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- A=80-2=78
- B=17(85+15)-120=17x100-120=170-120=50
- C= 45(74+26)=45•100=4500
- D=5x10-62=50-36=14
c) \(C=1.2+2.3+3.4+...+98.99\)
\(\Rightarrow3C=1.2\left(3-0\right)+2.3\left(4-1\right)+3.4\left(5-2\right)+...+98.99\left(100-97\right)\)
\(=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+....+98.99.100-97.98.99\)
\(=98.99.100\)
\(\Rightarrow C=\frac{98.99.100}{3}=323400\)
d) \(D=\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{99.101}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{99}-\frac{1}{101}\)
\(=1-\frac{1}{101}=\frac{100}{101}\)
b: \(7\cdot2^{13}< 8\cdot2^{13}=2^{16}\)
d: \(3^{99}=\left(3^{33}\right)^3\)
\(11^{21}=\left(11^7\right)^3\)
mà \(3^{33}>11^7\)
nên \(3^{99}>11^{21}\)
`Answer:`
\(A=\frac{-5x}{21}+\frac{-5y}{21}+\frac{-5z}{21}\)
\(=\frac{-5x-5y-5z}{21}\)
\(=\frac{-5\left(x+y\right)-5z}{21}\)
\(=\frac{-5\left(-z\right)-5z}{21}\)
\(=\frac{5z-5z}{21}\)
\(=\frac{0}{21}\)
\(=0\)
a) = (3.23)3.3-(2.3)4.25
= 33.(23)3.3-24.34.25
= 34.29-29.34
=0
a) 2 370 - 179 + 21 = 2 191 + 21 = 2 212
b) 100 : 5 . 4 = 20 . 4 = 8
c) 396 : 18 : 2 = 22 : 2 = 11
a) 2 370 - 179 + 21 = 2 191 + 21 = 2 212
b) 100 : 5 . 4 = 20 . 4 = 80
c) 396 : 18 : 2 = 22 : 2 = 11