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\(\frac{9}{2}:\left(2.5-\frac{15}{4}\right)+\left(\frac{-1}{2}\right)^2\)
\(=\frac{9}{2}:\left(10-\frac{15}{4}\right)+\frac{1}{4}\)
\(=\frac{9}{2}:\left(\frac{40}{4}-\frac{15}{4}\right)+\frac{1}{4}\)
\(=\frac{9}{2}:\frac{25}{4}+\frac{1}{4}\)
\(=\frac{9}{2}.\frac{4}{25}+\frac{1}{4}\)
\(=\frac{18}{25}+\frac{1}{4}\)
\(=\frac{97}{100}\)
\(\frac{9}{2}\div\left(2\times5-\frac{15}{4}\right)+\left(\frac{-1}{2}\right)^2\)
\(=\frac{9}{2}\div\left(10-\frac{15}{4}\right)+\left(\frac{-1}{2}\right)^2\)
\(=\frac{9}{2}\div\left(\frac{40-15}{4}\right)+\frac{1}{4}\)
\(=\frac{9}{2}\div\frac{25}{4}+\frac{1}{4}\)
\(=\frac{9}{2}\times\frac{4}{25}+\frac{1}{4}\)
\(=\frac{18}{25}+\frac{1}{4}\)
\(=\frac{72+25}{100}=\frac{97}{100}\)
Số số hạng cua dãy là:
(200-1):1+1=200(số hạng)
Giá trị của dãy số là:
(200*201):2=20100
1 + 2 + 3 + 4 + ... + 200 = ( 200 + 1 ) . 200 : 2 = 201 . 200 : 2 = 20100
a) \(=\dfrac{157}{8}.\dfrac{12}{7}-\dfrac{61}{4}.\dfrac{12}{7}=\dfrac{12}{7}\left(\dfrac{157}{8}-\dfrac{61}{4}\right)=\dfrac{12}{7}.\dfrac{35}{8}=\dfrac{15}{2}\)
b) \(\dfrac{2}{5}.\dfrac{1}{3}-\dfrac{2}{15}\div\dfrac{1}{5}+\dfrac{3}{5}.\dfrac{1}{3}=\dfrac{1}{3}\left(\dfrac{2}{5}+\dfrac{3}{5}\right)-\dfrac{2}{15}.5=\dfrac{1}{3}.1-\dfrac{2}{3}=\dfrac{1}{3}-\dfrac{2}{3}=-\dfrac{1}{3}\)
c) \(=-\dfrac{80}{9}\)
\(A=\frac{-7}{21}+\left(1+\frac{1}{3}\right)\)
\(A=\frac{-7}{21}+1+\frac{1}{3}\)
\(A=\left(\frac{-7}{21}+\frac{1}{3}\right)+1\)
\(A=0+1\\ A=1\)
\(B=\frac{2}{15}+\left(\frac{5}{9}+-\frac{6}{9}\right)\)
\(B=\frac{2}{15}+\frac{-1}{9}\)
\(B=\frac{1}{45}\)
\(C=\left(\frac{-1}{5}+\frac{3}{12}\right)+\frac{-3}{4}\)
\(C=\frac{-1}{5}+\left(\frac{3}{12}+\frac{-3}{4}\right)\)
\(C=\frac{-1}{5}+\frac{-1}{2}\)
\(C=\frac{-7}{10}\)
\(A=\frac{-7}{21}+\left(1+\frac{1}{3}\right)\)
\(A=\frac{-1}{3}+1+\frac{1}{3}\)
\(A=1\)
\(B=\frac{2}{15}+\left(\frac{5}{9}+\frac{-6}{9}\right)\)
\(B=\frac{2}{15}+\frac{5}{9}+\frac{-6}{9}\)
\(B=\frac{2}{15}+\frac{5}{9}+\frac{-10}{15}\)
\(B=\frac{-8}{15}+\frac{5}{9}\)
\(B=\frac{1}{45}\)
\(C=\left(\frac{-1}{5}+\frac{3}{12}\right)+\frac{-3}{4}\)
\(C=\frac{-1}{5}+\frac{3}{4}+\frac{-3}{4}\)
\(C=\frac{-1}{5}\)
A =\(\frac{2}{7}\times\frac{7}{15}-\frac{2}{3}\times\frac{5}{27}\) =\(\frac{14}{105}-\frac{10}{81}\)=\(\frac{2}{15}-\frac{10}{81}\)=\(\frac{162}{1215}-\frac{150}{1215}\)=\(\frac{12}{1215}\)
\(\frac{-4}{9}\times\frac{7}{15}+\frac{4}{9}\times\frac{5}{27}\)=\(\frac{-28}{135}+\frac{20}{243}\)=\(\frac{-6804}{32805}+\frac{2700}{32805}\)=\(\frac{-4104}{32805}\)=\(\frac{-152}{1215}\)
A=\(\frac{2}{7}\times\frac{7}{15}-\frac{2}{3}\times\frac{5}{27}\)chia cho\(\frac{-4}{9}\times\frac{7}{15}+\frac{4}{9}\times\frac{5}{27}\)
= \(\frac{12}{1215}:\frac{-152}{1215}\)
=\(\frac{12}{1215}\times\frac{1215}{-152}\)
=\(\frac{14580}{-184680}\)
\(\frac{14580}{-184680}\)rút gọn bằng\(\frac{-3}{38}\)
1,
\(\begin{array}{l}2,5.\left( {4,1 - 3 - 2,5 + 2.7,2} \right) + 4,2:2\\ = 2,5.\left( {4,1 - 3 - 2,5 + 14,4} \right) + 4,2:2\\ = 2,5.\left( {1,1 - 2,5 + 14,4} \right) + 2,1\\ = 2,5.\left( { - 1,4 + 14,4} \right) + 2,1\\ = 2,5.13 + 2,1\\ = 32,5 + 2,1\\ = 34,6\end{array}\)
2,
Cách 1:
\(\begin{array}{l}2,86.4 + 3,14.4 - 6,01.5 + {3^2}\\ = 11,44 + 12,56 - 30,05 + 9\\ = \left( {11,44 + 12,56} \right) + \left( { - 30,05 + 9} \right)\\ = 24 + \left( { - 21,05} \right)\\ = 24 - 21,05\\ = 2,95\end{array}\)
Cách 2:
\(\begin{array}{l}2,86.4 + 3,14.4 - 6,01.5 + {3^2}\\ = 4.(2,86+3,14) - 30,05 + 9\\ = 4.6 + \left( { - 30,05 + 9} \right)\\ = 24 + \left( { - 21,05} \right)\\ = 24 - 21,05\\ = 2,95\end{array}\)
\(\frac{7}{2}\div\left(2,5-\frac{15}{4}\right)+\left(\frac{-1}{2}\right)^2\)
\(=\frac{7}{2}\div\left(\frac{5}{2}-\frac{15}{4}\right)+\frac{1}{4}\)
\(=\frac{7}{2}\div\left(\frac{10}{4}-\frac{15}{4}\right)+\frac{1}{4}\)
\(=\frac{7}{2}\div\frac{-5}{4}+\frac{1}{4}\)
\(=\frac{-14}{5}+\frac{1}{4}\)
\(=-\frac{56}{20}+\frac{5}{20}\)
\(=-\frac{51}{20}\)
~Study well~
#Zu