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1) A=19952-1994.1996
=19952-(1995-1)(1995+1)
=19952-(19952-1)
=1
2) B=98.28-(184-1)(184+1)
=(9.2)8-[(184)2-1]
= 188-188+1
=1
3) C=1632+74.163+372
=1632+2.37.163+372
=1632+2.163.37+372
=(163+37)2.2
=80000
\(A=163^2+74.163+37^2\)
\(=163^2+2.37.163+37^2\)
\(=\left(163+37\right)^2=200^2\)
\(B=147^2-94.147+47^2\)
\(=147^2-2.47.147+47^2\)
\(=\left(147-47\right)^2=100^2\)
Vậy A > B
\(E=163^2+74\times163+37^2=163^2+2\times163\times37+37^2=\left(163+37\right)^2=200^2\)
\(F=147^2-94\times147+47^2=147^2-2\times147\times47+47^2=\left(147-47\right)^2=100^2\)
\(\frac{E}{F}=\frac{200^2}{100^2}=\left(\frac{200}{100}\right)^2=2^2=4\)
\(E=4F\)
132^2 - 112^2 = (132 - 112) (132 + 112) = 20 . 244 = 4880
39 . 41 = (40 - 1) (40 + 1) = 402 - 1 = 1599
402 - 392 + 382 - 372 + ... + 22 - 1 = (402 - 392) + (382 - 372) + ... + (22 - 1)
= (40 - 39) (40 + 39) + (38 - 37) (38 + 37) + ... + (2 - 1) (2 + 1)
= 40 + 39 + 38 + 37 + 36 + ... + 2 + 1
= \(\frac{\left(40-1+1\right)\left(40+1\right)}{2}=\frac{40.41}{2}=820\)
a: \(=1995^2-\left(1995^2-1\right)=1995^2-1995^2+1=1\)
b: \(=18^8-18^8+1=1\)
c: \(=\left(163+37\right)^2=200^2=40000\)
a) 732 - 272
= (73 - 27)(73 + 27)
= 46 . 100
= 4600
b) 372 - 132
= (37 - 13)(37 + 13)
= 24 . 50
= 1200
c) 20022 - 22
= (2002 - 2)(2002 + 2)
= 2000 . 2004
= 4008000
a ) 732 - 272 = 432
b ) 372 - 132 = 242
c ) 20022 - 22 = 19982
\(=\left(163+37\right)^2\) \(=200^2\) \(=40000\)
1632 + 74 . 163 + 372 = ( 163 + 37 ) . ( 163 + 37 ) = 200 . 200 = 40000