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\(A=\frac{5+55+555+5555}{9+99+999+9999}=\frac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}=\frac{5}{9}\)
Tớ làm luôn
A=\(\frac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}\)
A=\(\frac{5}{9}\)
a, \(\dfrac{3.5.7.11.13.37-10101.55}{1212120+40404}\)
\(=\dfrac{55\left(3.7.13.37-10101\right)}{1212120+40404}\)
\(=\dfrac{55.0}{1212120+40404}=0\)
b, \(\dfrac{5+55+555+5555}{9+99+999+9999}\)
\(=\dfrac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}=\dfrac{5}{9}\)
Chúc bạn học tốt!!!
a,\(\dfrac{3.5.7.11.13.37-10101.55}{1212120+40404}\)
\(=\dfrac{55\left(3.7.13.37-10101\right)}{1212120+40404}\)
\(=\dfrac{55.0}{1212120+40404}=0\)
\(\frac{5a}{15a}=\frac{5a\div a}{15a\div a}=\frac{5}{15}=\frac{5\div5}{15\div5}=\frac{1}{3}\)
199...999/999...995
=199...999/199...999 nhân 5
=1/5
Tck cho mik nhe
a ) 9 + 99 + 999 + ........ + 999...99 (có 10 chữ số 9)
= (10 - 1) + (100 - 1) + (1000 - 1) + ..... + (100...000 - 1)
= (10 + 100 + 1000 + .... + 100...00 ) - (1 + 1 + .... + 1)
= 1111....1110 - 10
= 1111....1100
Các ý khác tương tự nha !!!!!!!!!!!!!
\(\frac{5+55+555+5555}{9+99+999+9999}=\frac{5\cdot\left(1+11+111+1111\right)}{9\cdot\left(1+11+111+1111\right)}=\frac{5}{9}\)
\(\frac{5+55+555+5555}{9+99+999+9999}\)
= \(\frac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}\)
= \(\frac{5}{9}\)