{3}\).\(\dfrac{4}{5}\)+\(\dfrac{1}{3}\).\(\dfrac{6}{5}\)+\(\dfrac{2}{3}\) b. B=\(\dfrac{-5}{6}\).\(\dfrac{4}{19}\)+\(\dfrac{-7}{12}\).\(\dfrac{4}{19}\)-\(\dfrac{40}{57}\) c....

#Hỏi cộng đồng OLM #Toán lớp 6

2

TE

Tóc Em Rối Rồi Kìa

26 tháng 3 2018

\(A=\dfrac{1}{3}\cdot\dfrac{4}{5}+\dfrac{1}{3}\cdot\dfrac{6}{5}+\dfrac{2}{3}\\ =\dfrac{1}{3}\cdot\left(\dfrac{4}{5}+\dfrac{6}{5}\right)+\dfrac{2}{3}\\ =\dfrac{1\cdot2}{3}+\dfrac{2}{3}\\ =\dfrac{2}{3}+\dfrac{2}{3}\\ =\dfrac{4}{3}\)

DT

Đào Thảo Anh

30 tháng 3 2018

B =\(\dfrac{-5}{6}.\dfrac{4}{19}+\dfrac{-7}{12}.\dfrac{4}{19}\)-\(\dfrac{40}{57}\)

=\(\dfrac{4}{19}.\left[\dfrac{-5}{6}+\dfrac{-7}{12}\right]-\dfrac{40}{57}\)

=\(\dfrac{4}{19}.\left[\dfrac{-10}{12}+\dfrac{-7}{12}\right]-\dfrac{40}{57}\)

=\(\dfrac{4}{19}.\dfrac{-17}{12}-\dfrac{40}{57}\)

=\(\dfrac{-17}{57}\)-\(\dfrac{40}{57}\)

=\(\dfrac{-17}{57}+\dfrac{-40}{57}\)

=\(\dfrac{-57}{57}=-1\)

NT

Nguyễn Trà My

23 tháng 8 2017

Tìm \(x\) biết: a) \(\dfrac{1}{3}\).( \(\dfrac{1}{2}\) - \(6\)) + 5\(x\) = \(x\) - \(\dfrac{3}{5}\) b) \(\dfrac{3}{2}\). \(x\) - \(1\dfrac{1}{2}\) = \(x\) - \(\dfrac{3}{4}\) c)\(x\) - \(\dfrac{5}{4}\) = \(\dfrac{1}{3}-\dfrac{3}{4}\) . \(x\) d) \(\dfrac{3}{2}.\left(x-\dfrac{5}{3}\right)\)- \(\dfrac{7}{5}\) = \(x+1\) e)\(\dfrac{2}{3}.\left|4x+3\right|=\dfrac{6}{15}\) giúp mk với, mai mk phải nộp rồi cách làm nữa nhé ...

#Hỏi cộng đồng OLM #Toán lớp 6

7

TN

Trần Nguyễn Bảo Quyên

23 tháng 8 2017

\(a.\)

\(\dfrac{1}{3}\left(\dfrac{1}{2}-6\right)+5x=x-\dfrac{3}{5}\)

\(\Rightarrow\dfrac{1}{6}-2+5x=x-\dfrac{3}{5}\)

\(\Rightarrow\dfrac{1}{6}-2+\dfrac{3}{5}=-5x+x\)

\(\Rightarrow-4x=-\dfrac{37}{30}\)

\(\Rightarrow4x=\dfrac{37}{30}\)

\(\Rightarrow x=\dfrac{37}{120}\)

\(b.\)

\(\dfrac{3}{2}x-1\dfrac{1}{2}=x-\dfrac{3}{4}\)

\(\Rightarrow\dfrac{3}{2}x-\dfrac{3}{2}=x-\dfrac{3}{4}\)

\(\Rightarrow\dfrac{3}{2}x-x=\dfrac{3}{2}-\dfrac{3}{4}\)

\(\Rightarrow\dfrac{1}{2}x=\dfrac{3}{4}\)

\(\Rightarrow x=\dfrac{3}{2}\)

\(c.\)

\(x-\dfrac{5}{4}=\dfrac{1}{3}-\dfrac{3}{4}x\)

\(\Rightarrow x+\dfrac{3}{4}x=\dfrac{1}{3}+\dfrac{5}{4}\)

\(\Rightarrow\dfrac{7}{4}x=\dfrac{19}{12}\)

