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Trả lời
234 x 7 - ( 1347 - 579 )
= 234 x 7 - 768
= 1638 - 768
= 730
\(A=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\)
\(\Rightarrow A=\frac{1}{2}-\frac{1}{8}\)
\(\Rightarrow A=\frac{3}{8}\)
\(A=\left(\frac{1}{2}-\frac{1}{3}\right)+\left(\frac{1}{3}-\frac{1}{4}\right)+...+\left(\frac{1}{7}-\frac{1}{8}\right)\)
\(A=\frac{1}{2}-\frac{1}{8}\)
\(A=\frac{3}{8}\)
hhgggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg
\(\left(24\%+\dfrac{3}{4}+0,76+25\%\right)\times\left(\dfrac{3}{\dfrac{5}{7}}+\dfrac{1}{\dfrac{8}{28}}\right)\)
\(=\left(0,24 +0,75+0,76+0,25\right)\times\left(4,2+10,5\right)\)
\(=\left[\left(0,24+0,76\right)+\left(0,75+0,25\right)\right]\times\left(4,2+10,5\right)\)
\(=\left[1+1\right]\times\left(4,2+10,5\right)\)
\(=2\times14,7=29,4\)
\(~HT~,#Ng\)
99-97+95-93+91-89+...+7-5+3-1
Số các số hạng là:
(99-1):2+1=50 số
=(99-97)+(95-93)+(91-89)+...+(7-5)+(3-1)
Số cặp sẽ là:
50:2=25 cặp
=2+2+2+...+2+2
=2x25
=50
32x47+32-53+168+79+132
=1504+32-53+(168+79+132)
=1536-53+379
=1483+379
=1862
25/2+25/3-25/7/1/3+1/3-1/7
\(=\frac{25}{2}+\frac{25}{3}-\frac{25}{7}:\frac{1}{3}+\frac{1}{3}-\frac{1}{7}\)
\(=\frac{25}{2}+\frac{25}{3}-\frac{25}{7}\times\frac{3}{1}+\frac{1}{3}-\frac{1}{7}\)
\(=\frac{25}{2}+\frac{25}{3}-\frac{156}{7}+\frac{1}{3}-\frac{1}{7}\)
\(=\frac{525}{42}+\frac{350}{42}-\frac{936}{42}+\frac{14}{42}-\frac{6}{42}\)
\(=\frac{875}{42}-\frac{936}{42}+\frac{14}{42}-\frac{6}{42}\)
\(=\frac{-61}{42}+\frac{14}{42}-\frac{6}{42}\)
\(=\frac{-47}{42}-\frac{6}{42}\)
\(=\frac{-53}{42}\)
( Chú Ý: lớp 5 chưa học số âm )
=[(1009-1):2+1] x (1009+1):2 x [579-579]
=505 x 505 x 0
=505 x 0
=0
chúc bạn học tốt nha
ủng hộ mk nha
[1+3+3+5+7+....+1009] x [579-579]
[1+3+3+5+7+...+1009] x 0=0