Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) y x 42 + y x 57 + y = 25 400
y x ( 42 + 57 + 1 ) = 25 400
y x 100 = 25 400
y = 25 400 : 100
y = 254
b) 142 x y - 41 x y - y = 408 000
y x ( 142 - 41 - 1 ) = 408 000
y x 100 = 408 000
y = 408 000 : 100
y = 4 080
a.y*(42+57+1)=25400
y*100=25400
y=25400:100=254
b.(142-41-1)*y=408000
100*y=408000
y=408000:100=4080
Bài 2:
c: \(y:312=345:5\)
\(\Leftrightarrow y:312=69\)
hay \(y=21528\)
d: \(918670-y=251\cdot142\)
\(\Leftrightarrow y=91867-35642=56225\)
Y x 42 +Yx 57 + Y = 25400
=> Y x (42 + 57 + 1) = 25400
=> Y x 100 = 25400
=> Y = 25400 : 100
=> Y = 254
Y x 42 +Yx 57 + Y = 25400
Y x ( 42 + 57 ) + Y = 25400
Y x 99 + Y = 25400
\(\frac{42}{y}=\frac{18}{21}\)
\(\Rightarrow y\times18=42\times21\)
\(\Rightarrow y\times18=882\)
\(\Rightarrow y=882:18\)
\(\Rightarrow y=49\)
Vậy \(y=49\)
\(\frac{y}{14}=\frac{25}{35}\)
\(\Rightarrow y\times35=25\times14\)
\(\Rightarrow y\times35=350\)
\(\Rightarrow y=350:35\)
\(\Rightarrow y=10\)
Vậy \(y=10\)
a,\(\frac{42}{y}=\frac{18}{21}\)=> \(18y=882=>y=49\)
b,\(\frac{y}{14}=\frac{25}{35}< =>\frac{y}{14}=\frac{5}{7}=>7y=70=>y=10\)
\(12:y=\frac{3}{4}+\frac{4}{5}\)
\(12:y=\frac{15}{20}+\frac{16}{20}\)
\(12:y=\frac{31}{20}\)
\(y=12:\frac{31}{20}\)
\(y=12x\frac{20}{31}\)
\(y=\frac{240}{31}\)
\(\frac{4}{5}xY=1\)
\(y=1:\frac{4}{5}\)
\(y=1x\frac{5}{4}\)
\(y=\frac{5}{4}\)
\(\frac{37}{63}-y=\frac{1}{7}\)
\(y=\frac{37}{63}-\frac{1}{7}\)
\(y=\frac{37}{63}-\frac{9}{63}\)
\(y=\frac{28}{63}\)
\(y=\frac{4}{9}\)
\(y:\frac{3}{7}=\frac{3}{42}+\frac{5}{7}\)
\(y:\frac{3}{7}=\frac{3}{42}+\frac{30}{42}\)
\(y:\frac{3}{7}=\frac{33}{42}\)
\(y:\frac{3}{7}=\frac{11}{14}\)
\(y=\frac{11}{14}x\frac{3}{7}\)
\(y=\frac{33}{98}\)
\(12:y=\frac{3}{4}+\frac{4}{5}\) \(\frac{37}{63}-y=\frac{1}{7}\)
\(12:y=\frac{31}{20}\) \(y=\frac{37}{63}-\frac{1}{7}\)
\(y=12:\frac{31}{20}\) \(y=\frac{4}{9}\)
\(y=\frac{240}{31}\)
\(\frac{4}{5}\cdot y=1\) \(y:\frac{3}{7}=\frac{3}{42}+\frac{5}{7}\)
\(y=1:\frac{4}{5}\) \(y:\frac{3}{7}=\frac{11}{14}\)
\(y=\frac{5}{4}\) \(y=\frac{11}{14}.\frac{3}{7}\)
\(y=\frac{33}{98}\)
\(y.27+y.42+y.70-y.19=16700\)
\(\Leftrightarrow y\left(27+42+70-19\right)=16700\)
\(\Leftrightarrow y.120=16700\)
\(\Leftrightarrow y=\dfrac{835}{6}\)
\(y+142+y-42+y-y=20800\)
\(\Leftrightarrow\)\(\left(3y-y\right)+\left(142-42\right)=20800\)
\(\Leftrightarrow\)\(2y+100=20800\)
\(\Leftrightarrow\)\(2y=20800-100=20700\)
\(\Rightarrow\)\(y=\frac{20700}{2}=10350\)
Vậy \(y=10350\)
kô hiểu bạn có thể giải ra được kô