\(\Rightarrow x=\dfrac{19}{21}\)

\(d.\)

\(\dfrac{3}{2}\left(x-\dfrac{5}{3}\right)-\dfrac{7}{5}=x+1\)

\(\Rightarrow\dfrac{3}{2}x-\dfrac{5}{2}-\dfrac{7}{5}=x+1\)

\(\Rightarrow\dfrac{3}{2}x-\dfrac{39}{10}=x+1\)

\(\Rightarrow\dfrac{3}{2}x-x=\dfrac{39}{10}+1\)

\(\Rightarrow\dfrac{1}{2}x=\dfrac{49}{10}\)

\(\Rightarrow x=\dfrac{49}{5}\)

\(e.\)

\(\dfrac{2}{3}\left|4x+3\right|=\dfrac{6}{15}\)

\(\Rightarrow\left|4x+3\right|=\dfrac{3}{5}\)

\(\Rightarrow\left[{}\begin{matrix}4x+3=\dfrac{3}{5}\\4x+3=-\dfrac{3}{5}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}4x=-\dfrac{12}{5}\\4x=-\dfrac{18}{5}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{3}{5}\\x=-\dfrac{9}{10}\end{matrix}\right.\)

MP

Mysterious Person

23 tháng 8 2017

a) \(\dfrac{1}{3}.\left(\dfrac{1}{2}-6\right)+5x=x-\dfrac{3}{5}\Leftrightarrow\dfrac{1}{6}-2+5x=x-\dfrac{3}{5}\)

\(\Leftrightarrow5x-x=-\dfrac{3}{5}-\dfrac{1}{6}+2\Leftrightarrow4x=\dfrac{37}{30}\Leftrightarrow x=\dfrac{\dfrac{37}{30}}{4}=\dfrac{37}{120}\)

vậy \(x=\dfrac{37}{120}\)

b) \(\dfrac{3}{2}x-1\dfrac{1}{2}=x-\dfrac{3}{4}\Leftrightarrow\dfrac{3}{2}x-x=\dfrac{-3}{4}+1\dfrac{1}{2}\Leftrightarrow\dfrac{1}{2}x=\dfrac{-3}{4}+\dfrac{3}{2}\)

\(\Leftrightarrow\dfrac{1}{2}x=\dfrac{3}{4}\Leftrightarrow x=\dfrac{3}{4}.2=\dfrac{6}{4}=\dfrac{3}{2}\) vậy \(x=\dfrac{3}{2}\)

c) \(x-\dfrac{5}{4}=\dfrac{1}{3}-\dfrac{3}{4}x\Leftrightarrow x+\dfrac{3}{4}x=\dfrac{1}{3}+\dfrac{5}{4}\Leftrightarrow\dfrac{7}{4}x=\dfrac{19}{12}\)

\(\Leftrightarrow x=\dfrac{\dfrac{19}{12}}{\dfrac{7}{4}}=\dfrac{19}{21}\) vậy \(x=\dfrac{19}{21}\)

d) \(\dfrac{3}{2}\left(x-\dfrac{5}{3}\right)-\dfrac{7}{5}=x+1\Leftrightarrow\dfrac{3}{2}x-\dfrac{5}{2}-\dfrac{7}{5}=x+1\)

\(\Leftrightarrow\dfrac{3}{2}x-x=1+\dfrac{5}{2}+\dfrac{7}{5}\Leftrightarrow\dfrac{1}{2}x=\dfrac{49}{10}\Leftrightarrow x=\dfrac{49}{10}.2=\dfrac{49}{5}\)

vậy \(x=\dfrac{49}{5}\)

e) \(\dfrac{2}{3}\left|4x+3\right|=\dfrac{6}{15}\Leftrightarrow\left|4x+3\right|=\dfrac{\dfrac{6}{15}}{\dfrac{2}{3}}=\dfrac{3}{5}\)

th1 : \(4x+3\ge0\Leftrightarrow4x\ge-3\Leftrightarrow x\ge\dfrac{-3}{4}\)

\(\Rightarrow\left|4x+3\right|=\dfrac{3}{5}\Leftrightarrow4x+3=\dfrac{3}{5}\Leftrightarrow4x=\dfrac{3}{5}-3=\dfrac{-12}{5}\)

