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PQ
0
H
1
NN
1 tháng 10 2020
\(\left(5^7+5^9\right)\left(6^8+6^{10}\right)\left(2^4-4^2\right)=\left(5^7+5^9\right)\left(6^8+6^{10}\right)\left(16-16\right)=0\)
\(\left(7^3+7^5\right)\left(5^4+5^6\right)\left(3^3.3-9^2\right)=\left(7^3+7^5\right)\left(5^4+5^6\right)\left[3^4-\left(3^2\right)^2\right]\)
\(=\left(7^3+7^5\right)\left(5^4+5^6\right)\left(3^4-3^4\right)=0\)
20 tháng 6 2017
a) $3^8:3^6=3^{8-6}=3^2$
$19^7:19^3=19^{7-3}=19^4$
$2^{10}:8^3=2^{10}:(2^3)^3=2^{10}:2^9=2^{10-9}=2^1$
$12^7:6^7=(12:6)^7=2^7$
$27^5:81^3=(3^3)^5:(3^4)^3=3^{15}:3^{12}=3^{15-12}=3^3$
b) $10^6:10=10^{6-1}=10^5$
$5^8:25^2=5^8:(5^2)^2=5^8:5^4=5^{8-4}=5^4$
$4^9:64^2=4^9:(4^3)^2=4^9:4^6=4^{9-6}=4^3$
$2^25:32^4=2^{25}:(2^5)^4=2^{25}:2^{20}=2^{25-20}=2^5$
$18^3:9^3=(18:9)^3=2^3$
20 tháng 6 2017
\(\cdot3^8:3^6=3^{8-6}=3^2\)
\(\cdot19^7:19^3=19^{7-3}=19^4\)
\(\cdot2^{10}:8^3=2^{10}:\left(2^3\right)^3=2^{10}:2^9=2\)
\(\cdot12^7:6^7=\left(12:6\right)^7=2^7\)
\(\cdot27^5:81^3=\left(3^3\right)^5:\left(3^4\right)^3=3^{15}:3^{12}=3^3\)
\(\cdot10^6:10=10^{6-1}=10^5\)
\(\cdot5^8:25^2=5^8:\left(5^2\right)^2=5^8:5^4=5^4\)
\(\cdot4^9:64^2=4^9:\left(4^3\right)^2=4^9:4^6=4^3\)
\(2^{25}:32^4=2^{25}:\left(2^5\right)^4=2^{25}:2^{20}=2^5\)
\(18^3:9^3=\left(18:9\right)^3=2^3\)
DN
0
\(A=\left(2^6+3^7\right)\left(4^8+5^9\right)\left(9^4-3^8\right)\left(10^6-7^5\right)\)
\(A=\left(2^6+3^7\right)\left(4^8+5^9\right)\left(10^6-7^5\right)\left[\left(3^2\right)^4-3^8\right]\)
\(A=\left(2^6+3^7\right)\left(4^8+5^9\right)\left(10^6-5^7\right)\left(3^8-3^8\right)\)
\(A=\left(2^6+3^7\right)\left(4^8+5^9\right)\left(10^6-5^7\right).0\)
\(A=0\)