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\(\frac{2}{1^2}.\frac{6}{2^2}.\frac{12}{3^2}.\frac{20}{4^2}...\frac{110}{10^2}.x=-20\)
\(\Leftrightarrow\frac{1.2}{1^2}.\frac{2.3}{2^2}.\frac{3.4}{3^2}.\frac{4.5}{4^2}...\frac{10.11}{10^2}.x=-20\)
\(\Leftrightarrow\frac{2}{1}.\frac{3}{2}.\frac{4}{3}.\frac{5}{4}...\frac{11}{10}.x=-20\)
\(\Leftrightarrow11.x=-20\)
\(\Leftrightarrow x=\frac{-20}{11}\)
bai 1
20:(24-(3^2.4-34)^2)-20
=20:(24-(9.4-34)^2)-20
=20:(24-2^2)-20
=20:20-20
=-19
bai 2
a
14+5x=4^6:4^3
14+5x=4^3
14+5x=64
5x=64-14
5x=50
x=50:5
x=10
b
189-2.(93-x)=59
2..(93-x)=189-59
2.(93-x)=130
(93-x)=130:2
93-x=65
x=93-65
x=28
1) \(20:\left[24-\left(3^2.4-34\right)^2\right]-20\)
\(=20:\left[24-\left(9.4-34\right)^2\right]-20\)
\(=20:\left[24-4\right]-20\)
\(=20:20-20\)
\(=1-20\)
\(=-19\)
2)a.\(14+5x=4^6:4^3\)
\(14+5x=64\)
\(5x=64-14\)
\(5x=50\)
\(\Rightarrow x=10\)
b) 189-2(93-x)=59
2(93-x) =189-59
2(93-x) =130
93-x =130:2
93-x =65
x =93-65
x =28
Học tốt nha!!!
\(\dfrac{2}{1^2}.\dfrac{6}{2^2}.\dfrac{12}{3^2}.\dfrac{20}{4^2}.....\dfrac{110}{10^2}.x=-20\)
\(\dfrac{1.2}{1^2}.\dfrac{2.3}{2^2}.\dfrac{3.4}{3^2}.\dfrac{4.5}{4^2}.....\dfrac{10.11}{10^2}.x=-20\)
\(\dfrac{1.2.2.3.3.4.4.5.5.....10.10.11}{1.1.2.2.3.3.4.4.5.5.....10.10}.x=-20\)
\(11.x=-20\)
\(x=-20:11=-\dfrac{20}{11}\)
\(\dfrac{2}{1^2}\cdot\dfrac{6}{2^2}\cdot\dfrac{12}{3^2}\cdot\dfrac{20}{4^2}\cdot...\cdot\dfrac{110}{10^2}\cdot x=-20\)
\(\Leftrightarrow\dfrac{1\cdot2}{1\cdot1}\cdot\dfrac{2\cdot3}{2\cdot2}\cdot\dfrac{3\cdot4}{3\cdot3}\cdot\dfrac{4\cdot5}{4\cdot4}\cdot...\cdot\dfrac{10\cdot11}{10\cdot10}\cdot x=-20\)
\(\Leftrightarrow\dfrac{1\cdot2\cdot2\cdot3\cdot3\cdot4\cdot4\cdot5\cdot...\cdot10\cdot11}{1\cdot1\cdot2\cdot2\cdot3\cdot3\cdot4\cdot4\cdot...\cdot10\cdot10}\cdot x=-20\)
\(\Rightarrow11\cdot x=-20\)
\(\Rightarrow x=\dfrac{-20}{11}\)
Vậy \(x=\dfrac{-20}{11}\).
Bài 1:
a) 6/2 x+ 1 = 2/7
6/2 x = 2/7 - 1
6/2 x = 2/7 - 7/7
6/2 x = -5/7
x = - 5/7 : 6/2
x = - 5/7 . 2/6
x = -5/21
Ủng hộ nha! :)
BÀI 1 a 6/2x+1=2/7
6/2x=2/7-1
6/2x=-5/7
6*7=5*2x
42=5*2x
42/5=2x
x=42/5:2
x=21/5
\(3^{20}+4^{20}=\left(3+4\right)^{20}=7^{20}\)
\(\Rightarrow7^{20}>5^{20}\)
Vậy \(3^{20}+4^{20}>5^{20}\)
x+4=203:20
x+4=202
x+4=400
x = 400-4
x = 396
x+4=20^3÷20
x+4=8.000÷20
x+4=400
x =400-4
x =396
Vậy x=396