\(\Leftrightarrow x=\dfrac{\dfrac{-12}{5}}{4}=\dfrac{-3}{5}\left(tmđk\right)\)

th2: \(4x+3< 0\Leftrightarrow4x< -3\Leftrightarrow x< \dfrac{-3}{4}\)

\(\Rightarrow\left|4x+3\right|=\dfrac{3}{5}\Leftrightarrow-\left(4x+3\right)=\dfrac{3}{5}\Leftrightarrow-4x-3=\dfrac{3}{5}\)

\(\Leftrightarrow4x=-3-\dfrac{3}{5}=\dfrac{-18}{5}\Leftrightarrow x=\dfrac{\dfrac{-18}{5}}{4}=\dfrac{-9}{10}\left(tmđk\right)\)

vậy \(x=\dfrac{-3}{5};x=\dfrac{-9}{10}\)

LT

le thi minh hong

22 tháng 4 2018 - olm

tính

a) A= \(\frac{-2}{4}\)+\(\frac{2}{7}\)- \(\frac{5}{28}\)

b) B= ( \(\frac{5}{7}\).0,6 -5: 3\(\frac{1}{2}\)) .( 40%-1,4).(-2)\(^{^3}\)

#Hỏi cộng đồng OLM #Toán lớp 6

0

LT

lê thiên minh

5 tháng 5 2019 - olm

tìm x biết

\(\frac{3}{4}\). x + 40% = \(\frac{-1}{4}\)

\(\frac{1}{2}\)- \(\frac{2}{5}\).x = \(\frac{-1}{3}\)

|x - 1| = 2^3+ (-5)

#Hỏi cộng đồng OLM #Toán lớp 6

2

LT

Lê Tài Bảo Châu

5 tháng 5 2019

a) \(\frac{3}{4}.x+40\%=\frac{-1}{4}\)

\(\frac{3}{4}.x+\frac{2}{5}=\frac{-1}{4}\)

\(\frac{3}{4}.x=\frac{-13}{20}\)

\(x=\frac{-13}{15}\)

Vậy \(x=\frac{-13}{15}\)

LT

Lê Tài Bảo Châu

5 tháng 5 2019

c) \(|x-1|=2^3+\left(-5\right)\)

\(|x-1|=3\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=3\\x-1=-3\end{cases}\Leftrightarrow\orbr{\begin{cases}x=4\\x=-2\end{cases}}}\)

Vậy \(x\in\left\{-2;4\right\}\)

VT

Vũ Thị Trâm Anh

11 tháng 8 2016 - olm

Tìm X:a) 2 - ( 5\(\frac{3}{8}\)x X - \(\frac{5}{24}\)= \(\frac{5}{12}\)b) 1\(\frac{2}{9}\): ( 3\(\frac{1}{3}\)x X + \(\frac{1}{6}\)) = \(\frac{22}{23}\)c) \(\frac{4}{5}\)x X - \(\frac{1}{2}\)x X + \(\frac{3}{4}\)x X = \(\frac{7}{40}\)Giúp...

#Hỏi cộng đồng OLM #Toán lớp 6

1

AH

An Hoà

11 tháng 8 2016

a) 2 - ( \(5\frac{3}{8}\)x X - \(\frac{5}{24}\)) = \(\frac{5}{12}\)

\(5\frac{3}{8}\)x X - \(\frac{5}{24}\)= \(\frac{19}{12}\)

\(5\frac{3}{8}\)x X = \(\frac{43}{24}\)

X = \(\frac{1}{3}\)

b) \(1\frac{2}{9}\): ( \(3\frac{1}{3}\)x X + \(\frac{1}{6}\)) = \(\frac{22}{23}\)

\(3\frac{1}{3}\)x X + \(\frac{1}{6}\) = \(\frac{23}{18}\)

\(3\frac{1}{3}\)x X = \(\frac{10}{9}\)

X =\(\frac{1}{3}\)

C) \(\frac{4}{5}\)x X - \(\frac{1}{2}\)x X + \(\frac{3}{4}\)x X = \(\frac{7}{40}\)

( \(\frac{4}{5}-\frac{1}{2}+\frac{3}{4}\)) x X = \(\frac{7}{40}\)

\(\frac{21}{20}\) x X = \(\frac{7}{40}\)

X =\(\frac{1}{6}\)

KL

Khanh Lê

12 tháng 4 2017

Tìm x biết : 1/\(\dfrac{4}{3}\) + x = \(\dfrac{2}{15}\) 2/\(\dfrac{1}{3}+\dfrac{1}{2}:\) x = -0,25 3/(\(\dfrac{2x}{5}+2\) ):(-4) = -1\(\dfrac{1}{2}\) 4/ x.( x + 1) = 0 5/3\(\dfrac{1}{2}-\dfrac{1}{2}x\) = \(\dfrac{2}{3}\) 6/1\(\dfrac{1}{2}+x=\dfrac{3}{2}-7\) 7/\(2x-16=40+x\) 8/\(x:\dfrac{5}{3}+\dfrac{1}{3}=\dfrac{-2}{5}\) ...

