Question

[Nguyễn Hải Băng]

Tính:

1/3 - 3/4 - ( -3/5 ) + 1/72 - 2/9 - 1/36 + 1/15

Answer 1

[soyeon_Tiểubàng giải]

\(\frac{1}{3}-\frac{3}{4}-\left(-\frac{3}{5}\right)+\frac{1}{72}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)

\(=\frac{1}{3}-\frac{3}{4}+\frac{3}{5}+\frac{1}{72}-\frac{2}{9}-\frac{1}{36}+\frac{1}{15}\)

\(=\left(\frac{1}{3}-\frac{2}{9}\right)+\left(-\frac{3}{4}-\frac{1}{36}\right)+\left(\frac{3}{5}+\frac{1}{15}\right)+\frac{1}{72}\)

\(=\left(\frac{3}{9}-\frac{2}{9}\right)+\left(-\frac{27}{36}-\frac{1}{36}\right)+\left(\frac{9}{15}+\frac{1}{15}\right)+\frac{1}{72}\)

\(=\frac{1}{9}+\frac{-7}{9}+\frac{2}{3}+\frac{1}{72}\)

\(=-\frac{2}{3}+\frac{2}{3}+\frac{1}{72}\)

\(=0+\frac{1}{72}=\frac{1}{72}\)