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AH
Akai Haruma
Giáo viên
19 tháng 10 2022

Lời giải:

\(=\frac{2.(2.3)^9-2^5(2.3^2)^4}{2^2(2.3)^8}=\frac{2^{10}.3^9-2^9.3^8}{2^{10}.3^8}=\frac{2^9.3^8(2.3-1)}{2^{10}.3^8}\)

\(=\frac{5}{2}\)

28 tháng 10 2017

\(\dfrac{2\cdot6^9-2^5\cdot18^4}{2^2\cdot6^8}\\ =\dfrac{2\cdot\left(2\cdot3\right)^9-2^5\cdot\left(2\cdot3^2\right)^4}{2^2\cdot\left(2\cdot3\right)^8}\\ =\dfrac{2\cdot2^9\cdot3^9-2^5\cdot2^4\cdot3^8}{2^2\cdot2^8\cdot3^8}\\ =\dfrac{2^9\cdot3^8\left(2\cdot3-1\right)}{2^{10}\cdot3^8}\\ =\dfrac{5}{2}\)

28 tháng 10 2017

\(\dfrac{2.6^9-2^5.18^4}{2^2.6^8}=\dfrac{2.\left(2.3\right)^9-2^5.\left(2.3^2\right)^4}{2^2.\left(2.3\right)^8}=\dfrac{2.2^9.3^9-2^5.2^4.3^8}{2^2.2^8.3^8}=\dfrac{2^9.3^8\left(2.3-1\right)}{2^{10}.3^8}=\dfrac{5}{2}\)

11 tháng 12 2017

Ta có:\(\dfrac{2.6^9-2^5.18^4}{2^2.6^8}=\dfrac{2^{10}.3^9-2^9.3^8}{2^{10}.3^8}=\dfrac{2^9.3^8.\left(2.3-1\right)}{2^{10}.3^8}=\dfrac{2^9.3^8.5}{2^{10}.3^8}=\dfrac{5}{2}\)

27 tháng 11 2016

\(\frac{2.6^9-2^5.18^4}{2^6.6^8}=\frac{2^{10}.3^9-2^9.3^8}{2^{14}.3^8}=\frac{2^9.3^8.\left(6-1\right)}{2^{14}.3^8}=\frac{5}{2^5}=\frac{5}{32}\)

27 tháng 11 2016

= 2.29.39-25.24.34.34/ 26.38.28

=210.39-29.38/ 214.38

=29.38.(2.3-1.1)/214.38

=5/32

19 tháng 12 2017

\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

\(=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}\)

\(=\frac{-2}{6}\)

\(=\frac{-1}{3}\)

\(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}=\dfrac{2^{10}\cdot3^8-2\cdot2^9\cdot3^9}{2^{10}\cdot3^8+3^8\cdot2^8\cdot2^2\cdot5}\)

\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}=\dfrac{2^{10}\cdot3^8\cdot\left(1-3\right)}{2^{10}\cdot3^8\cdot6}\)

\(=\dfrac{-2}{6}=\dfrac{-1}{3}\)

11 tháng 8 2017

\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)

\(=\dfrac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)

\(=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

\(A=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^8.3^{10}.5}\)

Tách ra tiếp mk đang buồn ngủ

11 tháng 8 2017

\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

\(=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=\dfrac{-2}{6}=\dfrac{-1}{3}\)