#Hỏi cộng đồng OLM #Toán lớp 6

1

MV

Mới vô

23 tháng 4 2017

9) \(\dfrac{x}{4}=\dfrac{9}{x}\)

Theo định nghĩa về hai phân số bằng nhau, ta có:

\(4\cdot9=x^2\\ 36=x^2\Rightarrow\left[{}\begin{matrix}x=6\\x=-6\end{matrix}\right.\)

8)

\(x:\dfrac{5}{3}+\dfrac{1}{3}=-\dfrac{2}{5}\\ x:\dfrac{5}{3}=-\dfrac{2}{5}+\dfrac{1}{3}\\ x:\dfrac{5}{3}=-\dfrac{1}{15}\\ x=\dfrac{1}{15}\cdot\dfrac{5}{3}\\ x=\dfrac{1}{9}\)

7)

\(2x-16=40+x\\ 2x-x=40+16\\ x\left(2-1\right)=56\\ x=56\)

6)

\(1\dfrac{1}{2}+x=\dfrac{3}{2}-7\\ \dfrac{3}{2}+x=\dfrac{3}{2}-7\\ \dfrac{3}{2}-\dfrac{3}{2}=-7-x\\ -7-x=0\\ x=-7-0\\ x=-7\)

5)

\(3\dfrac{1}{2}-\dfrac{1}{2}x=\dfrac{2}{3}\\ \dfrac{7}{2}-\dfrac{1}{2}x=\dfrac{2}{3}\\ \dfrac{1}{2}x=\dfrac{7}{2}-\dfrac{2}{3}\\ \dfrac{1}{2}x=\dfrac{17}{6}\\ x=\dfrac{17}{6}:\dfrac{1}{2}\\ x=\dfrac{17}{3}\)

4)

\(x\cdot\left(x+1\right)=0\Rightarrow\left[{}\begin{matrix}x=0\\x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=-1\end{matrix}\right.\)

3)

\(\left(\dfrac{2x}{5}+2\right):\left(-4\right)=-1\dfrac{1}{2}\\ \left(\dfrac{2x}{5}+2\right):\left(-4\right)=-\dfrac{3}{2}\\ \dfrac{2x}{5}+2=-\dfrac{3}{2}\cdot\left(-4\right)\\ \dfrac{2x}{5}+2=6\\ \dfrac{2x}{5}=6-2\\ \dfrac{2x}{5}=4\\ 2x=4\cdot5\\ 2x=20\\ x=20:2\\ x=10\)

2)

\(\dfrac{1}{3}+\dfrac{1}{2}:x=-0,25\\ \dfrac{1}{3}+\dfrac{1}{2}:x=-\dfrac{1}{4}\\ \dfrac{1}{2}:x=-\dfrac{1}{4}-\dfrac{1}{3}\\ \dfrac{1}{2}:x=-\dfrac{7}{12}\\ x=\dfrac{1}{2}:-\dfrac{7}{12}\\ x=-\dfrac{6}{7}\)

1)

\(\dfrac{4}{3}+x=\dfrac{2}{15}\\ x=\dfrac{2}{15}-\dfrac{4}{3}x=-\dfrac{6}{5}\)

LF

Louise Francoise

22 tháng 3 2017

#Hỏi cộng đồng OLM #Toán lớp 6

1

NH

Ngọc Hằng

22 tháng 3 2017

tính nhanh hay là tính bt bn ?

LF

Louise Francoise

22 tháng 3 2017

Là tính nhanh.Giúp mình với!

