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a) \(\frac{18}{45}-\frac{4}{12}-\frac{6}{9}-\frac{21}{35}=\frac{2}{5}-\frac{1}{3}-\frac{2}{3}-\frac{3}{5}\)
\(=\left(\frac{2}{5}-\frac{3}{5}\right)-\left(\frac{1}{3}+\frac{2}{3}\right)\)
\(=\frac{-1}{3}-1\)
\(=\frac{-4}{3}\)
b) \(\frac{4}{3}+\frac{3}{5}+\frac{7}{3}+\frac{2}{5}+\frac{1}{3}=\left(\frac{4}{3}+\frac{7}{3}+\frac{1}{3}\right)+\left(\frac{3}{5}+\frac{2}{5}\right)\)
\(=4+1=5\)
c) \(\frac{1}{3}.\frac{4}{5}.\frac{1}{3}.\frac{6}{5}=\frac{8}{75}\)
d) \(\frac{6}{7}.\frac{8}{13}+\frac{6}{7}.\frac{9}{13}-\frac{3}{13}.\frac{6}{7}\)
\(=\frac{6}{7}.\left(\frac{8}{13}+\frac{9}{13}-\frac{3}{13}\right)\)
\(=\frac{6}{7}.\frac{14}{13}\)
\(=\frac{12}{13}\)
Câu 13 :
\(\left(-\frac{1}{4}+\frac{5}{8}\right)+-\frac{3}{5}\)
\(=\frac{3}{8}-\frac{-3}{5}\)
\(=\frac{39}{40}\)
Câu 14 :
\(M=\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
\(=\frac{5}{9}.\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)\)
\(=\frac{5}{9}.1=\frac{5}{9}\)
Câu 15 :
\(E=\left(-\frac{3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
\(E=\left(-\frac{3}{4}+\frac{2}{5}+\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)
\(E=0\)
Câu 16 :
\(H=\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{8}\right)+\frac{7}{8}:\left(\frac{1}{36}-\frac{5}{12}\right)\)
\(=\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{8}+\frac{1}{36}-\frac{5}{12}\right)\)
\(=\frac{7}{8}:\frac{-7}{24}=-3\)
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a)-12+(x-9)=0
(x-9) = 12
x = 21
b) 13-(x-5)=8
(x-5) = -5
x = 0
c)134-5(x+4)=34
(x + 4 ) = 20
x = 16
d)4-(27-3)=x-(13-4)
-20 = x - 9
x = -11
a, => |x+4| = 3-(-7) = 10
=> x+4=10 hoặc x+4=-10
=> x=6 hoặc x=-14
b, => |x+5| = 13 - 13 = 0
=> x+5=0
=> x=0-5 = -5
c, => |x-10| + 12 = 4
=> |x-10| = 4-12 = -8
=> ko tồn tại x tm vì |x-10| > = 0
Tk mk nha
a) -7 + | x - 4 | = 3 b) 13 - | x + 5 | = 13 c) | x - 10 | - (-12) = 4
=> | x - 4 | = 3 - (-7) => | x + 5 | = 13 - 13 =>| x - 10 | + 12 = 4
=> | x - 4 | = 10 => | x + 5 | = 0 =>| x - 10 | = 4 -12
=> x - 4 = 10 hoặc - 10 => x + 5 = 0 =>|x - 10 | = - 8
=> x = 14 hoặc x = -6 => x = 0 - 5 => Với mọi |x - 10| luôn lớn hơn hoặc bằng 0
=> x = - 5 Nên : Không có x thỏa mãn
a)
x-3=15
x = 15+3=18
b)
x+7-13=13
x+7 =13-13=0
x = 0-7=-7
c)
x+3-16=-4
x+3 =-4+16=12
x = 12-3=9
d)
26-x-9=-13
-x-9= -13-26=-39
-x =-39+9=-30
x=30
1.
a) \(\frac{13}{8}:\frac{13}{4}=\frac{1}{2}=0,5=50\%\)
b) \(12,5:2,5=5=500\%\)
~ Hok tốt ~
2.
\(\left(\frac{37}{9}+\frac{13}{4}\right).\frac{9}{4}+\frac{11}{4}\)
\(=\frac{265}{36}.\frac{9}{4}+\frac{11}{4}\)
\(=\frac{265}{16}+\frac{11}{4}\)
\(=\frac{309}{16}\)
\(1+\left(\frac{9}{10}-\frac{4}{5}\right):\frac{19}{6}\)
\(=1+\frac{1}{10}:\frac{19}{6}\)
\(=1+\frac{3}{95}\)
\(=\frac{98}{95}\)
\(\left(-7+\left|13\right|\right)-\left(13-\left|-7\right|-25\right)-\left(25+\left|-10\right|-9\right)\)
\(=\left(-7+13\right)-\left(13-7-25\right)-\left(25+10-9\right)\)
\(=-7+13-13+7+25-25-10+9\)
\(=\left(-7+7\right)+\left(13-13\right)+\left(25-25\right)-10+9\)
\(=0+0+0-10+9\)
\(=-10+9\)
\(=-1\)
~ Hok tốt ~
\(\dfrac{-4}{3}-\dfrac{5}{7}+\dfrac{4}{3}=\left(\dfrac{4}{3}+\dfrac{-4}{3}\right)-\dfrac{5}{7}=0-\dfrac{5}{7}=-\dfrac{5}{7}\)
\(\dfrac{3}{13}\cdot\dfrac{6}{11}+\dfrac{3}{13}\cdot\dfrac{9}{11}-\dfrac{3}{13}\cdot\dfrac{4}{11}=\dfrac{3}{13}\cdot\left(\dfrac{6}{11}+\dfrac{9}{11}-\dfrac{4}{11}\right)=\dfrac{3}{13}\cdot1=\dfrac{3}{13}\)
x.3 - 13 = 4
⇒ x.3 = 4 + 13
⇒ x.3 = 17
⇒ x = 17 : 3
⇒ x = \(\dfrac{17}{3}\)