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B = 64 . 16 + 81 . 84 + 17 . 16
B = (64 + 17) . 16 + 81 . 84
B = 81 . 16 + 81 . 84
B = 81 . (16 + 84)
B = 81 . 100
B = 8100
B = ( 64 . 16 + 17 . 16 ) + 81 . 84
= 16 . ( 64 + 17 ) + 81 . 84
= 16 . 81 + 81 . 84
= 81 . ( 16 + 64 )
= 81 . 100
= 8100
a) 23.56 + 56.77 = (23 + 77).56 = 100.56 = 5600.
b) 32.19 + 32 = 32.(19 +1) = 32.20 = 640.
c) 35.34 + 35.86 + 65.75 + 65.45 = 35.(34 + 86) + 65.(75 + 45)
= 120.35+120.65 -120.(35 + 65) = 12000.
d) 43.17 + 29.57 +13.43 + 57 = 43.(17 +13) + 57.(29 +1)
= 43.30 + 57.30 = 30. (43+57) = 3000.
e) 3.25.8 + 4.37.6 + 2.3812 - 24.25 + 24.37 + 24.38
= 24.(25 + 37 + 38) = 2400.
f) 64.16 + 81.84+17.16 = 16.(64+17)+81.84 = 16.81+81.84
= 81.(16 + 84) = 8100
a) 23.56 + 56.77 = (23 + 77).56 = 100.56 = 5600.
b) 32.19 + 32 = 32.(19 +1) = 32.20 = 640.
c) 35.34 + 35.86 + 65.75 + 65.45 = 35.(34 + 86) + 65.(75 + 45)
= 120.35+120.65 -120.(35 + 65) = 12000.
d) 43.17 + 29.57 +13.43 + 57 = 43.(17 +13) + 57.(29 +1)
= 43.30 + 57.30 = 30. (43+57) = 3000.
e) 3.25.8 + 4.37.6 + 2.3812 - 24.25 + 24.37 + 24.38
= 24.(25 + 37 + 38) = 2400.
f) 64.16 + 81.84+17.16 = 16.(64+17)+81.84 = 16.81+81.84
= 81.(16 + 84) = 8100
Chuyển dấu " - " của 84 sang số 17
=> -17 . 84 - 17 . 16
= -17 . ( 84 + 16 )
= -17 . 100
= -1700
17 . ( - 84 ) - 17 . 16
= 17 . [( - 84 ) - 16 ]
= 17 . ( - 100 )
= - 1700
a, 37.12=37.3.4=111.4=444
b, 15873.21= 15873. 7. 3= 111111. 3= 333333
a, Ta có: 37 . 3 = 111
mà \(12=3.4\)
\(\Rightarrow37.12=37.3.4=111.4=444\)
b, Ta có: 15873.7 = 111111
mà \(21=7.3\)
\(\Rightarrow15873.21=15873.7.3=111111.3=333333\)
2x . 26 . 24 = 23 . 260
2x + 6 + 4 = 23 + 60
2x + 10 = 263
=> x + 10 = 63
x = 63 - 10
x = 53
a/ 5x.52.53=52.540
5x.55=542
5x=537
x=37
b/ 2x.26.24=23.260
2x.210=263
2x=253
x=53
Ta có :
\(A=\frac{3}{1.3}+\frac{3}{3.5}+\frac{3}{5.7}+...+\frac{3}{49.51}\)
\(A=\frac{3}{2}\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{49.51}\right)\)
\(A=\frac{3}{2}\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{49}-\frac{1}{51}\right)\)
\(A=\frac{3}{2}\left(1-\frac{1}{51}\right)\)
\(A=\frac{3}{2}.\frac{50}{51}\)
\(A=\frac{25}{17}\)
Vậy \(A=\frac{25}{17}\)
Chúc bạn học tốt ~
\(A=\frac{3}{1.3}+\frac{3}{3.5}+\frac{3}{5.7}+...+\frac{3}{49.51}\)
\(A=\frac{3}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{49}-\frac{1}{51}\right)\)
\(A=\frac{3}{2}\left(1-\frac{1}{51}\right)\)
\(A=\frac{3}{2}.\frac{50}{51}\)
\(A=\frac{25}{17}\)
\(B=\frac{21}{4}\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}\right)\)
\(B=\frac{21}{4}\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}\right)\)
\(B=\frac{21}{4}\left(\frac{33}{3.4}+\frac{33}{4.5}+\frac{33}{5.6}+\frac{33}{6.7}\right)\)
\(B=\frac{21}{4}.33.\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\right)\)
\(B=\frac{21}{4}.33.\left(\frac{1}{3}-\frac{1}{7}\right)\)
\(B=\frac{21}{4}.33.\frac{4}{21}\)
\(B=\left(\frac{21}{4}.\frac{4}{21}\right).33\)
\(B=33\)
\(C=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{97.99}\)
\(C=\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\right)\)
\(C=\frac{1}{2}\left(1-\frac{1}{99}\right)\)
\(C=\frac{1}{2}.\frac{98}{99}\)
\(C=\frac{49}{99}\)
Số các số hạng là :
( 100 - 2 ) : 2 + 1 = 50 ( số )
Tổng các số trên là :
50 x ( 100 + 2 ) : 2 = 2550
Đáp số : 2550
Mình nhanh nhất
So cac so hang la: (100-2):2+1=50 (so)
*(so lon nhat - so be nhat) : khoang cach +1 hay (so cuoi - so dau): khoang cach + 1
Tong cua day la: (100+2)x50:2=2550
*(so cuoi + so dau) x so so hang : 2
64.16 + 81.84+17.16 = 16.(64+17)+81.84 = 16.81+81.84
= 81.(16 + 84) = 8100.