DV

Đặng Vũ Hoài Anh

4 tháng 8 2017

Bài 1: Tính ( hợp lý nếu có thể) A=\(\dfrac{-3}{8}\)+\(\dfrac{12}{25}\)+\(\dfrac{5}{-8}\)+\(\dfrac{2}{-5}\)+\(\dfrac{13}{25}\) B=\(\dfrac{-3}{15}\)+(\(\dfrac{2}{3}\)+\(\dfrac{3}{15}\)) C=\(\dfrac{-5}{21}\)+(\(\dfrac{-16}{21}\)+1) D=(\(\dfrac{-1}{6}\)+\(\dfrac{5}{-12}\))+\(\dfrac{7}{12}\) E=\(\dfrac{1}{3}\)x\(\dfrac{4}{5}\)+\(\dfrac{1}{3}\)x\(\dfrac{6}{5}\)+\(\dfrac{2}{3}\) F=\(\dfrac{-5}{6}\)x\(\dfrac{4}{19}\)+\(\dfrac{-7}{12}\)x\(\dfrac{4}{12}\)-\(\dfrac{40}{47}\) Bài 2: Tìm...

#Hỏi cộng đồng OLM #Toán lớp 6

2

CB

Cô Bé Yêu Đời

4 tháng 8 2017

Bài 1: Tính ( hợp lý nếu có thể )

\(A=\dfrac{-3}{8}+\dfrac{12}{25}+\dfrac{5}{-8}+\dfrac{2}{-5}+\dfrac{13}{25}\)

\(=\left(\dfrac{-3}{8}+\dfrac{5}{-8}\right)+\left(\dfrac{12}{25}+\dfrac{13}{25}\right)+\dfrac{2}{-5}\)

\(=-1+1+\dfrac{2}{-5}\)

\(=0+\dfrac{2}{-5}\)

\(=\dfrac{2}{-5}\)

\(B=\dfrac{-3}{15}+\left(\dfrac{2}{3}+\dfrac{3}{15}\right)\)

\(=\left(\dfrac{-3}{15}+\dfrac{3}{15}\right)+\dfrac{2}{3}\)

\(=0+\dfrac{2}{3}\)

\(=\dfrac{2}{3}\)

\(C=\dfrac{-5}{21}+\left(\dfrac{-16}{21}+1\right)\)

\(=\left(\dfrac{-5}{21}+\dfrac{-16}{21}\right)+1\)

\(=-1+1\)

\(=0\)

\(D=\left(\dfrac{-1}{6}+\dfrac{5}{-12}\right)+\dfrac{7}{12}\)

\(=\left(\dfrac{5}{-12}+\dfrac{7}{12}\right)+\dfrac{-1}{6}\)

\(=\dfrac{1}{6}+\dfrac{-1}{6}\)

\(=0\)

CB

Cô Bé Yêu Đời

4 tháng 8 2017

Bài 2: Tìm x,biết:

a) \(x+\dfrac{2}{3}=\dfrac{4}{5}\)

\(x=\dfrac{4}{5}-\dfrac{2}{3}\)

\(x=\dfrac{2}{15}\)

Vậy \(x=\dfrac{2}{15}\)

b) \(x-\dfrac{2}{3}=\dfrac{7}{21}\)

\(\Rightarrow x-\dfrac{2}{3}=\dfrac{1}{3}\)

\(x=\dfrac{1}{3}+\dfrac{2}{3}\)

\(x=\dfrac{3}{3}=1\)

Vậy \(x=1\)

c) sai đề hay sao ấy bạn.bỏ dấu - ở x thì đúng đề.mk giải luôn nha!

\(x-\dfrac{3}{4}=\dfrac{-8}{11}\)

\(x=\dfrac{-8}{11}+\dfrac{3}{4}\)

\(x=\dfrac{1}{44}\)

Vậy \(x=\dfrac{1}{44}\)

d) \(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\)

\(\dfrac{2}{5}+x=\dfrac{11}{12}-\dfrac{2}{3}\)

\(\dfrac{2}{5}+x=\dfrac{1}{4}\)

\(x=\dfrac{1}{4}-\dfrac{2}{5}\)

\(x=-\dfrac{3}{20}\)

Vậy \(x=-\dfrac{3}{20}\)

KS

kudo shinichi

2 tháng 5 2018 - olm

Thực hiện phép tính sau

1) A= \(\frac{-2}{4}\)+\(\frac{2}{7}\)-\(\frac{5}{28}\)

2) B= (\(\frac{5}{7}\). 0,6-5:\(3\frac{1}{2}\)) . (40%-1,4). (\(^{-2^3}\))

#Hỏi cộng đồng OLM #Toán lớp 6

0