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9,45-2,37+1,37
=9,45-(2,31-1,37)
=9,45-1
=8,45
\(\frac{2x-4,36}{0,125}=0,25.42,9-11,7.0,25+0,25.0,8\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.\left(42,9-11.7+0,8\right)\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.32\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=8\)
\(\Leftrightarrow2x-4,36=1\)
\(\Leftrightarrow2x=5,36\)
\(\Leftrightarrow x=2,68\)
b) \(N=\frac{1}{1.5}+\frac{1}{5.10}+\frac{1}{10.15}+\frac{1}{15.20}+...+\frac{1}{2005.2010}\)
\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\right)\)
\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{2010}\right)\)
\(\Leftrightarrow N=\frac{1}{5}.\frac{2009}{2010}=\frac{2009}{10050}\)
Bài 1:
a)\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot42,9-11,7\cdot0,25+0,25\cdot0,8\)
\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot\left(42,9-11,7+0,8\right)\)
\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot32\)
\(\frac{2\cdot x-4,36}{0,125}=8\)
\(2\cdot x-4,36=8\cdot0,125\)
\(2\cdot x-4,36=1\)
\(2\cdot x=1+4,36\)
\(2\cdot x=5,36\)
\(x=\frac{5,36}{2}=2,68\)
b) \(N=\frac{1}{1\cdot5}+\frac{1}{5\cdot10}+\frac{1}{10\cdot15}+\frac{1}{15\cdot20}+...+\frac{1}{2005\cdot2010}\)
\(4N=\frac{4}{1\cdot5}+\frac{4}{5\cdot10}+\frac{4}{10\cdot15}+\frac{4}{15\cdot20}+...+\frac{4}{2005\cdot2010}\)
\(4N=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\)
\(4N=1-\frac{1}{2010}=\frac{2009}{2010}\)
\(N=\frac{2009}{2010}\div4=\frac{2009}{8040}\)
Bài 2:
a) ( x + 5,2 ) : 3,2 = 4,7 ( dư 0,5 )
\(x+5,2=4,7\cdot3,2+0,5\)
\(x+5,2=15,54\)
\(x=15,54-5,2=10,34\)
b)\(A=\frac{4047991-2010\cdot2009}{4050000-2011\cdot2009}\)
\(A=\frac{4047991-2010\cdot2009}{4050000-2009-2010\cdot2009}\)
\(A=\frac{4047991-2010\cdot2009}{4047991-2010\cdot2009}=1\)
Bài 3:
a) \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)
\(x\cdot\left(104,5-14,1+9,6\right)=25\)
\(x\cdot100=25\)
\(x=\frac{25}{100}=\frac{1}{4}=0,25\)
b) \(T=\frac{2009\cdot2010+2000}{2011\cdot2010-2020}\)
\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+4020-2020}\)
\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+2000}=1\)
(41,65+8,35+8,25+21,75)x(10,55+9,45)
=(50+50)x20
=100x20
=2000
41,65+8,25+8,35+9,45+21,75+10,55
= ( 41,65 + 8,35 ) + ( 8,25 + 21,75 ) + ( 9,45 + 10,55 )
= 50 + 30 + 20
= 50 + 50
= 100
41,65+8,25+8,35+9,45+21,75+10,55=
= (41,65+8,35)+(8,25+21,75)+(9,45+10,55)
= 50 + 30 + 20
= 100.
4x5,6x2,5=(4x2,5)x5,6=1x5,6=5,6
2,37x7,2+5x7,2+7,2x2,63=7,2x(2,37+5+2,63)=7,2x10=72
a , 4 x 5,6 x 2,5 = (4 x 2,5) x 5,6 =10 x 5,6 =56
b, 2,37 x 7,2 + 5 x 7,2 + 2,63 = 7,2 x ( 2,37 + 2,63 + 5 ) = 7,2 x 10 = 72
a, A=333(999+3):2=166833\
b, B=3737x83-8383x37+2015
=37x101x83-8383x37+2015
=8383x37-8383x37+2015
=0+2015
=2015
B1 :
Số hạng tử của A là
(999 - 3 ):3 + 1 = 333 (hạng tử)
A = 3 + 6 + 9 ... + 999
A = (3 +999) + (6 + 996) + ...
A = 1002 +1002 +.. + 1002
A = 1002 . 333 :2 = 166833
b/ B = 37 x101 x 8 3 + 83x 1 01x37 + 2015 = 2015
Bài 1 : Tính :
a)\(\frac{6}{5}\)x 4,7 - 3,2
= 5,64 - 3,2
= 2,44
b) 17,6 x 6,7 + 3,2
= 117,92 + 3,2
= 121,12
Bài 2 :
a) 0,8 x 2,5 x 1,25
= ( 0,8 x 1,25 ) x 2,5
= 1 x 2,5
= 2,5
b) 4 x 5,6 x 2,5
= ( 4 x 2,5 ) x 5,6
= 10 x 5,6
= 56
c) 4,65 x 5,6 + 5,6 + 5,6 x 4,35
= 4,65 x 5,6 + 5,6 x 1 + 5,6 x 4,35
= 5,6 x ( 4,65 + 1 + 4,35 )
= 5,6 x 10
= 56
1.
\(\frac{6}{5}\)x \(4,7-3,2\)\(=5,64-3,2=2,44\)
\(17,6\)x \(6,7+3,2\)\(=117,92+3,2=121,12\)
2.
\(0,8\)x \(2,5\)x \(1,25\)\(=\)\(1,25\)x \(0,8\)x \(2,5\)\(=\)\(1\)x \(2,5\)\(=2,5\)
\(4\)x \(5,6\)x \(2,5\)\(=\)\(4\)x \(2,5\)x \(5,6\)\(=\)\(10\)x \(5,6\)\(=\)\(56\)
\(4,65\)x \(5,6\)+ \(5,6\)+ \(5,6\)x \(4,35\)= \(5,6\)x \(\left(4,65+1+4,35\right)\)= \(5,6\)x \(10\)= \(56\)
Nếu đúng thì cho mình 1 k mình nhé :)
Chúc bạn học tốt :)
9,45 - 2,37 + 1,37 = 8,45
2,3 : 3,2 x 0,8 = 0,575
Nếu đúng thì tk nha
a 9.45-2.37-1.37=9.45-1=8.45
b 2.3*0.8chia3.2*0.8=0.575
dung thi cho k