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b,
b.a=30=1.30=2.15=3.10=5.6
=>(b,a)={(1,30),(2,15),(3,10),(5,6)}
c,
(x+1)(y+2)=10=1.10=2.5
TH1:x+1=1;y+2=10=>x=0,y=8
tuong tu=>(x,y)={(0,8),(1,3),(4,0)}
\(a,-7624+\left(1543+7624\right)-x=25\)
\(\Leftrightarrow-7624+9167-x=25\)
\(\Leftrightarrow1543-x=25\)
\(\Leftrightarrow x=1518\)
Vậy ................
\(b,\left(27-514\right)-\left(486-73\right)+x=7\)
\(\Leftrightarrow-487-413+x=7\)
\(\Leftrightarrow-900+x=7\)
\(\Leftrightarrow x=907\)
\(c,14-12+x=10-\left|-15\right|+\left|-3\right|\)
\(\Leftrightarrow2+x=10-15+3\)
\(\Leftrightarrow2+x=-2\)
\(\Leftrightarrow x=-4\)
Vậy ....
a) - 7624 + (1543 + 7624) - x = 25
-7624 + 9167 - x = 25
1543 - x = 25
x = 1543 - 25
x = 1518
b) (27 - 514) - (486 - 73) + x = 7
(-487) - 413 + x = 7
-900 + x = 7
x = 7 - (-900)
x = 907
c) 14 - 12 + x = 10 - |-15| + |-3|
14 - 12 + x = 10 - 15 + 3
14 - 12 + x = (-5) + 3
14 - 12 + x = -2
2 + x = -2
x = (-2) - 2
x = -4
\(\left(x-1\right)^3-2\left(x+1\right)^2=\left(2x+1\right)\left(1-3x\right)-2x\left(1-x\right)\)
\(\Leftrightarrow x^3-3x^2+3x-1-2x^2-4x-2=2x-6x^2+1-3x-2x+2x^2\)
\(\Leftrightarrow x^3-5x^2-x-3=-4x^2-3x+1\)
\(\Leftrightarrow x^3+x^2+2x-4=0\)
\(\Leftrightarrow x^3-x^2+2x^2-2x+4x-4=0\)
\(\Leftrightarrow\left(x-1\right)\left(x^2+2x+4\right)=0\)
=>x-1=0
hay x=1
Bài 1 a, \(17.25\)
\(=\left(1+16\right).25\)
\(=1.25+16.25\)
\(=25+4.4.25\)
\(=25+4.100\)
\(=25+400\)
\(=425\)
b, Bạn kia làm rồi nhé!
c, \(29.31+66.69+31.37\)
\(=31.\left(29+37\right)+66.99\)
\(=31.66+66.69\)
\(=66\left(31+69\right)\)
\(=66.100\)
\(6600\)
\(\left(x-7\right)\left(x+2019\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-7=0\\x+2019=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=7\\x=-2019\end{cases}}\)
\(9-25=\left(7-x\right)-\left(25+7\right)\)
\(\Leftrightarrow-16=7-x-25-7\)
\(\Leftrightarrow-x=-16+25\)
\(\Leftrightarrow-x=9\)
\(\Leftrightarrow x=-9\)
\(2\left(4x-2x\right)-7x=15\)
\(\Leftrightarrow4x-7x=15\)
\(\Leftrightarrow x=-5\)
a ) 9 - 25 = ( 7 - x ) - ( 25 + 7 )
9 - 25 = 7 - x - 25 - 7
9 - 25 - 7 + 25 + 7 = -x
9 = - x
=> x = -9
Vậy x = -9
b) 2 . ( 4x - 2x ) - 7x = 15
8x - 4x - 7x = 15
-3x = 15
x = 15 : ( - 3 )
x = -5
Vậy x = -5
c ) ( x - 7 ). ( x + 2019 ) = 0
=> x - 7 = 0 hoặc x + 2019 = 0
=> x = 7 hoặc x = - 2019
vậy x \(\in\){ 7 ; -2019 }
B1:
\(n^2+2n-7⋮n+2\)
\(\Leftrightarrow n\left(n+2\right)-7⋮n+2\)
Vì \(n\left(n+2\right)⋮n+2\Rightarrow-7⋮n+2\)
\(\Rightarrow n+2\inƯ\left(-7\right)=\left\{-1;1;-7;7\right\}\)
Ta có bảng sau:
| \(n+2\) | \(-1\) | \(1\) | \(-7\) | \(7\) |
| \(n\) | \(-3\) | \(-1\) | \(-9\) | \(5\) |
Vậy để \(n^2+2n-7⋮n+2\) thì \(n\in\left\{-9;-3;-1;5\right\}\)
Mình giúp câu 2 thôi nhé :
95 - 2.( x + 7 ) = 23
2.( x + 7 ) = 95 - 23
2.( x + 7 ) = 72
x + 7 = 72 : 2
x + 7 = 36
x = 36 - 7
x = 29
Vậy x = 29
Chúc bạn học tốt !
1. Tính nhanh
29.31+ 66.69+31.37
= (29.31 + 31. 37) + 66.69
= 31.(29+37) + 66.69
= 31.66 + 66.69
= 66.(31+69)
= 66.100
= 6600
2. Tìm x
95 - 2.(x+7) = 23
=> 95 - 23 = 2.(x+7)
=> 72 = 2.(x+7)
=> (x+7) = 72 : 2
=> x+7 = 36
=> x = 36 - 7
=> x = 29